but also the number of moles of particles. ________true__________ 5. The mass of each reactant and product is related to its coefficient in the balanced chemical equation for the reaction by its molar mass. Complete the table below‚ using information represented in the chemical equation for the combustion of methanol‚ an alcohol. methanol oxygen → carbon dioxide water 2CH3OH(l) 3O2 (g) → 2CO2(g) 4H2O(g) Substance Molar Mass (g/mol) Number of Molecules Number of Moles (mol) Mass (g) 6.
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Molar mass Na2CO3= 105.99g/mol Mass of Na2CO3= 0.2123g Moles of Na2CO3= 0.2123g/105.99g/mol Moles of Na2CO3= 2.003 x 10-3 moles Mole-to-Mole Ratio 1 Na2CO3: 2 HCl Moles of HCl= 2 x 2.003 x 10-3moles Moles of HCl= 4.006 x 10-3 Molarity of HCl= (4.006 x 10-3)/0.04304 Molarity of HCl= 0.09308M Moles of HCl= 0.09308M x 0.03073L Moles of HCl= 2.8601 x 10-3 moles Moles of Na2CO3 = (2.860 x 10-3 moles) / 2 Moles of Na2CO3 = 1.4301 x 10-3 Mass of Na2CO3== 1.4301 x10-3
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Equation HX + NaOH NaX + H2O 1 mole 1 mole 1 mole 1 mole Aim To analyze the Vitamin C from a rival company and compare with that of my company and find out the best value for the money spent by the consumer. Controlled Variable * Mass of the tablet and hereby vitamin C in rival company tablets * Consistency of components in the Vitamin C tablet * Concentration of NaOH Apparatus 1. Burette (50ml) 2. Conical flask (50ml) 3. Vitamin C tablet (1 tablet
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In chemistry‚ this formula weight is a quantity computed from multiplying the atomic weight of units by each element in the chemical formula by the number of atoms which are present in the formula. Finding molar mass starts with units of grams per mole. The formula weight is simply the weight in atomic mass units of all the atoms in the given formula. There are many household products which contain this ingredient are typically in the category of home maintenance or personal care‚ that you may
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ratio Urea to C.Acid 97.7-125.5 C 98.9-118.8 Calculations Molar mass of urea (CO(NH2)2) = 60.05526 g/mol and 1g of urea was used so converting it to moles take 1g / 60.05526g/mol = 0.0166513 moles of urea. Molar mass of cinnimic acid (C9H8O2) is 148.16g/mol and 1g was used so converting it to moles take 1g/ 148.16g/mol = 0.00674946 moles of cinnimic acid. Procedure A. Calibrate Thermometer a. Use Table 3.2 of known melting point temperatures for a series of standard substances. b. Note
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corrodes and rust is a byproduct. (16 pts.) 5. Determine the mass of iron consumed in the reaction. Show your work. (16 pts.) 7.75-5.5g=2.25g 6. Calculate the number of moles of iron consumed. Show your work. (16 pts.) 2.25G X 1MOL FE/55.85g= 0.040286 = 0.040286=0.0403 moles Fe Formula: Mass Fe used X 1 mol Fe = Moles of iron used Molar mass of Fe 7. Determine the mass of product formed. Show your work. (16 pts.) 3.52g-.086g=2.66g Formula: (Mass of
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13.80 mL x = 0.01380 L Moles of potassium acid phthalate = = = 0.000735 Moles of NaOH solution = Moles of (HKC8H4O4) x = 0.000735 mol x = 0.000735 mol Molarity (NaOH) = = = 0.053 M TRIAL II Volume of NaOH solution = Final reading of buret - Initial reading of buret =27.20 mL– 13.80 mL = 13.40 mL Converting the Volume (mL) to Volume (L) Volume (liters) = Volume (mL) x = 13.40 mL x = 0.01340 L Moles of potassium acid phthalate
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CHEMISTRY (Theory) Time allowed : 3 hours General Instructions: (i) All questions are compulsory. Maximum Marks : 70 (ii) Marks for each question are indicated against it. (iii) Question numbers 1 to 8 are very short-answer questions and carry 1 mark each. (iv) Question numbers 9 to 18 are short-answer questions and carry 2 marks each. (v) Question numbers 19 to 27 are also short-answer questions and carry 3 marks each. (vi) Question numbers 28 to 30 are long-answer questions and carry 5 marks
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water = (Mass of hydrate) – (mass of dehydrate) Mass of water = (answer to #1) – (answer to #3) Mass of water = (5.000g) – (4.500g) Mass of water = 0.500g 5. Convert the mass of water to moles of water. To do this‚ we need the molar mass (from 2.04 and 3.09-molar mass is the mass‚ in grams‚ of one mole of your
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9-12 Unit 7 II: Unit Title: Mole Concept III. Unit Length: 7 days (on a 90 min. per day block schedule) IV. Major Learning Outcomes: Students should be able to: Mole Concept • Calculate formula mass. • Convert representative particles to moles and moles to representative particles. (Representative particles are atoms‚ molecules‚ formula units‚ and ions.) • Convert mass of atoms‚ molecules‚ and compounds to moles and moles of atoms‚ molecules‚ and compounds
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