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    { 1 } = 0.41g 6. Mass of chlorine in Magnesium Chloride: { 5 } – { 3 } = 0.32g 7. Moles of Magnesium: 0.09g x 1mol = 0.004mol 24.31g 8. Moles of Chlorine: 0.32g x 1mol = 0.009mol 35.45g 9. Moles of Magnesium divided by the smaller number of moles: Mg = 0.004g =1

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    (Oh) 2.4.2 Mol Of Ca3p2

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    appropriate response. 1. What is a mole ratio? 2. What piece of information is needed to convert grams of a compound to moles of the same compound? 3. Phosphine (PH3) can be prepared by the hydrolysis of calcium phosphide‚ Ca3P2: Ca3P2 + 6 H2O 3 Ca (OH)2 + 2 PH3 a) One mole of Ca3P2 produces 2 mol of PH3. b) One gram of Ca3P2 produces 2 g of PH3. c) 3 moles of Ca(OH)2 are produced for each 2 mol of PH3 produced. d) The mole ratio between phosphine and calcium

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    of lithium plus the watch glass *37.41 g of Watch glass *122 cm3 of hydrogen gas collected Calculations from method 1 Moles of hydrogen produced: Assuming that 1 mole of gas occupies 24000 cm3 at pressure and room temperature! I will now calculate the number of moles of the hydrogen gas produced. I will do that by dividing the volume of gas produced by 24000cm3 : Moles (n) = Volume (cm") 24000 cm" So: n = 122 cm" = 0.005083 mol of H2 24000 cm" Equation: 2 Li(s) + 2 H2O (L)2LiOH(Ag) +

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    Abstract Molar volume is the volume that one mole of gas occupies when temperature and pressure are kept constant. The molar volume of a gas can be determined through evaluating how much gas is given off when the number of moles of the substance is known. To find the volume of gas that will be used to calculate the molar volume‚ the process of water displacement can be used. Reference Citation Cesa‚ J. (2002). ChemTopic labs: Experiments and demonstrations in chemistry (vol. 9). Batavia

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    11 g Questions 1. Calculate the value of “n”. Show your work. Include an example of ALL calculations involving solving for “n”. 3.02 g of hydrated copper sulfate is heated to drive off water. The dry sample has a mass of 2.11 g. What is the mole ratio between copper (II) sulfate‚ CuSO4‚ and water‚ H2O? Mass of Hydrate 3.02 g Mass of Dry Sample - 2.11g Mass of Water 0.91 g MM CuSO4= 63.55 + 32.07 + 4(16.00)= 159.62 g/mol 2.11 g CuSO4 (1 mol CuSO4

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    General Chemistry I

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    Test 2 Name___________________________________ MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) Find the combination that will give a gas as a product A. AgNO3(aq) + NaI(aq) B. HCl(aq) + Na2CO3 (aq) C. MgCl2(aq) + K2CO 3 (aq) D. CaSO4 (aq) + (NH4)3 PO4(aq) 1) A) A B) C C) B D) D 2) 2) The balanced molecular equation for complete neutralization of H2 SO4 by KOH in aqueous solution is __________. A) 2H+ (aq) + 2OH- (aq)

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    Solution Moles from mass weighed Moles = Mass Mr = 2.42 97.1 = 0.0249mol Molarity of solution Concentration = Moles Volume = 0.0249 (250 ÷ 1000) = 0.0996dm3 Titration Moles of NH2SO3H Moles = Volume x Concentration = 12.90 x 0.0996 1000 = 1.28484 X10-3 moles From equation 1 mole NH2SO3H = 1 mole KOH Molarity of KOH Concentration = Moles

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    Gas Laws

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    CHAPTER 5 GASES AND THE KINETICMOLECULAR THEORY 5.1 Plan: Review the behavior of the gas phase vs. the liquid phase. Solution: a) The volume of the liquid remains constant‚ but the volume of the gas increases to the volume of the larger container. b) The volume of the container holding the gas sample increases when heated‚ but the volume of the container holding the liquid sample remains essentially constant when heated. c) The volume of the liquid remains essentially constant‚ but the volume of

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    copy work

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    Edexcel Level 3 BTEC Nationals in Applied Science (Forensic Science) Unit 01 – Fundamentals of Science Assignment 01-01‚ Volumetric Analysis Date set: Sept 2010 Date due: Oct 2010 This assignment addresses the following Criteria… Unit 1 – Fundamentals of Science Assessment and grading criteria To achieve a pass grade the evidence must show that the learner is able to: To achieve a merit grade the evidence must show that‚ in addition to the pass criteria‚ the learner is able to: To

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    Chemistry Laboratory 6A – Stoichiometric Analysis of an Iron-Copper Single Replacement Reaction Martin Sun Purpose The purposes of this experiment were to: determine the number of moles of iron reacted; determine the number of moles of copper produced; and calculate the ratio of moles of copper to moles of iron. Materials and Methods Materials and methods for this laboratory followed those laid out in Experiment 6A on pages 56-59 of Essential Experiments for Chemistry by Morrison and Scodellaro

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