of the dehydrated compound from the mass of the hydrate to determine the mass of water that was present in the hydrate. -20.03 grams 5. Convert the mass of water to moles of water. -0.1281 moles 6. Convert the mass of dehydrated compound to moles of the compound. -1.113 7. Divide by the lowest mole value to get a whole number mole ratio. -0.007 Discussion and Conclusion: 1. How would you expect the final measured mass of the anhydrate to change if the hydrate was not heated for a sufficient length
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For example‚ a manufacturer might want to know‚ How much ammonia will I produce from 20 tonnes of nitrogen in the Haber Process? To do these calculations you will need to be familiar with the term Ar (relative atomic mass)‚ Mr‚ Molar mass and Mole. Relative Atomic Mass – Ar • The Ar tells us the average mass of an individual atom (average because of isotopes). • The Ar for an atom has no units as it is relative • You will always be given the Ar for an atom in any example set. Relative
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Deborah Bell April 17‚ 2012 Chemistry 1212K Lab Synthesis Report Introduction In this Chemistry Lab the main objective is to perform accurate chemical analysis for the quantity of elements and compounds in a sample. There will be a compound made then synthesized. The methods used were acid-base titrations‚ redox titrations‚ gravity filtration‚ and distillation. General conclusions included Procedures Weight of Crucibles 1. The first experiment is Preparation of a Cobalt Amine
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by the addition of water to another molecule. In the first trial‚ the mass of water in the hydrate was determined to be 0.41 g‚ while in the second trial the mass of water was 0.52 g. Moles of water associated with a single mole of anhydride were then calculated for both trials‚ giving the values of 4.7 and 4.5 moles of water‚ respectively. This indicated that the empirical formula of the hydrate might be copper (II) sulfate pentahydrate – CuSO4·5H2O. I. INTRODUCTION Hydrates are chemical
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of iron to convert the mass of iron to moles. 85.65g/55.9g 1.534 moles of Iron were used 2. According to the law of conservation of mass‚ what is the mass of oxygen that reacts with the iron? 118.37g – 85.65g = 32.72 grams of Oxygen reacted with Iron 3. Calculate the number of moles of oxygen in the product. 32.72g/15.99g = 2.045 moles is the amount of moles of Oxygen produced 4. Use the ratio between the number of moles of iron and the number of moles of oxygen to calculate the empirical formula
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* Introduction The melting point is defined as the temperature at which the solid is in equilibrium with its liquid‚ and this characteristic is very unique‚ so a substance can be determined by the melting point. Determination of the melting point is very important technique in many areas of chemistry especially‚ in organic chemistry area because the melting point is really significant in order to identify the purity and the identity of a substance. Measuring the melting point is a fast and
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00 g of sodium sulfate decahydrate (Na2SO4.10 H2O). Hydrates Analysis Objective: The formula for an unknown hydrate is quantitatively determined by heating the unknown hydrate to constant mass and calculating the ratio of the moles of water to the moles of anhydrous material. Observations will be made of any color changes during heating and re-hydration of the compound as well as heat effects during the re-hydration. A hydrate is a compound that is associated with a definite number
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Experiment 9 and 10: Volumetric/Vinegar Analysis Abstract: The goal of the experiment that was conducted was to figure out both the molar concentration of NaOH and the standard mole ratio of the NaOH solution. In order to find the concentration of the NaOH solution‚ volumetric analysis was used. In volumetric analysis‚ a titration mechanism was utilized in order to find the reaction that the base will end up having with KHC8H4O4
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Amount # moles Bromine (excess) Trans-cinnamic Acid 1.246 g/cm3 0.148g – do conversion Dichloromethane 1‚3266 g/cm3 - Table of Results Name Amount obtained Molar Mass (g/mol) Amount used (moles) Melting point (Celsius) Color/observations 2‚3-dibromo-3-phenylpropanoic acid 0.285g 307.97 200.4 – 205.1 White powder Limiting reagent: Trans-cinnamic acid (148.16g/mol) 2.5g/148.16g/mol=0.01687mol Stoichiometry ratio: 1:1 ratio Theoretical yield: Since 0.01687 moles of trans-cinnamic
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COLLIGATIVE PROPERTIES 1. Calculate the vapor pressure when 10.o mL glycerol (C3H8O3) is added to 500.0 mL water at 500C. At this temperature the vapor pressure of pure water is 92.5 torr and its density is 0.988 g/mL. Density of glycerol is 1.26 g/mL. 2. Calculate the boiling point and freezing point of the solution if 1.00 kg of ethylene glycol (C2H6O2) is added to a car radiator which contains 4450 g water. a. Kb of water = 0.512 oC/m at normal boiling point of 100oC b. Kf of water
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