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of mass m initially at speed u collides head-on (without rotation) with a stationary puck of mass M. Find the velocities of both puck after the collision if: i) the collision is fully elastic ii) the collision if fully inelastic. i) momentum: *kinetic*** energy**: mu = mv+MV (+ve in direction of initial u) 1 /2 m u2 = 1/2 m v2 + 1/2 M V2
2 eqns in 2 unknowns: V = (u - v) m/M substitute in K eqn: u2 = v2 + (M/m) V2 = v2 + (M/m) (u - v)2 (m/M)2 = v2 + (u - v)2 (m/M) let ρ = (m/M) ⇒ v2 (1 + ρ) - 2ρ u v...

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the theories of conservation of momentum and *kinetic*** energy** in different types of 2D collisions. In order to do this, both an elastic and inelastic collision was conducted on an air table with pucks. A video was taken and analyzed to determine velocity, allowing for future finding of momentum and

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and final momentum are equal irrespective of their masses and initial velocities. The results show that momentum and *kinetic*** energy** of the system is conserved during an elastic collision while only momentum is conserved during inelastic collision.

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Abstract :The purpose of the experiment is to explore elastic and inelastic collisions in order to study the conservation of momentum and ** energy**. The guided track, carts, photogates , 250 g weight and picket fences were the primary components used in the procedural part of the experiment. Each experiment involved the use of the photogates and picket fences to measure the initial and final velocities of both carts when they collide. The data was collected and translated to a graphical model for further...

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Part B
Now, suppose that Zak's younger cousin, Greta, sees him sliding and takes off her shoes so that she can slide as well (assume her socks have the same coefficient of ** kinetic** friction as Zak's). Instead of getting a running start, she asks Zak to give her a push. So, Zak pushes her with a force of 125 \rm N over a distance of 1.00 \rm m. If her mass is 20.0 \rm kg, what distance d_2 does she slide after Zak's push ends?
Remember that the frictional force acts on Greta during Zak's push and...

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-1.80 m/s
2.40 kg
4.80 kg
+1.30 m/s
0.0 m/s
-.433 m/s
2.50 kg
3.90 kg
.850 m/s
11.5 kgm/s
2.68 m/s
5.10 kg
1.00 kg
0.900 m/s
-4.60 m/s
4.60 m/s
KE stands for *Kinetic*** Energy** and is measured in joules. Note that

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1) Introduction
This Lab is about conservation of momentum. It is to investigate the difference of momentum before and after collisions. Using the photo gates record the velocity of each cart, comparing momentum and *kinetic*** energy** to find the law. The experimental apparatus are two red carts in approximately same weight and a gold cart in lower weight than the red ones, a stable air track (blow a constant stream of air out through numerous tiny holes) with low friction and two photo gates.
2)...

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Two-body collision process:
Linear momentum is conserved for a closed and
isolated two-body system during collision
because there is no net external force.
Total *kinetic*** energy** of the system of two
colliding bodies may or may not be conserved.
If it is conserved, the collision is called an
elastic collision. If the

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rocket flight measured in meters and total amount of time aloft measured in seconds. The altitude will be measured by an altimeter. The acceleration will speed up and change direction. The force can be the gravity. The *kinetic*** energy** will be the mass and velocity. The potential

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accelerate to the same angular velocity.3
To calculate the moment of inertia of an object one can imagine that the object is divided into many small volume elements, each of mass ?m. "Using the definition (which is taken from a formula in rotational ** energy**) I=?ri2?mi and take the sum as ?m?0 (where I is the moment of inertia and ri is the perpendicular distance of the infinitely small mass' distance from the axis of rotation). In this limit the sum becomes an integral over the whole object:
I = lim...

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