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** Yield** of CuCl2.2DMSO
Formula weight (Mr) of CuCl2 = 63.55 + (35.45 x 2) =134.45g/mol
Formula weight of product CuCl2.2DMSO = 134.45 + 2[16 + 32.06 + (12.01 x 2) + (1.0079 x 6)] = 290.704g/mol
Mass of CuCl2= 0.850g
Equation for reaction
CuCl2 + 2DMSO -> CuCl22DMSO
Mole ratio between CuCl2 and CuCl22DMSO = 1:1
Mole of CuCl2 = Mass/ Mr = 0.850/134.45 = 0.00632 moles
Since the ratio between CuCl2 and CuCl22DMSO = 1:1, mole of CuCl2DMSO is also 0.0063 moles.
To find theoretical

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The ** Yield** Curve is very similar to the term structure except that it is based on coupon bond

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following formula:
KAl(SO4)2(aq) xH20
After the formula of the product had been deduced, it was then possible to complete the third and final objective of the project, which was to calculate the theoretical ** yield**, the actual

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The purpose of this experiment is to use stoichiometry to predict how much of a product will be made in a precipitation reaction, to measure the reactants and products of the reaction correctly, to figure out the actual ** yield** vs. the theoretical

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Mass of filter paper and dry calcium carbonate __1.5_g
Net mass of the dry calcium carbonate __0.5__g (This is the actual ** yield**)
Step 11: Show the calculation of the theoretical

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Copper(II) oxide will be synthesized from a known mass of copper(II) sulfate pentahydrate. Using the relationship of the balanced equation, and other stoichiometry relationships, you will calculate a theoretical ** yield** of CuO, and your actual

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samples from each plastic material type, we are able to obtain the mean tensile strength, mean tensile modulus and mean ** yield** strength of each material. With this, the results is that PP is the most elastic among them, but the strongest material seems to be GPPS as it has the highest mean tensile strength and mean tensile modulus among the four different plastics. But GPPS did not

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|1.5044 |-- |
|Co(acac-NO2)3 |0.3510 |182-187 |
Percent ** Yield** Calculations:
• Balanced Equations
Cu(NO3)2·3H2O + 2 C4H6O3 ( Cu(C2H3O2)2·3H2O + 2 C2H3O2NO2
2/3 Co(acac)3 + 2 C2H3O2NO2 ( 2/3 Co(acac-NO2)3 + 2 C2H3O2
• Moles of reagent used
- Cu(NO3)2·3H2O, MW: 241.59 g/mol
[pic]
- Acetic anhydride...

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Nitration of Naphthalene
Wed 2/25/2015
Lab report # 1
Abstract:
The purpose of this experiment was to nitrate naphthalene with nitronium ion, which is formed at low concentration from a reaction of nitric acid and sulfuric acid. The percent ** yield** from the experiment was 54.4% of the product, and the melting point of the possible results were 59 °C for 1-nitronaphthalene, and 78°C for 2-nitronaphthalene.
Introduction:
Polynuclear aromatic hydrocarbons such as naphthalene can be nitrated...

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procedure, the calculation included will be the percent ** yield**).
Present a data table containing all of the other data related to the procedure that was not found in the example calculation.
Present a statement of final results from the procedure along with its reliability (i.e., average plus percent deviation). Section 2.0 will not have this statement since the only result is the grams of your unknown which is included in the percent

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