Mass of filter paper and dry calcium carbonate __1.5_g Net mass of the dry calcium carbonate __0.5__g (This is the actual yield) Step 11: Show the calculation of the theoretical yield of calcium carbonate. 0.00680 moles CaCO3 x 100 g CaCO3 1 mole CaCO3 = 0.68g CaCO3 Show the calculation of the percent yield. Actual yield/Theoretical yield x 100 (0.5/0.68) x 100 = 73.5% Conclusion: The objectives of this experiment are to predict the amount of product
Premium Sodium Stoichiometry Measurement
actual yield) Step 11: Show the calculation of the theoretical yield of calcium carbonate. The mole ration between CaCl2-.2H2O and CaCO3 is 1:1 that means that if we have 0.00680 moles of CaCl2-.2H2O we will get 0.00680 moles CaCO3 Convert the moles of CaCO3 to grams of CaCO3 = 0.00680 moles CaCO3 x 100 g CaCO3 1 mole CaCO3 = 0.68g CaCO3 Show the calculation of the percent yield. = Actual yield/Theoretical
Premium Stoichiometry Solubility Calcium carbonate
78 D 4 $635.52 1). The yield to maturity on bond A is . a. 10% b. 11% c. 12% d. 14% e. none of the above 2). The yield to maturity on bond C is . a. 10% b. 11% c. 12% d. 14% e. none of the above 3). A coupon bond that pays interest annually is selling at par value of $1‚000‚ matures in 5 years‚ and has a coupon rate of 9%. The yield to maturity on this bond is a. 6.00% b. 8.33% c. 9.00% d. 45
Premium Bond Bonds Yield
Mass of filter paper and dry calcium carbonate __1.7__g Net mass of the dry calcium carbonate ___0.7_g (This is the actual yield) Step 11: Show the calculation of the theoretical yield of calcium carbonate. .0068 mol of CaCO3 *100.06 g CaCO3/1mol of CaCO3 =.6804 g of CaCO3 Show the calculation of the percent yield. (Actual yield/theoretical yield)*100 = (.7/.68)*100 =102% Conclusion: The objectives of this experiment were to use stoichiometry as a method to predict
Premium Stoichiometry Solubility Measurement
to complete. OBJECTIVE 1. Predict the amount of product produced in a precipitation reaction using stoichiometry 2. Accurately measure the reactants and products of the reaction 3. Determine the actual and theoretical yield 4. Calculate percent yield PROCEDURE Please complete the entire experiment as instructed in the lab manual except for any modifications noted below. Fill out the report below‚ insert your digital photograph(s) into the report‚ and submit it me electronically
Premium Stoichiometry Yield Filter paper
evaporated 1.00 g of sodium carbonate and 1.00 g of lead II nitrate was given to start the lab out with. To calculate the percent yield of lead II carbonate‚ the limiting reactant must be identified first. 1.00 g Na2CO3 x 1 mole106 g = 0.00943 mole Na2CO3 1.00 g Pb(NO3)2 x 1 mole331 g = .00302 mole Pb(NO3)2 Limiting reactant: lead II nitrate Next‚ the theoretical yield of lead II
Premium Stoichiometry Water Yield
Preparation and SN1 Reactivity of 2-Bromobutane Whitney Bellido Department of Chemistry‚ Illinois State University‚ Normal‚ IL 61790-4160 Submitted: April 4th‚ 2013 Introduction The overall goal of this experiment is to understand and be familiar of SN1 reactivity. We also learned how to prepare 2-Bromobutane by learning how to distill and extract this product from its organic layer. Finally‚ another goal was to specifically understand the relative reactivity of alkyl halides under SN1 conditions
Premium Stoichiometry Distillation Yield
turned blue - Postlab Questions 1. Whas is the theoretical yield of casein based on the table of Milk Composition Analysis? 3.3 % 2. What is your percent yield? 3.2g/3.9g x 100= 82% 3. Why might your percent yield be lower than expected? More fat has a decrease in protein which would cause a lower percent yield. 4. Why might your percent yield be higher than expected? Less fat causes an increase in protein‚ thus giving a higher percent yield. 5. In the precipitation of casein‚ why is it important
Premium Milk Cheese Yield
Purpose=The purpose of this lab was to combine reactants‚ which we would pick ourself‚ to make 2 grams of Copper Phosphate and another product. Background: Chemistry is the branch of science that deals with the identification of the substances of which matter is composed. Chemistry has to do with many things we use today. For example‚ fireworks are made by the chemical combining magnesium‚ titanium‚ copper‚ aluminum‚ strontium‚ or other periodical elements. Things also like making plastic‚ jewelry
Premium Chemical reaction Stoichiometry Reagent
Density of Bromine = 3.103 g/ml[2] Mass of Bromine = (0.25ml) X (3.103g/ml) = 0.78g Molar mass of Bromine = 79.9g/mol[2] Number of moles of bromine = (0.78g) / (79.9g/mol) = 0‚0097 mols Acetanilide is the limiting reagent -To find the heoretical yield of p-bromoacetanilide: Number of moles of p-bromoacetanilide =0‚0049 mols Molar
Premium Stoichiometry Yield Oxygen