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    Magnetic Force

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    An electron gun fires electrons into a magnetic field directed straight downward. Find the direction of the force exerted by the field on an electron for each of the following directions of the electron’s velocity: (a) horizontal and due north; (b) horizontal and 30° west of north; (c) due north‚ but at 30° below the horizontal; (d) straight upward. 2. (a) Find the direction of the force on a proton moving through the magnetic fields in Figure 1‚ as shown. (b) Repeat part (a)‚ assuming the moving

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    Force Of 870n

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    Mass 6.00 kg moved by 18.0N. What is its acceleration? Divide both sides by m a=18N/6.00kg convert N = 18N * 1kg*m/s^2 = 18kg*m/s^2 a=18kg*m/s^2/ 6.00 kg = 3m/s^2 a=3m/s^2 7. Truck pulls trailer with friction force of 870 N and a coefficient of friction 0.23. What is the trailer’s normal force. 870N=.023(FN) divide by .023 FN=870N/.023 FN=37826.7N 9. mass 13.0 kg dropped from a cliff. Find its weight Fw=13.0kg * 9.8m/s^2 Fw=127.4kg*m/s^2 Fw=127.4N 13. A force of 175N needed to keep a 640N

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    Improper Force

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    While Bolger’s analysis looked broadly at police use of force‚ the analysis by Harris looked only at improper use of force. What is the difference between these two concepts and what differences did you notice regarding Bolger’s results and Harris’s findings? The obvious difference between the study of the use of force and the study of improper force is easily understandable. Bolger looked at a broad sense and didn’t leave out the use of force in a rightful manner which in my opinion led to different

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    Triangle of Forces

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    ............................... 7 AIM To show that three forces acting upon a body‚ in equilibrium‚ may be represented by a triangle of forces. (Vector addition) INTRODUCTION With this experiment we will show that a body in a state of equilibrium‚ with three forces acting in a singular plane. The following conditions must be met: * Moment of all three forces must pass through the same point. * Magnitudes of the forces can be represented by the sides of a triangle‚ each as a vector

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    Driving Force

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    Chapter 20 Driving Forces Analysis Ch20. Driving Forces • • • • • • • • • Short Description Background Strategic Rationale & Implications Strengths & Advantages Weaknesses & Limitations Process for Applying Technique Summary Case Study: Digital Music Industry FAROUT FT Press 2007. All Rights Reserved. Business and Competitive Analysis. By C. Fleisher & B. Bensoussan. Ch20.2 Ch20. Driving Forces Short Description • Driving forces analysis (DFA) is a way

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    Force Vector

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    Engineering Mechanics: Statics in SI Units‚ 12e 2 Force Vectors Part 2 Copyright © 2010 Pearson Education South Asia Pte Ltd Chapter Objectives • Cartesian vector form • Dot product and angle between 2 vectors Copyright © 2010 Pearson Education South Asia Pte Ltd Chapter Outline 1. 2. 3. 4. 5. Cartesian Vectors Addition and Subtraction of Cartesian Vectors Position Vectors Force Vector Directed along a Line Dot Product Copyright © 2010 Pearson Education South Asia Pte

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    Force and Spring

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    = 9.8 N/m .25m K avg. = 9.8 N/m 2. Unknown Masses Green: m = kx = 9.8 * .07 = .07kg = 70g g 9.8 Gold: m = kx = 9.8 * .155 = .155kg = 155g g 9.8 Red: m = kx = 9.8 * .3 = .300kg = 300g 9.8 3. Explain the effect of mass on Hooke’s Law. Hooke’s Law states that the restoring force of a spring is directly proportional to a small displacement. Applying

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    Normal Force

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    Time x 2 = 3.6 Great height reached by ball – (Velocity)(time)+(-5)(time^2) 18x1.8+(-5)(1.8^2)=16.2 A model rocket accelerates upward from the ground with a constant acceleration‚ reaching a height of 63 m in 8 s.  * Speed at height 63 - 2x63/8 = answer What is the acceleration= answer/8 * If you were to drop a rock from a tall building‚ assuming that it had not yet hit the ground‚ and neglecting air resistance‚ after 5.5 s; * How fast? 5.5x10 * How far? Half gravity = 5x5.5^2 *

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    Use of Force

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    Use of Force Use of Force Serena R. Smith Grand Canyon University JUS 515 Use of Force Use of Force One night‚ a small-town patrol officer stops a car driven by two teenagers. The officer believes that one of them might be responsible for a string of recent burglaries. The teens are questioned‚ and the officer becomes angry at their responses. Over the objections of the teenagers‚ both teens are pulled out of the car and shoved around a little. They are both told that they are under arrest

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    Force and Kg

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    More Equilibrium Problems 1. A uniform 25 kg bar‚ 6.0 m long‚ is suspended by a cord as shown. What is the tension in the cord? 270 N 2. A boom hinged at P is held stationary‚ as shown in the diagram below. If the tension in the supporting cord‚ attached three-quarters of the way along the boom from P‚ is 720 N‚ what is the weight of the boom? 2160 N 3. A uniform beam 6.0 m long‚ and with a mass of 75 kg‚ is hinged at A. The supporting

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