Philppines‚ 1004 Keywords: Kenaf; mathematical equation; quantifying sorbent capacity; oil spill; sorbent; sorption ABSTRACT Sorption using natural sorbents is an alternative method of oil spill treatment. This research proposed a polynomial equation that described the sorption behavior of Hibiscus cannabinus L. core in Bunker Oil C-seawater mixtures. This equation may be applied for oil concentrations of 0.001 to 0.003 mL oil/mL mixture and for a contact time of 15.00 to 120.00 min
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ADVANCED MATHEMATICS MONASH UNIVERSITY FOUNDATION YEAR 1. INTRODUCTION A student taking this course must also be concurrently enrolled in (or previously studied) MUFY Mathematics Part A as many of the topics in MUFY Advanced Mathematics require an understanding of the concepts in MUFY Mathematics Part A. 2. COURSE OBJECTIVES Advanced Mathematics is designed to prepare students who wish to take tertiary courses with a high mathematical content‚ or which use
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Algebra/Trig Review Introduction This review was originally written for my Calculus I class but it should be accessible to anyone needing a review in some basic algebra and trig topics. The review contains the occasional comment about how a topic will/can be used in a calculus class. If you aren’t in a calculus class you can ignore these comments. I don’t cover all the topics that you would see in a typical Algebra or Trig class‚ I’ve mostly covered those that I feel would be most useful for
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2013 May Candidate Name: Emil Abrahamyan Candidate Number: 006343-021 Mathematics Higher Level Type 1: Shadow Functions SHADOW FUNCTIONS The Aim of the Investigation: The overall aim of this investigation is to investigate different polynomials with different powers and create shadow function for each one. Afterwards identify the real and imaginary components of complex zeros from the key points along the x-axis using the method of shadow functions and their generators. Technology
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CCE for SSLC 2014 - 15 Subject : Mathematics Dimension 1 sl.no. Unit no.of periods marks 1 Real numbers 2 2 Sets 2 3 Progressions 4 Permutations and combinations 5 5 Probability 3 6 Statistics 4 7 Surds 3 8 Polynomials 4 9 Quadratic equations 10 10 10 Similar triangles 6 11 Pythagoras theorem 4 12 Trigonometry 6 13 Co-ordinate geometry 4 14 Circle - chord properties 1 15 Circles - tangent properties 9 Dimension – 2 Weightage to objectives 1 2
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matrix methods or otherwise‚ find a quadratic function and a cubic function which model this situation. Explain the process you used. On a new set of axes‚ draw these model functions and the original data points. Comment on any differences. Find a polynomial function which passes through every data point. Explain you choice of function‚ and discuss its reasonableness. On a new set of axes‚ draw this model function and the original data points. Comment on any differences. Using technology‚ find one
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For four years during high school‚ we learn the principles of science and math. How to solve for x in a polynomial equation. But as a volunteer engineer for a manufacturing factory during my sophomore year‚ I found that the typical high school curriculum is just not enough to prepare students for the real world. Our schools have become too old-fashioned. Today‚ success in the real world is not about memorizing the periodic table or the quadratic equation. It’s not about studying for hours the
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Partial Fractions A way of "breaking apart" fractions with polynomials in them. What are Partial Fractions? We can do this directly: Like this (read Using Rational Expressions to learn more): 2 + 3 = 2·(x+1) + (x-2)·3 x-2 x+1 (x-2)(x+1) Which can then be simplified to: = 2x+2 + 3x-6 = 5x-4 x2+x-2x-2 x2-x-2 ... but how do we go in the opposite direction? That is what we discover here: How to find the "parts" that make the single fraction (the "partial fractions")
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coefficients for a linear relation c = bo + b1 d and plot the equation obtained together with the data. NOTE: It is recommended to use a spreadsheet program (Excel) to solve this problem Problem #2: Heat capacities are usually given in terms of polynomial functions of temperature. The equation for carbon dioxide is: C p = 8.4448 + 0.5757 *10 −2 T − 0.2159 *10 −5 T 2 + 0.3059 *10 −9 T 3 where T is in °F and Cp is in BTU/(lb mol) (°F). Convert the equation so that T can be in °C and Cp will be in
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Oklahoma Algebra II End-of-Instruction Test Preparation and Practice Teacher’s Guide Help for the Oklahoma ACE Algebra II Test i-viii_OK_A2_TE_FM.indd i 7/11/09 12:38:29 AM Copyright © by Houghton Mifflin Harcourt Publishing Company. All rights reserved. No part of this work may be reproduced or transmitted in any form or by any means‚ electronic or mechanical‚ including photocopying or recording‚ or by any information storage or retrieval system‚ without the prior written permission of
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