"Chemlab specific heat" Essays and Research Papers

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    water plays a part in this. One method of reducing internal body heat is sweating; sweat is mostly made up of water. The structure of the water molecule means that it has very high melting and boiling points for a molecule of its nature because of the strong attraction between them. This means that a large amount of energy is needed before the molecules begin to move about and therefore change state. It is because of this high latent heat of vaporisation that water is an effective coolant; energy from

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    Fire Fighting Notes

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    occupant to move safely before threatened by smoke Containment • Ensure fire can be contained to smallest possible area Extinguishment • Ensure fire can be extinguished quickly with minimum damage FIRE DETECTION SYSTEM SMOKE DETECTORS HEAT DETECTOR FLAME DETECTOR GAS SENSING DETECTOR Ionisation Dectectors Fixed Temperature Detector Infrared Flame Detector Infrared Flame Detector Photolectic Detector Rate Compensation Detector Ultra Violet Detector Ultraviolet

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    weight and the difference was the water mass. I placed the burner stand inside aluminum tray‚ then the beaker filled with water on top of burner stand. Measured the initial water temperature. I left the thermometer inside the beaker to measure water heat later. I started with a marshmallow. I weighted alone first the marshmallow and the fork. Later weighted both together. I subtracted the total weight of fork + marshmallow to obtain the food item weight. I lit the marshmallow and once on fire‚ I

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    Lab Report-

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    Date of Experiment- 11/27/12 Date Report Submitted 11/27/12 Title: Caloric Content of Food Purpose: to be able to measure the energy content of foods Procedure: We are going to take food items and burn them to heat water to be able to determine the amount of “energy” a food source can emit. Data Tables: |Data Table 1: Food Item - Observations | |Food

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    My greatest ambition

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    Cambridge International Examinations Cambridge Ordinary Level * 8 7 0 6 7 3 2 3 4 6 * 5054/32 PHYSICS Paper 3 Practical Test May/June 2014 2 hours Candidates answer on the Question Paper. Additional Materials: As listed in the Confidential Instructions. READ THESE INSTRUCTIONS FIRST Write your Centre number‚ candidate number and name on all the work you hand in. Write in dark blue or black pen. You may use an HB pencil for any diagrams or graphs. Do not use staples‚ paper

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    This experiment will test the suggestion that the enthalpy change between a metal and a solution of a salt is related to the relative position of the two metals in the reactivity. Presumably the further apart in the series the bigger the enthalpy change will be. The experiment is as follows‚ 1) Zn(s) + CuSO4(aq) ZnSO4(aq) + Cu(s) 2) Zn(s) + Pb(NO3)2(aq) Zn(NO3)2 (aq) + Pb(s) Both of the solutions will be in 1mol.dm-3 Apparatus: Distilled Water Polystyrene Cup

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    Experiment 1: Calorimetry

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    recorded; the change in temperature (∆T) was calculated by subtracting the initial temperature from the final temperature. The reaction was performed twice for every calorimeter. The heat capacity (Ccal) of each calorimeter was calculated using the formula‚ C_cal=(-〖∆H〗_rxn^o n_LR)/∆T [1] where ∆Horxn is the total heat absorbed or evolved for every mole of reaction and nLR is the number of moles of the limiting reactant. The ∆Horxn used was -55.8kJ per mole of water while the nLR was 0.005 mole

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    IGCSE Physics Answers

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    Page 12 1 a) Between t = 30 and t = 45 mins b) 7.5 mins c) i) distance travelled = area under graph between t = 0 and t = 12½ mins ii) average speed = total distance travelled total time for journey = total area under graph 60 mins 2 a) ∆v = 32 m/s a =10 m/s² t = ∆v = 32 = 3.2 s a 10 b) 3 a) OP – constant acceleration PQ – constant acceleration (greater than OP) QR – constant speed RS – constant deceleration b) O and S c) 6 m/s d) 70 s e) Total distance travelled = area under

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    Chem 1331 Midterm 2

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    1. | |   | What is the pressure‚ in atm‚ of a tank of gas with a regulator that reads 1250mmHg? | |   | Student Response | Correct Answer | A. | 1.64 |   | B. | 490 |   | C. | 1.79 |   | D. | 0.608 |   | E. | 1.25 |   | | Score: | 0/1 |   | | 2. | |   | A 147.9-L sample of dry air is cooled from 88.0°C to 22.1°C while the pressure is maintained at 2.85 atm. What is the final volume in L? (Do not type the units.) | |   | Student Response | Correct

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    months melting the top one metre of ice‚ called the active layer. This layer contains both water and mud‚ which both have different viscosities and therefore different specific heat capacities. During the three months of summer‚ when the active layer is visible‚ rocks will embed themselves into it. These rocks have a fairly high specific heat capacity in relation to ice‚ so the ice around it will be melted‚ and the process of percolation will cause a pool of water will form below the rock. As the temperature

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