HALIDES General formula: Ar–X where X = F‚ Cl‚ Br or I Examples Structure: C-X bonds are shorter and stronger Bond C-Cl C-Br Ar-X 1.69 A° 1.86 A° R-X 1.77 1.91 Dipole moments are unusually small. Bond C-Cl Preparation: 1. electrophilic aromatic substitution – useful only if one product is obtained C-Br Ar-X 1.7 D 1.7 D R-X 2.10 D 2.15 D Dipole moments may cancel out depending on the geometry of the molecule. 1 3/22/2012 PHYSICAL PROPERTIES: Boiling points – similar to those
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Experiment B10- Photocromism and Piezochromism Reece Harms 4320288 Introduction This experiment investigates an oxidative coupling reaction in an to synthesise triphenylimidazole dimer from 2‚4‚5-triphenyl-1H-imidazole. The resulting compound was investigated for both photochromic and piezochromic properties by way of formation of a stable radical‚ utilizing visual observations and UV-Vis as a means of distinction. Both the oxidative coupling reaction and the dimers interaction with light
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reaction (SN2‚ E2 etc)? E1 3. Why was acid employed in this reaction? The acid was used to protonate the leaving group (OH) to form water which is a much better leaving group than OH. 4. What role does the aromatic ring play in both intermediate and product formation? The aromatic ring is also benzyllic which helps us steer the reaction in the E1 pathway we are trying to achieve. It also forms a very stable carbocation which is essential for an E1 reaction to occur. The ring helps stabilize
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molecular formula would be C8H11N with a HDI of 4. Looking at the IR spectroscopy‚ there is a sharp peak at around 3000 cm-1‚ which indicates C-H bonds. At around 1600 cm-1‚ we see a peak which tells us there are C=C that might corresponds to an aromatic benzene ring‚ which I proved using the NMR. The Nitrogen is also present on the IR spectroscopy leaving its mark with a peak at around 3200 – 3500 cm-1. Lastly‚ I finalized my structure using the NMR spectroscopy. With the information I have collected
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INTRODUCTION Hydrocarbons are compounds that consists carbon and hydrogen only. They are the simplest organic compounds. Hydrocarbons‚ because of their number and variety‚ are classified into different ways. One way of classifying hydrocarbons is in which way carbon atoms are connected. It can be classified as either a chain aliphatic hydrocarbon or a cyclic hydrocarbon. Chain aliphatic hydrocarbons are compounds that are linked either in a single or branched chain. An example of this is hexane
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REACTIONS OF HYDROCARBONS Diane Cate Satsatin Biology Student‚ Biology Department College of Science‚ De La Salle University-Dasmarinas ABSTRACT Five substances which are Hexane‚ Eugenol‚ Unknown hydrocarbon 1‚ Unknown hydrocarbon 2‚ and Acetylene gas was used for the selective reactivity of hydrocarbons to functional group tests; Bayer’s test‚ Bromine test light‚ Bromine test dark‚ and Tollen’s test. In Bayer’s test‚ only Acetylene‚ Eugenol and Unknown hydrocarbon 2 reacted positively
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2‚3‚.. and m= 1‚2‚3‚.. | PHYSICAL PROPERTIES | * MP & BP Size of hydrocarbon molecules inc‚ f.o.a inc‚ more heat overcome f.o.a * Density Mass per molecule inc faster than volume per molecule * Gas – liquidSize of hydrocarbon molecule inc‚ f.o.a stronger‚ mp&bp inc * Insoluble in water‚ soluble in organic solvent(covalent comp) * Insulator * Less dense than water | * MP & BP Size of hydrocarbon molecules inc‚ f.o.a inc‚ more heat overcome f.o.a * Density mass per molecule
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all aromatic compounds known today share the same distinction (many are in fact‚ odorless or even unpleasant)‚ they are the principle components in such pleasant smelling substances as cinnamon‚ licorice‚ wintergreen‚ clove & vanilla CLASSIFICATION – - also known as arenes‚ many aromatic compounds possess the benzene ring functional group: G’s FG = aromatic compound or arene benzene ring or aryl grp - other compounds which do not contain a benzene ring are also referred to as “aromatic” based
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Hydrocarbon – Alcohols • Ethanol - 92.3% by weight of ethanol‚ 94.9% by volume. - 70 % which is used as local antiinfective • Diluted Alcohol - 48.4 % to 49.5% used as solvent • Brandy - distillation from wine • Whisky - fermented malted grain • Rum fermented molasses Product of Reductive Metabolism • Mannitol • Ash Manna • Fraxinus ornus – Oleaceae • Osmotic diuretic • Laxative Product of Reductive Metabolism • Sorbitol- Mountain ash • Sorbus aucuparia Rosaceae • Half as sweet as
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Analysis of Hydrocarbons Jessa Grace B. Castillo* and Stephanie Chua Department of Chemistry‚ University of Santo Tomas‚ Manila‚ Philippines ______________________________________________ Hydrocarbons are organic compounds containing only hydrogen and carbons and further divided in major types. Hydrocarbons react differently in reagents. The basis of determining an unknown hydrocarbon is due to the differences in reactions of hydrocarbons. An unknown compound is determined using tests.
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