mass of the product in for each mole. We divided this to find out how many grams of reactant for every one gram of product‚ and finally multiplied this by two. Our final results were lower than the desired 2.00 grams. Balanced Equation: CaCl2 X 2H2O + Na2CO3 x H2O → CaCO3 + 2NaCl + 3H2O Background Information: We chose Calcium Chloride dihydrate because it is soluble in water‚ not very expensive and only mildly toxic (LD50 1000mg/kg). In addition we chose Sodium Carbonate because it is soluble
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representative samples of each food group under different conditions‚ such as increased/decreased pH and presence of other substances‚ were observed. A pancreatin solution was first prepared from a hog pancreas and was completely neutralized using 0.5% Na2CO3. Afterwards‚ 3 mL each of the neutral pancreatin solution was placed in 7 test tubes and were further added with other specified reagents. The test tubes containing HCl were not effective in digesting the biomolecules since pancreatin is only active
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Guided Inquiry Lab CaCl2 + Na2CO3 → CaCO3 + 2 Na + 2 Cl Purpose: Determine the amount of ions‚ specifically calicum‚ that are present in multiple samples of water by adding another chemical to create a reaction to percipitate the calcium out of the water into a measureable solid Materials: balance (.001g)‚ 100ml beakers‚ graduated cylinder‚ drying oven‚ Na2CO3 (sodium carbonate)‚ stir rod‚ scoopula‚ DI water‚ watch glasses‚ filter paper‚ ring stand‚ funnel‚ water samples with CaCl2 (calcium chloride)
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Solvay process Raw materials - NaCl‚ salt - CaCO3‚ limestone - H2O‚ water - NH3‚ ammonia is recycled Useful products - sodium carbonate. Na2CO3 – reason for process Waste products - CaCl2‚ calcium chloride - Heat Chemical properties of the main product (Na2CO3) - Forms several hydrates which are used in many ways - It is moderately alkaline‚ so it can neutralise strong acids - Can precipitate many metal ions from solution as carbonates Uses of sodium carbonate - Glass
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carbonate. This formula is: Na2CO3(aq) + CaCl2. 2H2O(aq) à CaCO3(s) + 2NaCl(aq) + 2H2O 1. Put on your goggles. 2. Weigh out 1.0 g of CaCl2·2H2O and put it into the 100-mL beaker. Add 25 mL of distilled water and stir to form the calcium chloride solution. Use only distilled water since tap water may have impurities that interfere with the experiment. 3. Use stoichiometry to determine how much Na2CO3 you will need for a full reaction. 4. Weigh the calculated amount of Na2CO3 and put it in a small
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the driving forces that control a double replacement reaction. 3. a. Balanced equation: CaCl2 (aq) + NaPO4 (aq) Ca3(PO4)2 (s) + 6NaCl (aq) Ionic equation: 3Ca2+(aq) + 6Cl-(aq) + 6Na+(aq) + 2PO43- (aq) Ca3(PO4)2 (s) + 6Na+ (aq) + 6Cl- (aq) Net ionic equation: 3Ca2+ (aq) + 2PO43- (aq) Ca3(PO4)2 (s) b. Na2SO (aq) + Cu(NO3)2 (aq) NO REACTION c. Balanced: 2AgNO3 (aq) + CaCl2 (aq) 2AgCl (s) + Ca(NO3)2 (aq) Ionic equation: 2Ag+ (aq) + 2NO3- (aq) + Ca2+ (aq) + 2Cl- (aq)
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calculate the percent yield. Procedure First‚ 1.0 g of CaCl2·2H2O was put into a 100-mL beaker and 25 mL of distilled water was added. The two ingredients were stirred to create a calcium chloride solution. Then‚ stoichiometry was used to determine how much Na2CO3 was needed for a full reaction: First‚ 1 g of CaCl22H2O was converted to moles: 0.00680 moles. The mole ratios of CaCl22H2O and Na2CO3 was seen to be 1:1. Then‚ moles of Na2CO3 were converted to grams: 0 .72 g. The measure of CaCo3 was
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This left us with the silver and chlorine which yield us silver chloride which is a solid. We did note on our observation that we had a change in color and a solid precipitate. 3. Na2CO3(aq)+ HCl(aq) → NaCl(aq) + HCO3(aq) Na2CO3 + 2HCl → 2NaCl + H2O + CO2(aq) 2Na+ + CO32- + 2H+ + 2Cl- → 2Na+ + 2Cl- + H2O + CO2 CO32- + 2H+ → H2O(l) + CO2(g) With this reaction the carbonate and the diatomic hydrogen combined together to make the bubbling effect that
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r Lab Report 5 Introduction to the Classes of Chemical Reactions Course: Chem. 1151L‚ Tuesday & Thursday June 23‚ 2011 Mr. Nasir Uddin Pre Lab Questions: 1. CaBr2 (aq) + K3PO4 (aq) → CA(PO4)2(S) + KBr (aq) = Ca3(PO4)2 + 6 KBr Double Replacement 2. Li(s) + O2(g) = Li2O(s) =2 Li2O Decomposition 3. CH4 + O2 = CO2 + H2O = CO2 + 2 H2O Combination 4. AgBr(s) = Ag (s) + Br2(l) = 2 Ag + Br2 Combination 5. Mg(s) + H2SO4 (aq) = MgSO4 + H2
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Precipitation Reaction|Lab Section: 73426| Data Tables: Step 3: Show the calculation of the needed amount of Na2CO3 CaCl2.H2O(aq)= m/M =1/147 =0.0068 mol CaCO3(s)=0.0068*1/1 =0.0068 mol CaCO3(s)= CaCO3 (s)= CaCO3 mol *CaCO3 g =0.0068 mol*100.01 g =.68 g Step 4: Mass of weighing dish _0.6_g Mass of weighing dish and Na2CO3 .72_g Net mass of the Na2CO3 .12_g Step 6: Mass of filter paper __1.0__g Step 10: Mass of filter paper and dry calcium
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