Harvesting CaCo2 in a precipitate reaction results in less grams desired amount (2 grams)

Topics: Sodium, Solubility, Calcium compounds Pages: 6 (1437 words) Published: March 3, 2014
Chemistry 1
February 3, 2014
Harvesting CaCo2 in a precipitate reaction results in less grams desired amount (2 grams) Abstract:
The objective of this experiment was to synthesize 2.00 grams of CaCo2 for a hypothetical manufacturing company using the two least detrimental (in regards to health and the environment) and least expensive chemicals possible through a precipitate reaction. A precipitate reaction happens when cations and anions of certain aqueous solutions react and combine forming a precipitate, which is an insoluble ionic solid. In this precipitate reaction we dissolved both chosen chemicals (powder Calcium Chloride dihydrate and powder Sodium Carbonate) in distilled water and then mixed them together in a single beaker. Finally we filtered this mixture and let all the water evaporate leaving behind solely the precipitate. In order to determine the amounts needed of each reactant we had to use stoichiometry. First we had to set up a balanced equation of the precipitate reaction that yielded 2.00 grams of CaCo3, then we looked at the ratio of moles reactant to moles product. We then substituted the ratio of the molar mass of each reactant to molar mass of the product in for each mole. We divided this to find out how many grams of reactant for every one gram of product, and finally multiplied this by two. Our final results were lower than the desired 2.00 grams. Balanced Equation:

CaCl2 X 2H2O + Na2CO3 x H2O → CaCO3 + 2NaCl + 3H2O

Background Information:
We chose Calcium Chloride dihydrate because it is soluble in water, not very expensive and only mildly toxic (LD50 1000mg/kg). In addition we chose Sodium Carbonate because it is soluble in water, inexpensive and only less toxic (LD50 4090mg/kg). Our Product (CaCo3) is slightly soluble in water; in acids with evolution of carbon dioxide, it is a white color and has no odor with a toxicity of LD50 6450mg/kg. Calculations:

1 mol CaCl2 X 2H2O/ 1 mol CaCo3 X 147.01056 g CaCl2 X 2H2O/ 100.0869g CaCo3 = 1.47g X 2 = 2.94g CaCl2 X 2H2O 1 mol Na2CO3 x H2O/1 mol CaCo3 X 124.00378 g Na2CO3 x H2O/ 100.0869g CaCo3 = 1.24g X 2 = 2.48 g Na2CO3 x H2O

Name
Formula
Properties/ price/ toxicity
Calcium Sulfate (dihydrate)
CaSO4• 2H2O
$12.95/100 g
Soluble: Slightly in water.
Color: Off-white
Odor: None
non-toxic
Calcium chloride dihydrate
CaCl2•2H2O
$8.05/100g
Soluble: Water and alcohol.
Color: White
Odor: None
Slightly toxic (LD50 1000mg/kg)
Calcium acetate monohydrate
Ca(C2H3O2)2•H2O
$6.05/100g
Soluble: Water; slightly in alcohol.
Color: White
Odor: Slight vinegar.
non-toxic
Calcium nitrate tetrahydrate

Ca(NO3)2•4H2O
$8.70/100g
Soluble: Water, alcohol, and acetone.
Color: Colorless
Odor: None
Slightly toxic (LD50 3900 mg/kg)   
Sodium carbonate
Na2CO3
$9.95/500g
Soluble: Water, glycerin; not alcohol.
Color: White
Odor: None
skin irritant (LD50 4090mg/kg)
Potassium carbonate
K2CO3
$13.25/100g
Soluble: Water; not alcohol.
Color: White
Odor: None
Non-toxic
Lithium carbonate
Li2CO3
$18.95/100g
Soluble: Slightly in water; insoluble in alcohol; soluble in dilute acid. Color: White
Odor: None
Moderately toxic (LD50 525mg/kg)
Magnesium carbonate
MgCO3

$10.45/100 g
Soluble: Acids; slightly in water; insoluble in alcohol.
Color: White
Odor: None
Non-toxic

Procedure:
1. Weigh two beakers
2. Weigh the two reactants separately in weigh boats
3. Measure out enough water to dissolve each reactant
4. Pour water into beaker w/ one reactant (each beaker has already been weighed) 5. Pour water into beaker w/ other reactant
6. Mix the two aqueous solutions together create Calcium Carbonate (stir thoroughly to make sure everything is reacted before moving on to next step) 7. Weigh filter paper
8.Place the filter paper into a funnel over the mouth of a beaker 9. Pour solution into beaker until completely filtered (filter as many times needed) 10. Let filter paper w/ Calcium Carbonate dry on a watch glass //...
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