accurately weighed due to some CaCO3 reside being left on the sides of the beaker. Na2CO3 + CaCl22H2O = CaCO3 + 2NaCl + 2H2O Convert 1g of CaCl22H2O to moles‚ 1g CaCl22H2O x 1mol = .00689Moles CaCl22H2O 144.9994 Consider the mole ratio of Na2CO3 to CaCl22H2O 1:1 Thus‚ 1 mole of CaCl22H2O will equal 1 mole of Na2CO3 Convert moles of Na2CO3 to grams: .00689moles Na2CO3 x 105.99 = .73027g Na2CO3 1 mole Na2CO3 How much CaCO3 can we expect? .00689 moles of CaCl22H2O x 1mole CaCO3 = .00689Moles
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solution was swirled‚ it became orange again. At the end point‚ the solution turned from orange to pink. Calculations 2HCl + Na2CO3 -> 2NaCl + CO2 + H2O Therefore‚ mole ratio of Hydrochloric Acid to Sodium Carbonate is 2:1 Percentage uncertainty of volume of HCl = 0.10/14.63 * 100 = 0.68% Percentage uncertainty of volume of Na2CO3 = 0.06/25 * 100 =0.24% Number of moles of sodium carbonate
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Chemistry Purpose/Objective: To observe the colors produced when elements are put into a flame and to prove when electrons jump down from higher layers they release energy in the form of light. Materials: CoCl2 Na2SO4 CaCl2 KCl SrCl2 CuCl2 LiCl Unknown A Unknown B Distilled H2O Q-tips Beaker Bunsen Burner Spectroscope Spot Plate Procedure: 1. Light the Bunsen Burner. 2. Fill a beaker with water. 3. Get the spot plate with all the known and unknown
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Edexcel Level 3 BTEC Nationals in Applied Science (Forensic Science) Unit 01 – Fundamentals of Science Assignment 01-01‚ Volumetric Analysis Date set: Sept 2010 Date due: Oct 2010 This assignment addresses the following Criteria… Unit 1 – Fundamentals of Science Assessment and grading criteria To achieve a pass grade the evidence must show that the learner is able to: To achieve a merit grade the evidence must show that‚ in addition to the pass criteria‚ the learner is able to: To
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is titrated with an HCl titrant‚ standardized by 1o Na2CO3. The indicators used are phenolphthalein for basicity and methyl orange for acidity. The two volumes of the titrant are then used to calculate percent composition of soda ash analyte. Statistical parameters such as relative standard deviation and confidence limits are also calculated. At the end of the experiment‚ the calculate percent /calculated average percent by mass of Na2CO3 is 27.6% with a relative standard deviation of 64.1 ppt
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1: Pb (NO3) 2 (aq) + CaCl2 (aq) PbCl2 (aq) + Ca (NO3) 2 (aq) (double displacement reaction) According to the solubility guidelines lead (II) chloride (PbCl2) is a possible precipitate. This is because even though most chlorides are soluble‚ lead chloride is considered insoluble (p.2‚ Lesson 17). Step 2: PbCl2 ↔ Pb2+ + 2Cl- Q = [Pb2+] [Cl-] 2 Step 3: Ksp = 1.2 x 10-5 (from table 17.1‚ p.5) Step 4: V2 = 20.0 mL (volume of Pb (NO3)2) + 45.0 mL (volume of CaCl2) = 65.0 mL C2
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ratio NaCl : Na2CO3 = 2 : 1 (1) mass ratio NaCl : Na2CO3 = 117 : 106 = 1 : 106/117 (1) 546 kg NaCl produces 546 × 106/117 (1) = 495 kg Na2CO3 (unit required) (1) or moles NaCl = 546000/58.5 = 9333 (if 9.33‚ allow 3 max) (1) moles NaHCO3 = moles NaCl = 9333 (1) moles Na2CO3 = ½ moles NaHCO3 = ½ × 9333 = 4667 (1) mass Na2CO3 = 4667 × 106 = 495 kg (unit required) (1) or mass ratio NaCl: NaHCO3 = 58.5 : 84 (1) mass NaHCO3 = 546 × 84/58.5 = 784 kg (1) mass ratio NaHCO3 : Na2CO3 = 168 : 106
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chemical (primary standard) for the preparation of a standard solution. Standard Solutions are critical in chemistry because you need to have solutions with an EXACT known concentration and volume. Chemicals/Materials: solid sodium carbonate (Na2CO3) distilled water Apparatus: 250cm3 volumetric flask 250cm3 beaker Glass stirring rod Weighting boat or aluminium foil Dropping pipette Electronic scales to 2 DP Health and safety: Sodium carbonate powder may irritate the lungs if
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Name Naza Moore ID# 24120389 Lab# 2 Lab instructors Alecia Palmer and Donald Burke Course Instructor Maureen Wilson Lab Title Preparation of cyclohexene from cyclohexanol Aim Preparation of an Alkene by dehydration of an alcohol in the presence of a catalyst. Calculate the percentage recovery of products. Test for purity and identification of products. Abstract Cyclohexene and cyclohexanol are both colourless aromatic compounds. The major difference between the two is the presence
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significance of knowing the limiting reactant is high. In order to increase the percent yield of product‚ increasing the limiting reactant‚ possibly‚ is the most effective. In this experiment we were able to calculate limiting reactants from the reaction of CaCl2. 2H2O + K2C2O4.H2O(aq). As a group‚ we obtained our salt mixture of calcium chloride and potassium oxalate‚ and weighed the mixture. We were able to make an aqueous solution from the mixture and distilled water. We boiled and filtered off the solution
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