8th Maths Practice Paper-1 1. An altitude of a triangle is 5/3 of its corresponding base. If the altitude were increased by 4cm and the base decreased by 2cm‚ the area of the triangle would remain the same. Find the base and altitude of the triangle. 2. Some toffees are bought at the rate of 11 for Rs10 and same numbers are bought at the rate of 9 for Rs 10. If the whole lot is sold at one rupee per toffee‚ find the gain or loss percent. 3. Chandu purchased a watch at 20% discount
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potatoes reacting with Hydrogen Peroxide. In particular I will investigate the effects of changing the surface area of a potato when added to Hydrogen Peroxide. This is because‚ when increasing the surface area of the potatoes it will increase the rate of reaction because there will be more surface area on which particles from the potato and the Hydrogen Peroxide will collide on‚ and with more surface area there would be more particles carrying kinetic energy‚ and by carrying more kinetic energy the chance
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Background Information Surface area will increase the speed of reaction as the greater the surface of the solid reactants‚ the more particles are required to expose and ‘cover’ the capacity of the solid. Increased surface area results in an increased chance of collisions between reactant particles. Since the collisions become more frequent and abundant‚ the rate of reaction increases. Aim The aim of the experiment is to see if a greater surface area of a dissolvable tablet creates a faster or
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Planning Aim To determine how the surface area of the tablets affects the rate of the reaction. To determine which form of tablets gives the biggest surface area resulting in the fastest reaction rate. Investigation question: What is the relationship between the total surface area of the tablets and the rate of the reaction? Hypothesis: The rate of reaction will be the fastest when the tablets crushed into powder as there is a bigger total surface area resulting in more effective collisions
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[Type text] [Type text] [Type text] _An experiment on the effect of surface area to volume ratio on the rate of osmosis of Solanum tuberosum L._ BACKGROUND A cell needs to perform diffusion in order to survive. Substances‚ including water‚ ions‚ and molecules that are required for cellular activities‚ can enter and leave cells by a passive process such as diffusion. Diffusion is random movement of molecules in a net direction from a region of higher concentration to a region of lower concentration
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The Effects of Surface Area to Volume ratio in Agar Introduction: What is an efficient way to maximize mass but minimize diffusion time in cell? Answer: An efficient way to maximize mass but minimize diffusion time in a cell is to increase its surface area. If you increase the surface area of a cell relatively to its volume‚ then the diffusion time will decrease. Materials: Agar cubes‚ bromothymol blue- pH indicator‚ vinegar‚ ruler‚ spatula‚ beaker. Methods: I used agar cubes as cell models
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Purpose: The purpose of this experiment is to determine how the surface area of CaCO3(s) affects the rate of reaction by measuring the volume of CO2(g) produced with time. Background: When solid reactants are mixed with liquid reactants only the particles on the surface of the solid will have direct contact‚ or collide‚ to the other liquid reactant particles. When there is more surface area there will be more solid particles exposed to collide
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of Changing the surface area on the Rate of Reaction? By : 22/10/2013 The effect of changing the surface area on the rate of reaction? Unit Question: Should we speed things up or slow them down? Hypothesis: According to collision theory‚ should the surface area increase the amount of collisions increase increasing the rate of reaction. Therefore‚ my hypothesis is that when the surface area increases the rate
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Materials: Metric ruler‚ razor blades‚ potato pieces‚ paper towels‚ iodine Purpose: to identify why cells are so small. Hypothesis: Make a statement as to which potato cubes will diffuse the closer to the center of a cell (small‚ medium‚ large. __________________________________________________________________________________________________________________________________________________________________________ Dimensions For Experiment 3 Cubes with sizes A) 0.5 cm B) 1.0 cm C)
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Surface Area to Volume Ratio and the Relation to the Rate of Diffusion Aim and Background This is an experiment to examine how the Surface Area / Volume Ratio affects the rate of diffusion and how this relates to the size and shape of living organisms. The surface area to volume ratio in living organisms is very important. Nutrients and oxygen need to diffuse through the cell membrane and into the cells. Most cells are no longer than 1mm in diameter because small cells enable nutrients and oxygen
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