concurrently on a point. As the angle between these forces increases from 0° to 90°‚ the magnitude of their resultant (1) decreases (2) increases (3) remains the same 2. A car increases its speed from 9.6 m/s to 11.2 m/s in 4.0 s. The average acceleration of the car during this 4.0-second interval is (1) 0.40 m/s2 (3) 2.8 m/s2 (2) 2.4 m/s2 (4) 5.2 m/s2 3. What is the speed of a 2.5-kilogram mass after it has fallen freely from rest through a distance of 12 m? (1) 4.8 m/s (3) 30. m/s
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| We found the average by using the formula (Trial 1 +Trial 2 + Trial 3)/3‚ and example would be (0.4663+0.454+0.4664)/3 = (1.3867)/3 = 0.4622 seconds. Graphs - The graphs (stapled on the back) all display that the ball moves at a constant acceleration. 4 book x-t graph: P= 32.38cm/s2 (t) + 6.012cm 7 book v-t graph: V= 52.19cm/s2 (t) + 54.74s 7 book x-t graph: P= 55.09cm/s2 (t) + 4.948cm 4 book v-t graph: The position vs. time graphs’ (x-t) slopes represent velocity. Obviously‚ 7 books
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object moving with a constant acceleration can certainly slowdown‚ But can an object ever come to a permanent halt if its acceleration truly remains constant? Explain. -An object can never come to a complete stop if its acceleration remains constant because even if the velocity reaches zero‚ it will just continue‚ probably in the opposite direction #2 An airliner reaches its take off speed of 334 m/s from rest in 35.2 s. What is the magnitude of its average acceleration? -D=vt D=334m/s(35.2s)
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skateboard out of his way. Calculate the initial acceleration A solo arctic adventurer pulls a string of two toboggans of supplies across level‚ snowy ground. The toboggans have masses of 95kg and 55kg. Appling a force of 165N causes the toboggans to accelerate at 0.61m/s2. Find the tension in the rope attached to the second toboggan. A 75kg man is standing on a scale in an elevator when the elevator begins to descend with an acceleration of0.66 m/s2. What is the reading on the scale while
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Unit 1 HW 16.2: Acceleration 2 Name: Date: Period: UNIT I Acceleration 2 The problem v vs t graph Solution 1. A poorly tuned Yugo can accelerate from rest to a speed of 28 m/s in 20 s. a) What is the average acceleration of the car? b) What distance does it travel in this time? a = (28-0m/s)/20s = 1.4 m/s/s x = 1/2at2 = ½(1.4)(20)2= 280m 2. At t = 0 a car has a speed of 30 m/s. After 6 s‚ its speed is 15 m/s. What is its average acceleration during this time interval
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Constant Acceleration‚ Velocity and Displacement On A Downward Ramp 3/3/2014 Purpose: To determine the velocity and acceleration of an object at different positions going down a ramp at four different angles. Hypothesis: If an object is accelerating at different angles then the larger angles will always have the largest acceleration. Materials: Ramp Miniature car Ticker Machine Masking tape Ticker tape Carbon paper Power supply Ruler Procedure: 1. A ramp
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measured for various initial angles‚ and also calculated by applying the theory for motion with constant acceleration. For further background information‚ refer to the sections in your textbook on projectile motion and motion with constant acceleration. THEORY For a given initial velocity‚ v0 ‚ and initial position‚ s0 ‚the position of a particle‚ s‚ as a function of time‚ undergoing constant acceleration‚ a is given by sr = sr 0 + vr 0 t + 12 ar t 2 ( 1 ) This is a vector equation and can be broken up
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Physics C-110 Module 1 Chapter 1 1. What is science? Science is a body of knowledge that is ever changing. It is made up of not only facts but also theories that are made up of well-tested hypotheses. 2. Distinguish among the scientific fact‚ hypothesis‚ law and theory As stated above‚ a theory is made up of well-tested hypotheses‚ which in themselves are well educated guesses yet to be proven. A fact is something that can change over time even though it was agreed upon by knowledgeable
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(the distance between the two deflecting plates)‚ and (the distance from the second plate to the coordinate screen–on which the electron’s deflection would be measured). The total displacement‚ is equal to the displacement caused by vertical acceleration () while traveling through
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Projectile Motion Lab Report Objectives: This laboratory experiment presents the opportunity to study motion in two dimensions‚ projectile motion‚ which can be described as accelerated motion in the vertical direction and uniform motion in the horizontal direction. Procedures and Apparatus: |Rubber Ball |White sheets of papers | |Metal Track |Water | |Books |Table | |Meter-stick
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