Incline Lab
Purpose – The purpose of this experiment was to find how position and time are related to a ball on an incline. Data –
7 Books
X (cm)| Trial 1 (s)| Trial 2 (s)| Trial 3 (s)| Average (s)| 10| 0.336| 0.3654| 0.3434| 0.3479|
15| 0.3952| 0.4262| 0.43| 0.4171|
50| 0.9127| 0.8846| 0.8936| 0.8971|
75| 1.1257| 1.1178| 1.1322| 1.1252|
100| 1.320| 1.2788| 1.2979| 1.2989|
125| 1.4924| 1.4966| 1.4766| 1.4885|

We found the average by using the formula (Trial 1 +Trial 2 + Trial 3)/3, and example would be (0.4663+0.454+0.4664)/3 = (1.3867)/3 = 0.4622 seconds. Graphs - The graphs (stapled on the back) all display that the ball moves at a constant acceleration. 4 book x-t graph: P= 32.38cm/s2 (t) + 6.012cm

7 book v-t graph: V= 52.19cm/s2 (t) + 54.74s
7 book x-t graph: P= 55.09cm/s2 (t) + 4.948cm
4 book v-t graph:
The position vs. time graphs’ (x-t) slopes represent velocity. Obviously, 7 books will have a higher velocity than 4 books, thus having a larger slope (32.38cm/s2 vs. 55.09cm/s2). The y-intercept represents the place where we started the ball on the ramp. The velocity vs time graphs’ (v-t) slopes represent acceleration. To find instantaneous velocity, you have to find the slope of all the points on the v-t graph and use the slopes of all the points as the points in the acceleration vs. time graph. Conclusion – In this lab I have learned that an object going down an incline will accelerate at a constant rate and moves faster every second. The position vs. time squared graphs’ equation is ½ the slope of the acceleration vs. time graph because you have to use time...

...
Cart on an InclineLab
Kennedy Van Allen
SPH 4U1
February 20, 2014
M. Reid
Purpose: To determine both qualitative and quantitative properties of the motion of a cart on an inclined plane on position vs. time, velocity vs. time and acceleration vs. time graphs.
Question: Which properties of the cart’s motion can be determined from examining each of the three graphs?
Hypothesis: The predictions on the type of motion demonstrated by the cart-qualitatively- are shown below.
Materials:
Laptop computer
Motion sensor equipment
Dynamic cart and track
Procedure
1. Set up all equipment.
2. Roll the cart up the incline toward the sensor and record the data for all three graphs.
3. Carefully analyze the graphs to determine which information can be pulled off which graph.
Observations:
Discussion:
1. In the first graph, the motion demonstrated by the cart begins with a leftward, negative velocity, moving from a fast velocity to a slow one. This is then mirrored at the 3s mark where the cart moves away from the motion sensor and demonstrates a positive, changing velocity and acceleration.
In the second graph, the motion demonstrated by the cart begins with a rightward, fast, negative velocity, gradually becoming slower as it approaches the 3s mark. From there, it...

...Lab 1, problem 3: Motion Down an Incline
Shaoren Yuan
October 5, 2013
Physics 1301W, professor: Dr. Zudov, TA: David
Abstract
The processes of a cart rolling up and returning back along a track were recorded, and the processes (motion of the cart.) were described as equations. Also, we calculated the accelerations of every stage (aup, adown and ahighest). Then the relationship among aup, adown and ahighest was concluded. Finally, the acceleration was measured and was proved from data.
Introduction
If there is a car launched from the bottom of an incline and it goes up until reaching the highest point, then it reverses its direction. To ensure the safety under this circumstance, the accelerations of every stage need to be measured in order to study the relationship among them. Meanwhile, we need to know which acceleration is the biggest one. This real case now can be simplified as 1-dimensional motion in the experiments. During the lab, the MotionLab&VideoRECOREDER was used to record the motion of the cart. After that, the accelerations were gained by calculating the slope of Velocity VS. Time graph. The accelerations and the relationship among them in every stage are gained from the graph.
Prediction
It was predicted that the acceleration would be a constant, as long as the angle, θ, between the track and the desk did...

...Experiment 1.7: Graphical Analysis of Motion
Introduction
To graphically analyze motion, two graphs are commonly used: Displacement vs. Time and Velocity vs. Time. These two graphs provide significant information about motion including distance/displacement, speed/velocity, and acceleration. The displacement and acceleration of a moving body can be obtained from its Velocity vs. Time graph by respectively finding the area and the slope of the graph.
Data Tables – Part I
Displacement (m) Time (s)
0.10 m 0.37 s
0.20 m 0.586 s
0.30 m 0.761 s
0.40 m 0.907 s
0.50 m 1.041 s
0.60 m 1.147 s
0.70 m 1.263 s
0.80 m 1.351 s
0.90 m 1.439 s
1.00 m 1.597 s
1.10 m 1.646 s
1.20 m 1.779 s
1.30 m 1.956 s
Part II
Main Photogate at __(m) Time (s) Instantaneous Velocity (m/s)
0.30 m 0.098 s 0.41 m/s
0.40 m 0.072 s 0.55 m/s
0.50 m 0.06 s 0.67 m/s
0.60 m 0.053 s 0.75 m/s
0.70 m 0.047 s 0.85 m/s
0.80 m 0.043 s 0.93 m/s
0.90 m 0.042 s 0.95 m/s
1.00 m 0.038 s 1.05 m/s
1.10 m 0.038 s 1.05 m/s
1.20 m 0.041 s 0.98 m/s
1.30 m 0.049 s 0.82 m/s
1.40 m 0.05 s 0.8 m/s
1.50 m 0.055 s 0.72 m/s
Part III
Estimated area
Velocity vs. Time graph
From t=0s to t=0.8s
0.49 m
Slope @ T= 0.8 s
Displacement vs. Time
= 0.6 m/s
Velocity vs. Time
= 0.3 m/s2
(Work shown on graph paper)
Summary Questions
1) Describe the meaning of the slopes of the graphs you obtained in Part...

...Abstract
In this lab experiment the range equation will be used to calculate range of the launched rocket, initial velocity and distance traveled. Various projectiles will be tested at various angles and table heights for experiment one. Results will be compared to initial calculations. Despite human error and calculation error, the results still correlated with the hypothesis.
Introduction
Background
Acceleration is constant at 9.8 m/s2 because of the force of gravity. For experiment 1 the velocity will be calculated by measuring “x” and “y” and using the combined x & y equations to solve for Vo. Vo= x⌠g/2y. For experiment 2 the range equation for distance x=R is applicable since the launch and landing elevations are the same. R=(Vo2sin2ᶿ)/g
Objective
The objective of experiment one is to determine the distance a falling object will travel when the launch height is changed. The objective of experiment two is to observe the distance, x=R, a projectile will travel when the launch angle is changed. Acceleration is constant at 9.8 m/s2 in all the experiments due to gravity.
Hypothesis
Experiment 1: When the height is raised, the marble will have more time to continue traveling at its initial velocity while the gravitational force is acting upon it, increasing the distance the marble travels while falling.
Experiment 2: The range of the rocket will decrease as the angle launched moves away from 45 degrees.
Experiment
Materials:
Experiment 1:...

...Lab #1: Uniformly Accelerated Motion
This is an example of a laboratory report. For a detailed description of how to complete a lab report,
consult the laboratory manual. When writing your lab reports, use your own words. Do not copy from this
sample or from the laboratory manual.
Your name:
Lab partners’ names:
PHYS 1.2 L
Section:
Instructor: Prof. Gelman
Date:
Objectives
To investigate the properties of a uniformly accelerated cart moving down an inclined
plane. To measure the instantaneous velocity and to determine the acceleration of the
cart from the slope of the velocity-time graph.
Theoretical Background
A cart moving down a smooth incline speeds up. This is a simple case of a uniformly
accelerated motion in one dimension. The rate of change of velocity is constant or
uniform. The rate of change of velocity is called acceleration. To determine the
acceleration, one needs to measure the velocity at two different points along the incline,
v and v0, and to measure the time t it takes a cart to move between the two points. Then
the acceleration is given by,
The SI unit for the acceleration is 1 m/s2. This equation can be rearranged as,
This equation gives the future velocity v in terms of the initial velocity v0, acceleration a
and elapsed time t. According to this equation, the velocity-time graph for uniformly
accelerated...

...vector until the ball moves the opposite direction or stops. The blue vector decelerates at a certain point on the path while the green vector continues to move with the direction of the ball. Velocity and acceleration increase as the ball moves rapidly in one direction. When the ball changes direction, the acceleration decreases the opposite direction while velocity follows the movement of the ball.
6) Now click on ‘Circular’ on the bottom. Describe the motion of the ball and the behavior of the two vectors. Is there a force on the ball? How can you tell? Be detailed in your explanations.
The ball is moving in a circulation motion. The vectors remain constant even though there is still force exerted on the ball. Since the ball is accelerating towards the center, the ball is experiencing net force. If there was not force pushing the ball, the ball would not be moving in a circle.
7) Click on ‘Simple Harmonic’ on the bottom. Based on the behavior of the ball and the vectors, write a definition of Simple Harmonic Motion.
The green vector is demonstrating the direction of the ball. The blue vector is demonstrating the acceleration of the ball. The ball is moving on a linear path around an equilibrium point. The acceleration is always moving toward the equilibrium point and directly proportional to the displacement of the ball from the equilibrium point....

...groove that imparts motion to a follower
➢ Cams are very important and frequently occurring elements in many types of machines – especially AUTOMATIC MACHINES
➢ Cams are the heart of such automatic devices as automatic devices as automatic machine tools, record changers, mechanical calculators, cash registers, and many other devices.
Types of Cams:
Motions Used for Cam Followers:
➢ Themotion of the follower is of primary interest in the analysis of existing cams or in the design of new cams.
➢ It is easier to analyze the motion of cam followers if their motion is plotted as a graph often referred to as DISPLACEMENT DIAGRAM
A. Displacement Diagram
B. Motions that are most commonly used:
1. Uniform Velocity (straight line) motion – UVM
2. Simple Harmonic Motion – SHM
3. Uniformly Accelerated motion (Parabolic Motion) – UAM or PM
4. Modified Uniform-Velocity Motion – MUVM
a. Arc method – MUVM-Arc
b. Uniform Acceleration Method – MUVM-UAM
5. Cycloidal Motion – CM
A. Uniform Velocity Motion (Straight Line Motion)
If the follower is to move with uniform velocity, its displacement must be the same for equal units of time....

...Name Noah Meador___ Motion in 2D Simulation
Go to http://phet.colorado.edu/simulations/sims.php?sim=Motion_in_2D and click on Run Now.
1) Once the simulation opens, click on ‘Show Both’ for Velocity and Acceleration at the top of the page. Now click and drag the red ball around the screen. Make 3 observations about the blue and green arrows (also called vectors) as you drag the ball around.
1. The green line points in the direction that the ball is going to go
2. The blue line changes the direction it points.
3. The blue line also changes size depending on the speed
2) Which color vector (arrow) represents velocity and which one represents acceleration? How can you tell?
The green line represents velocity because it points in the direction. The blue line is acceleration because as the ball is no longer accelerating it points in the opposite direction.
3) Try dragging the ball around and around in a circular path. What do you notice about the lengths and directions of the blue and green vectors? Describe their behavior in detail below.
When the ball is in a circular path the blue line points towards the middle of the circle, while the green follows the circumference.
4) Now move the ball at a slow constant speed across the screen. What do you notice now about the vectors? Explain why this happens.
The blue line does not appear because when there is a constant speed there is no longer acceleration.
5) What happens to the vectors when you...