Treatment of Results 1) What is the role of 0.25M sucrose as the medium for the fractionation process? Cold sucrose does not chemically react with cell organelles Due to the density and size of sucrose molecules‚ it is able to suspend pellets for configuration while providing a solution where the centrifugation can be better balanced Sucrose offers a liquid medium in which less dense fractions can be poured off as supernatant at the end of each centrifugation step. 0.25M sucrose solution
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of an unknown microbe by observing its reactions to a barrage of chemical and physical tests. Different microorganisms react in different ways‚ due to their function‚ digestibility‚ morphology‚ chemical make-up and other details. By observing the responses to these tests performed in a particular sequence‚ some can be eliminated as possibilities and others require further investigation. Materials and Methods: A stock culture‚ labelled 25‚ was stored at room temperature (in the lab desk). A transfer
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Course: Science / EVS Topic: Teeth and Microbes Class Subject Language Subject Matter Expert(s) Targeted Length III Science / EVS English What is the purpose of this document? The purpose of this document is to finalize the content that will be displayed on each screen‚ and the visuals that will be used for the content. What are you expected to do? You are expected to check the document for the following facts: • Content accuracy • Visual relevance • Validity
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Introduction: During this unknown lab report various test were performed to differentiate microbes from each other and to compare metabolic and biochemical process. The gram stain distinguishes between Gram positive and Gram negative bacteria based on the composition of the cell wall. The Gram stain procedure distinguishes between Gram positive and Gram negative groups by coloring these cells red or violet. Gram positive bacteria stain violet due to the presence of a thick layer of peptidoglycan
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CHM 131(GENERAL CHEMISTRY) TITLE: BASIC LABORATORY TECHNIQUES (EXPERIMENT 1) NAME: MURSYIDA BINTI MOHD DAKROH(ID: 2015883226) LAB PARTNERS:NABILA SOFEABINTI ZAWAWI (ID: 2015850932) :NUR ANISLYANA BINTI TAMAM (ID: 2015832718) :NUR AUNI BINTI MOHD RADZIFF (ID: 2015863252) LECTURER NAME: MADAM DYIA SYALEYANA BINTI MD.SHUKRI PROGRAM: RAS1201B DATE OF EXPERIMENT: 30 JUNE 2015 OBJECTIVE 1. To learn the qualitative and quantitative aspect
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oasis of life that resides around the earth ’s nourishing thermal vents. Here‚ a vast community of organisms thrive under very harsh circumstances‚ and most importantly‚ in the absence of life-giving light. How is this possible? Chemoautotrophic microbes. Chemoautotrophic bacteria are the primary producers on the ocean floor‚ where light cannot reach. Unlike most organisms‚ these bacteria do not need carbohydrates‚ vitamins‚ protein‚ and sugar to create energy‚ and ultimately to survive. Instead
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as well. B. Discuss the temperature requirements of the organisms (you grew) in this lab. Both Staphylococcus epidermis and Lactobacillus acidophilus are mesophiles. Mesophiles grow best between 25- 45 degrees Celsius (Alonzo‚ n.d.). In this experiment both bacteria have grown easily at a maintained room temperature of 26 Celsius. C. Discuss under what conditions you would want to control the growth of microbes.
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Lab #4: The Immune System Purpose: The purpose of this lab was to perform and understand the procedures of conducting an ELISA test to determine whether a particular antibody is present in a patient’s blood sample through a virtual simulation. Hypothesis: If I successfully complete this lab‚ I will then understand how to perform an ELISA test‚ the purpose an ELISA test‚ and also how to interpret the results of this test. Materials and Procedures: Materials: Howard Huges medical
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Name: LaGarrian Harris|Date: 2/10/2013| Exp 2: Laboratory Techniques & Measurements|Lab Section: 1411| Data Tables: Length Measurements Object Measured|Length in cm|Length in mm|Length in m| Key|5.2|52|0.05| CD|12.0|120|0.12| Spoon|15.0|150|0.15| Warm Temperature Measurements Hot tap water temperature __44.0 ˚?C 111.2˚?F 317.15_K Boiling water temperature at 5 min __100_˚?C _212 ˚?F 373.15_K Cold Temperature Measurements Cold tap water temperature _19.0_˚?C _66
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In the unknown identification labs‚ we have identified our unknown as Pseudomonas aeruginosa. Pseudomonas aeruginosa is Gram negative and rod shaped that we found to be motile in the lab. Our strain of P. aeruginosa formed colonies that were round in shape and had scalloped margins on nutrient agar. On our agar slant‚ the P. aeruginosa colonies had a filiform appearance on the edges. I think we correctly identified our unknown as P. aeruginosa because we performed several different tests‚ eleven
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