again receive electrons and plate that metal. Lemon Cell While there are many electrolytes which will cause this reaction‚ citric acid is frequently used as a demonstration because it occurs naturally in citrus fruits. The two metals often used are zinc‚ as in a galvanized nail‚ for the anode and copper‚ as in a penny‚ for the cathode. A lemon can be used as both the container and the source of citric acid. If a slit is made in one end of the lemon‚ the penny can be inserted about half-way. A galvanized
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Theory What is rust? Rust is the common name of a compound‚ iron oxide. Iron oxide‚ the chemical Fe2O3‚ is common because iron combines very readily with oxygen -- so readily‚ in fact‚ that pure iron is only rarely found in nature. Iron (or steel) rusting is an example of corrosion -- an electrochemical process involving an anode (a piece of metal that readily gives up electrons)‚ an electrolyte (a liquid that helps electrons move) and a cathode (a piece of metal that readily accepts electrons)
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resulting in current. The potato does not participate directly in the reaction. It is there rather as an electrolyte to facilitate the transport of the zinc and copper ions in the solution‚ while keeping the copper and zinc electrodes apart. The potato contains phosphoric acid (H3PO4)‚ which facilitates the electro-chemical reaction of zinc with copper. Zinc is an active metal‚ which reacts readily
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e– Ag(s) Overall equation: Fe(s) + 2Ag+(aq) Fe2+(aq) + 2Ag(s) b Oxidation: Mg(s) Mg2+(aq) + 2e– Reduction: Cu2+(aq) + 2e– Cu(s) Overall equation: Mg(s) + Cu2+(aq) Mg2+(aq) + Cu(s) c No reaction. Iron cannot displace the more reactive zinc from solution. d Overall equation: Cu(s) + 2Ag+(aq) Cu2+(aq) + 2Ag(s) Review Exercise 9.2 1 a –2 b 0 c +4 d +6 e +6 f –2 2 a NH3‚ ammonium salts b N2 c N2O d NO e HNO2‚ N2O3‚ nitrites f HNO3‚ nitrates 4 a Cr2O72–(aq) + 8H+(aq) +
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Section 12 1. Introduction: This lab focused on showing the reaction that takes place between zinc and iodine using only deionized water instead of acetic acid (or vinegar) as we did in the previous lab by adding acetic acid to zinc iodide. The purpose of this lab was to see how water created the reaction and another compound or precipitate. Focus Question: Zn(OH)2 was the product when zinc and iodine were reacted without the presence of acetic acid in the water. Confidence Report: I am confident
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full)‚ and celestite (strontium mineral 50% of globe output) 2nd in fluorspar (14% of world output) 4th in arsenic and graphite fifth in molybdenum 1 with the leading ten in barite‚ cadmium‚ gypsum‚ mine direct‚ manganese ore‚ salt‚ sulfur‚ and mine zinc as well as inside the very best 15 in mine copper‚ cement‚ gold‚ and crude metal (secondlargest producer in Latin The usa). India’s 4th‚ fifth‚ and sixth foremost industries in 2002 were generating iron and steel‚ oil‚ and mining‚ correspondingly‚
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products and the number of moles of reactants and products. PROCEDURE Polish the zinc strip using steel wool and then determine its mass. Allow the strip to sit in lead acetate for approximately an hour and observe the changes in the zinc strip. The zinc starts to accumulate particulate matter (lead particles) on its surface. This is cause by the chemical reaction that occurs between the lead acetate and the zinc strip. The strip is then rinsed in water and acetate and then dried. The particles
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60% yield. A + B C + D C + E F What is the yield of F? answers 1 | 1.71 x 10-2 nm3 | 2 | 0.860 g carbon dioxide | 3 | 9.99 g iron III chloride | 4 | x = 1 | 5 | 70% lead II oxide | 6 | 7.42 g Zn and 27.64 g zinc iodide | 7 | 79 % yield | 8 | 48% yield
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of mineral processing methods. Gravity separation is also used for sorting iron ore and manganese ore‚ is also used to deal with some non-metallic ore‚ such as asbestos‚ diamond‚ kaolin. Flotation processing non-ferrous metals such as copper‚ lead‚ zinc ore‚ gravity separation method of pre-sorting to remove coarse gangue or wall rock to reach the initial enrichment. Gravity concentrator new technology is the formation of the joint operations of the fine sieve and magnetic agglomeration process
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post 1982 penny is 2.5 grams‚ and the percent of zinc is 97.5% leaving only 2.5% copper. The amount of Zinc in a post 1982 penny is 2.437 grams‚ and the amount of copper is 0.062 grams. Along with all of this we must know the amount of moles of each. To find the amount of moles we must solve for them: Zinc = (2.4375g / 1) X (1 / 65.38g) = 3.73 X 10-2 moles Copper = (0.0625g / 1) X (1 / 63.546g) = 9.835 X 10-4 moles The balanced equation for zinc and HCl is Zn + 2HCl = 1H2 + 1 ZnCl2 H=1‚ Zn = 65
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