crystallization indicates that the solution has become statured. This means that at each temperature recorded the solution contains the maximum quantity of solute that can be dissolved in that amount of solvent. Standard solubility table of Ammonium chloride Solubility g/100gH2O Temperature /°c/±0.1 60‚3 71‚3 55‚5 59‚3 51.3 52‚4 47‚7 47‚2 43‚4 41‚8 Uncertainties and errors of volume and temperature VOLUME H2O/ml/±0.05 Percentage uncertainty/% Temperature/°c/±0.1 Percentage
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Q. 1. During the electrolysis of molten lead bromide‚ which of the following takes place : A : Bromine is released at the cathode. B: Lead is deposited at the anode. C : Bromine ions gain electrons. D: Lead is deposited at the cathode. Ans : - D. Q. 2. Here is an electrode reaction : Cu → Cu2+ + 2e-. [i.e. Cu- 2e- →Cu2+]. At which electrode(anode or cathode) would such a reaction take place. Is this an example of oxidation or reduction. Ans : - At anode. Oxidation. Q. 3. A solution contains
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Erlenmeyer flask while it was submerged in cold water? What are the possible sources of errors in this experiment? B. Graham’s Law of Diffusion Distance Travelled by Ammonia in cm (dNH3) | | Distance Travelled by Hydrogen Chloride in cm (dHCl) | | Molar Mass of Hydrogen Chloride in g/mole (MHCl) | | Experimental Molar Mass of Ammonia in g/mole (MNH3) | | True Molar Mass of Ammonia in g/mole (MNH3) | | Percent Error | | Show the computations for the following: 1. Experimental
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formula. To determine the molecular formula of a compound‚ we need to know both the empirical formula and the molar mass of the compound. Benzene‚ for example‚ has an empirical formula of CH. In a molecule of benzene‚ the number of carbon atoms (C) and hydrogen atoms (H) are the same. The molar mass of benzene is 78.11 g/mol. We can determine the molecular formula of benzene by first calculating the molar mass of the empirical formula‚ which is 13.02 g/mol. We then determine the number of empirical units
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is added to sodium metal to make sodium chloride‚ the sodium has donated an electron and the chlorine has accepted an electron to become a chloride ion or an attached chlorine. If a compound divides into elements in a decomposition‚ a decomposition reaction could be a redox reaction. The electrolysis of water is a redox reaction. With a direct electric current through it‚ water can be separated into oxygen and hydrogen. H2O H2 + O2 The oxygen and hydrogen in the water are attached by a covalent
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an isomer‚ differs from (1^H) in that: 3^H has 2 more neutrons than 1^H Nitrogen has 7 electrons and thus can form a maximum of ___ covalent bonds with other elements 3 Carbon has 6 electrons while hydrogen has 1 electron. How many covalent bonds can form between a carbon atom and hydrogen atoms 4 In the lab you are culturing human cells in order for the cells to survive they must be cultured in a solution containing 25 mM glucose. You must make 500 ml of this solution. First‚ calculate
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Amrita VISHWA VIDYAPEETHAM (University established u/s 3 of UGC Act 1956) Amrita Entrance Examination – Engineering PHYSICS‚ CHEMISTRY & MATHEMATICS Question booklet Version Code Question booklet no. Number of pages Number of questions Time 120 : 3 hrs Max. Marks : 360 Registration number Name of the candidate Signature of the candidate INSTRUCTIONS TO THE CANDIDATES GENERAL 1. Any malpractice or attempt to commit malpractice in the examination hall will lead
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will dissolve in the hydrochloric acid to produce hydrogen gas. This is because magnesium is higher than hydrogen in the reactivity series. Therefore‚ when the two reactants are combined‚ a displacement reaction occus and the magnesium displaces the hydrogen‚ forming magnesium chloride and hydrogen gas. Mg (s) + 2HCl (aq) -> MgCl 2 (aq) + H 2 (g) Magnesium + Hydrochloric acid -> Magnesium Chloride + Hydrogen Aim The aim of this investigation is to observe
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Gases PURPOSE This experiment has two parts. The purpose of part A of the experiment is to determine the atomic mass of a metallic element whereas the purpose of part B of the experiment is to determine the rate of diffusion of both gases hydrogen chloride and ammonia by measuring the distances travelled by the two gases in the same time period. For part A the reaction of the metal with the aqueous acid is as follows: M(s) + n H3O+ -----> M+n(aq) + n/2 H2(g) + n H2O EQ.1
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The prescribed procedure produced nylon. The initial indication that nylon was being formed was through the combination of 0.02M of sebacoyl chloride in hexane and 0.05 M 1‚6 hexanediamine. Due to the fact there was an evident product formed after the combination of these two solutions‚ this simply shows that nylon was produced. The prescribed procedure produced nylon due to the fact that there was a present product of the reaction within the IR spectrum. The main peaks of frequency for the unknown
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