"Catalase facilitates the breakdown of hydrogen peroxide into water and molecular oxygen" Essays and Research Papers

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    In my coursework I will investigate about enzymes in potatoes reacting with Hydrogen Peroxide. In particular I will investigate the effects of changing the surface area of a potato when added to Hydrogen Peroxide. This is because‚ when increasing the surface area of the potatoes it will increase the rate of reaction because there will be more surface area on which particles from the potato and the Hydrogen Peroxide will collide on‚ and with more surface area there would be more particles carrying

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    Hydrogen and Points

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    unknown 3 (1 point) positive 6. unknown 4 (1 point) positive 1. List whether each of the following substances was positive or negative for starch‚ as indicated by using iodine. (7 points) 1. onion juice (1 point) positive 2. water (1 point) negative 3. cornstarch (1 point)positive 4. unknown 1 (1 point) negative 5. unknown 2 (1 point) positive 6. unknown 3 (1 point) positive 7. unknown 4 (1 point) negative 1. List whether each of the following

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    The Effect of Temperature on the Enzyme Catalase Stephen Francis Biology 183 Abstract This experiment was performed to determine the resultant effect of temperature change on the reaction between the enzyme catalase and hydrogen peroxide. This experiment was performed by measuring and comparing the amount of oxygen bubbles produced and the absorbance of the catalase and hydrogen peroxide solution over time at room temperature‚ 2°C‚ 50°C‚ and 60°C. The overall result of this experiment proved

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    of different concentrations of catalase on the production of oxygen and water through the breakdown of Hydrogen Peroxide. In this experiment paper disc where coated in varying concentrations of catalase‚ 0‚ 25‚ 50 75 and 100%. The time taken for the disc to float between two markers on the side of a glass was then recorded. This experiment demonstrates that the higher the concentration of enzyme used the greater the production of oxygen on the paper disc. The oxygen then produced on the disc gives

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    varying substrate concentration‚ and the effect of temperature on the rate of Enzyme-Catalase reaction. In experiment one (i.e. the effect of varying substrate concentration on the rate of enzyme-catalase reaction) we tested the hypothesis HA as substrate concentration increases‚ so will reaction rate until all active sites are bound. In experiment two (i.e. The effect of temperature on the rate of enzyme-catalase reaction) we tested the hypothesis HA as temperature increases‚ so will

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    of pH on catalase activity. Catalase by scavenging hydrogen peroxide to water and oxygen is an important enzyme of cell defense mechanisms against oxidative stress in all living organisms (Dat et al.‚ 2003). Cells use catalase because it is the most efficient enzyme as an antioxidative enzyme which lowers hydrogen peroxide or superoxide to accumulate to toxic levels in plant growth (Bowler et al. 1992). The formula that involves catalase as the enzyme is . pH is a measure of the Hydrogen ion concentration

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    Oxygen

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    Oxygen – Carbon dioxide Cycle The Carbon Dioxide- Oxygen Cycle relates to the relationship between Carbon Dioxide [CO2] breathing plants and Oxygen [O2] breathing life forms. All oxygen-breathing life forms take in Oxygen and exhale CO2. Plants take in the CO2 and use it in their photosynthesis process and in turn give off oxygen. The Carbon Dioxide-Oxygen Cycle is a continuously occurring process whereby animals inhale Oxygen and then exhale carbon dioxide‚ and plants use the CO2 and "exhale"

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    INTRODUCTION The enzyme catalase converts hydrogen peroxide (H2O2) to water and O2. The evolution of O2 causes bubbling. Thus‚ catalase-positive organisms that are mixed into hydrogen peroxide will cause bubbling (catalase-negative organisms will not). This test is good for distinguishing between Gram-positive cocci in chains (catalase negative) versus Gram-positive cocci in clusters (catalase positive). The coagulase test is used to differentiate Staphylococcus aureus from coagulase-negative

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    Hydrogen

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    Study of the first element – Hydrogen. Answer the following questions:- 1. Give a reason why hydrogen can be placed in group 1[IA] and group 17[vIIA] of the periodic table. 2. What similarities does it show with group 1[IA] and group 17[VIIA]. With special reference to valency electrons and ion formaton and examples. 3. How does hydrogen occur in the free and combined state? 4. Which metals react with cold‚steam and boiling water to form their respected oxides and hydroxides ? Give examples and

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    of hydrogen peroxide with a fixed mass of catalyst. A catalyst is a substance‚ which alters the speed‚ or rate of a chemical reaction but is chemically unchanged at the end of the reaction. The two factors that we can change are the temperature and the concentration. We chose to vary the concentration of hydrogen peroxide. The catalyst to speed up the reaction without affecting the result will be manganese oxide. Prediction: I predict that the higher the concentration of hydrogen peroxide‚ the

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