How Does Drop Height Affect The Amount Of Water Drop In Water
The splash is cause by sudden disturbance in liquid. For example if the ball is dropped into water, its energy will affect the water, causing some amount to splashed out. When the ball is released from a height, its initial potential energy combined with the gravitational energy form a kinetic energy, which transmitted to the water. So I will investigate the relationship of drop height of the ball and the amount of water splashed out.
Research question:
How does the volume of water splashed out depend on drop height of the ball?
Explanation for controlled variable:
The change in mass in ball will affect the kinetic energy as KE = mv2/2, so will use the same ball for all experiments.
Initial volume of the water will be also controlled using …show more content…
Using measuring glass, I measured the volume of the water after the splash. Before pouring water into the measuring glass, I removed the ball from the beaker.
9. Repeat 1-9 steps changing the drop height
I have done five trials for each drop height and considered the average value.
I subtracted from the initial volume of water in beaker the volume of water after dropping a ball in order to find out the volume of water splashed out.
Water splashed out = initial V – final V
To measure the drop height I used a common metric ruler, so uncertainty is ±0.05cm, which is indicated as horizontal bars in Graph 1.
To measure the volume of water, I used measuring glass with smallest division 5ml, so uncertainty is ±2.5ml
All points on the Graph seem to lie on a straight line. And the correlation coefficient of best-fit line is r = 0.9959. So we can assume that there is relationship between drop height of the ball and volume of water splashed out is very close to linear.
The slope of the best fit line is m = 1.423 ml/cm, which means that 1 cm increase in drop height will approximately increase 1.423 ml of water splashed out.
The minimum slope is mmin = 1.194 ml/cm and the maximum slope is mmax = 1.722 ml/cm.
Δm = (mmax = mmin)/2 = (1.722 – 1.194)/2 = 0.264
Research question:
How does the volume of water splashed out depend on drop height of the ball?
Explanation for controlled variable:
The change in mass in ball will affect the kinetic energy as KE = mv2/2, so will use the same ball for all experiments.
Initial volume of the water will be also controlled using …show more content…
Using measuring glass, I measured the volume of the water after the splash. Before pouring water into the measuring glass, I removed the ball from the beaker.
9. Repeat 1-9 steps changing the drop height
I have done five trials for each drop height and considered the average value.
I subtracted from the initial volume of water in beaker the volume of water after dropping a ball in order to find out the volume of water splashed out.
Water splashed out = initial V – final V
To measure the drop height I used a common metric ruler, so uncertainty is ±0.05cm, which is indicated as horizontal bars in Graph 1.
To measure the volume of water, I used measuring glass with smallest division 5ml, so uncertainty is ±2.5ml
All points on the Graph seem to lie on a straight line. And the correlation coefficient of best-fit line is r = 0.9959. So we can assume that there is relationship between drop height of the ball and volume of water splashed out is very close to linear.
The slope of the best fit line is m = 1.423 ml/cm, which means that 1 cm increase in drop height will approximately increase 1.423 ml of water splashed out.
The minimum slope is mmin = 1.194 ml/cm and the maximum slope is mmax = 1.722 ml/cm.
Δm = (mmax = mmin)/2 = (1.722 – 1.194)/2 = 0.264