Oscilloscope 1. Connect the function generator output to Channel 1 of the oscilloscope with a BNC-BNC cable as shown in Figure 1 below and turn on both instruments. Figure 1: Function Generator to Oscilloscope Connection 2. Select the Sine wave button of the function generator. Set the frequency to 1 kHz. 3. Select the Amplitude button on the function generator to set the output voltage. Adjust the voltage to 2 V peak to peak. 4. On the oscilloscope‚ set the Volts/Div knob
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AC Circuits. Oscilloscope Arjun Patel Group: 2 Partner: Hirbod B. Partner: Wonyoung J. PHY 114 Section 87725 TA: Hank Lamm November 3rd 2011 Abstract: The main goal of this experiment to Investigate the sine wave AC signal from signal generator using the scope and determine the relationships between the rms value and the amplitude of the voltage as well as the period and the frequency of the signal. The following are the results of the lab: T= 10-3seconds‚ Vo=1.4V ‚ 2% discrepancy
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APPLICATION NOTE AN014 Understanding FFT Windows The Fast Fourier Transform (FFT) is the Fourier Transform of a block of time data points. It represents the frequency composition of the time signal. Figure 2 shows a 10 Hz sine waveform (top) and the FFT of the sine waveform (bottom). A sine wave is composed of one pure tone indicated by the single discrete peak in the FFT with height of 1.0 at 10 Hz. Introduction FFT based measurements are subject to errors from an effect known as leakage. This effect
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Irms if i(t) = 50 + 40 sin wt amperes. 5. Calculate Irms if i(t) = 150 + 50 sin wt + 25 sin 2wt amperes. 6. The effective value of i(t) = 100 + A sin wt is known to be 103.1 amperes. Determine the amplitude A of the sine term. 7. If a half-wave rectified sine wave of voltage has an effective value of 20 V. What is its average value? 8. Calculate Iave and Irms for the waveform shown below. 9. Calculate Iave and Irms for the waveform of current below. 10. Determine
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showing the operation of QPSK modulation and demodulation. The transition from analog communication to digital has advanced the use of QPSK. Euler’s relation is used to assist analysis of multiplication of sine and cosine signals. A SPICE simulation is used to illustrate QPSK modulation of a 1MHz sine wave. A phasor diagram shows the impact of poor synchronization with the local oscillator. Digital processing is used to remove phase and frequency errors. Since the early days of electronics‚ as advances
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ANSWER: 8-4 Trigonometry Express each ratio as a fraction and as a decimal to the nearest hundredth. 1. sin A 3. cos A SOLUTION: The cosine of an angle is defined as the ratio of the adjacent side to the hypotenuse. So‚ ANSWER: SOLUTION: The sine of an angle is defined as the ratio of the opposite side to the hypotenuse. So‚ 4. tan A ANSWER: 2. tan C SOLUTION: The tangent of an angle is defined as the ratio of the opposite side to the adjacent side. So‚ ANSWER: 3. cos A SOLUTION:
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one-half the product of two of its side lengths and the sine of the angle. ______2. Given only the three sides of a triangle‚ there is insufficient information to solve the triangle. ______3. Given two sides and the included angle‚ the first thing to do to solve the triangle is to use the Law of Sines. ______4. The Law of Sines states that the ratio of the sine of an angle in a triangle to its opposite side is equal to the ratios of the sines of the other two angles to their opposite sides. ______5
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in circles‚ and proved theorems that are equivalent to modern trigonometric formulae‚ although they presented them geometrically rather than algebraically. Claudius Ptolemyexpanded upon Hipparchus’ Chords in a Circle in his Almagest.[7] The modern sine function was first defined in the Surya Siddhanta‚ and its properties were further documented by the 5th centuryIndian mathematician and astronomer Aryabhata.[8] These Greek and Indian works were translated and expanded by medieval Islamic mathematicians
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integrator. Theoutput of the third op amp is a sine wave (the integral of atriangular wave). 5 The sine wave output of the third op amp is fed into the fourth opamp‚ which is configured as an inverting amplifier. The output of this last op amp is also a sine wave but opposite in phase as itsinput. Advantage : y Circuit should be simple y It also cheap Dis advantage : y We can¶t properly recognize difference between sine andtriangular on simple CRO. C onclu si on
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field around the conductor or vice versa makes electrons move. When you have physically moved either the conductor or magnet in a complete 306-degree circle you have produced one sine wave or one complete cycle. The amount of time it takes to complete one cycle is referred to as a period. The frequency of an alternating sine wave is the amount of cycles per second. Frequency is measured in hertz. One hertz is equivalent to one cycle per second. The frequency coming out of your electrical plug at
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