M11/5/MATME/SP1/ENG/TZ1/XX 22117303 mathematics staNDaRD level PaPeR 1 Wednesday 4 May 2011 (afternoon) 1 hour 30 minutes iNSTrucTioNS To cANdidATES candidate session number 0 0 Examination code 2 2 1 1 – 7 3 0 3 Write your session number in the boxes above. not open this examination paper until instructed to do so. do are not permitted access to any calculator for this paper. You Section A: answer all questions in the boxes provided. Section B: answer all questions on the
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Alma Guadalupe Luna Math IA (SL TYPE1) Circles Circles Introduction The objective of this task is to explore the relationship between the positions of points within circles that intersect. The first figure illustrates circle C1 with radius r‚ centre O‚ and any point P. r is the distance between the centre O and any point (such as A) of circle C1. Figure 1 The second diagram shows circle
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generate an equation for the numerator of the fraction‚ the fraction data must be organized and graphed. The table below shows the relationship between the row number and numerator being relative to an exponential function as the sequence goes on. N(n+1)-Nn represents the equation for the graph that increases more evenly as the sequence advances. Using excel to graph the points and loggerpro to generate an equation‚ the general statement for finding the numerator N=0.5n2+0.5n‚ n having to be greater
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Lacsap’s Fractions IB Math SL SL Type 1 December 11‚ 2012 Lacsap’s Fractions: Lacsap is Pascal backwards and the way that Lacsap’s fractions are presented is fairly similar to Pascal’s triangle. Thus‚ various aspects of Pascal’s triangle can be applied in Lacsap’s fraction. To determine the numerators: To determine the numerator (n)‚ consider it in relation to the number of the row (r) that it is a part of. Consider the five rows below: Row 1
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IB Maths SL TYPE I Lacsap’s Fractions Portfolio Lacsap’s fraction Introduction: Lacsap’s fraction is a symmetrical triangle that has the following pattern in the first five rows The shape is similar to Pascal triangle. It has the same quantity of symmetrical triangle as Pascal triangle. And Lacsap is the inverse alphabet order of Pascal. These make me think about Pascal triangle and I made an assumption that elements in Lacsap triangle may have the same relationship as in Pascal triangle
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SL TYPE 1-LACSAP’S FRACTIONS * INTRODUCTION This investigation is going to do research patterns relates to the Lacsap’s Fractions. For its external structure‚ Lacsap’s Fraction is analogous to Pascal’s Triangle. Lacsap’s Fraction presents the way of generating and organizing the binomial coefficients. Within this investigation‚ the work is planning to be divided into two parts. In the first part‚ the content will relate to the pattern of numerators. In the second part‚ I am going to do the
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Diploma Programme Mathematics SL formula booklet For use during the course and in the examinations First examinations 2014 Published March 2012 © International Baccalaureate Organization 2012 Mathematical studies SL: Formula booklet 5045 1 Contents Prior learning 2 Topics 3 Topic 1—Algebra 3 Topic 2—Functions and equations 4 Topic 3—Circular functions and trigonometry 4 Topic 4—Vectors 5 Topic 5—Statistics and probability 5 Topic 6—Calculus
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In Lacsap’s Fractions‚ En(r) refers to the (r+1)th term in the nth row. The numerator and denominator are found separately‚ therefore to find the general statement‚ two different equations‚ one for the numerator and one for the denominator‚ must be found. Let M=numerator and let D=denominator so that En(r) = M/D. To find the numerator for any number of Lacsap’s Fractions‚ an equation must be made that uses the row number to find the numerator. Because the numerator changes depending on the row
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Aa = Sin Bb = Sin Cc a2= b2+ c2-2bc cosA and the two triangles that are going to be used; For the first calculations‚ r=1 and OP =2. By finding the ∠O in one triangle‚ I have found the ∠O in both triangles‚ allowing me a complete ration to perform the sine law. Side Note: All Final Answers are rounded to 3 Significant Figures. For the first calculations‚ r=1 and OP =2. By finding the ∠O in one triangle‚ I have found the ∠O in both triangles‚ allowing me a complete ration to perform the
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Introduction In this task‚ I will develop model functions representing the tolerance of human beings to G-force over time. In general‚ humans have a greater tolerance to forward acceleration than backward acceleration‚ since blood vessels in the retina appear more sensitive in the latter direction. As we all know‚ the large acceleration is‚ the shorter time people can bear. Using the data shown in the task and Mat lab analysis‚ we can get several model functions to represent the tolerance
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