Threesamma Joseph HLT-362V 9/7/2012 1. The answer is C‚ interval/ratio. The researchers analyzed the data as though it were interval/ratio level. They calculated the mean and standard deviation which is only appropriate for interval/ratio level data. 2. The mean post-test empowerment score for the control group is 97.12. This data is found explicitly in the chart of data given. 3. The baseline score mean is 14 and the post-test depression score mean is 13.36‚ meaning they were less depressed
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nature). Third‚ any independent variable consists of one group or two “matched pair” groups. Finally‚ all subjects are assumed to have been surveyed the same and data collection was unbiased. The assumption that was met in this study is the normal distribution. 5. Compare the 3 months and 6 months t ratios for the variable Exercise from Table 3. What is your conclusion about the long-term effect of the health-promotion intervention on Exercise in this study? After comparing the t-ratios for the Exercise
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Class: HTL-362V-0104 EXERCISE 20 1. Which patient scored the highest on the preoperative CVLT Acquisition? What was his or her T score? Patient 3 scored highest on the preoperative CVLT Acquisition with a T score of 62 2. Which patient scored the lowest on postoperative CVLT Retrieval? What was this patient’s T score? Patient 4 scored lowest on the postoperative CVLT Retrieval with a T score of 23 3. Did the patient in Question 2 have more of a memory performance decline than average on
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1. The researchers analyzed the data they collected as though it were at what level of measurement? The answer is C‚ which is interval/ratio scale. 2. What was the mean posttest empowerment score for the control group? The mean posttest empowerment score for the control group was 97.12 3. Compare the mean baseline and posttest depression scores of the experimental group. Was this an expected finding? Provide a rationale for your answer. The data shows that there was an improvement in the mean
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Sampling distribution The sampling distribution is the distribution of the values of a sample statistic computed for each possible sample that could be drawn from the target population under a specified sampling plan. Because many different samples could be drawn from a population of elements‚ the sample statistics derived from any one sample will likely not equal the population parameters. As a result‚ the sampling distribution supplies an approximation of the true value’s population parameters
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other. In small populations such sampling is typically done "without replacement"‚ i.e.‚ one deliberately avoids choosing any member of the population more than once. Although simple random sampling can be conducted with replacement instead‚ this is less common and would normally be described more fully as simple random sampling with replacement. Conceptually‚ simple random sampling is the simplest of the probability sampling techniques. It requires a complete sampling frame‚ which may not be available
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EXERCISE 29 Questions to be Graded 1. Were the groups in this study independent or dependent? Provide a rationale for your answer. The two groups were independent since they were formed based on gender with no intent to match subjects on any variable. The men and women selected didn’t share any relationship or live in the same location. 2. t = −3.15 describes the difference between women and men for what variable in this study? Is this value significant? Provide a rationale for your answer
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SAMPLING DISTRIBUTIONS |6.1 POPULATION AND SAMPLING DISTRIBUTION | |6.1.1 Population Distribution | Suppose there are only five students in an advanced statistics class and the midterm scores of these five students are: 70 78 80 80 95 Let x denote the score
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HOMEWORK 2 FROM CHAPTER 6 and 7‚ NORMAL DISTRIBUTION AND SAMPLING Instructor: Asiye Aydilek PART 1- Multiple Choice Questions ____ 1. For the standard normal probability distribution‚ the area to the left of the mean is a. –0.5 c. any value between 0 to 1 b. 0.5 d. 1 Answer: B The total area under the curve is 1. The area on the left is the half of 1 which is 0.5. ____ 2. Which of the following is not a characteristic of the normal probability distribution? a. The mean and median are equal
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X-bar Definition 1 x xi n i 1 Probability and statistics - Karol Flisikowski n Sampling Distribution of x-bar How does x-bar behave? To study the behavior‚ imagine taking many random samples of size n‚ and computing an x-bar for each of the samples. Then we plot this set of x-bars with a histogram. Probability and statistics - Karol Flisikowski Sampling Distribution of x-bar Probability and statistics - Karol Flisikowski Central Limit Theorem The key to
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