"Force majeure" Essays and Research Papers

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    Centripetal Force

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    Centripetal force (from Latin centrum "center" and petere "to seek"[1]) is a force that makes a body follow a curved path: its direction is always orthogonal to the velocity of the body‚ toward the fixed point of the instantaneous center of curvature of the path. Centripetal force is generally the cause of circular motion. In simple terms‚ centripetal force is defined as a force which keeps a body moving with a uniform speed along a circular path and is directed along the radius towards the centre

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    Triangle of Forces

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    ............................... 7 AIM To show that three forces acting upon a body‚ in equilibrium‚ may be represented by a triangle of forces. (Vector addition) INTRODUCTION With this experiment we will show that a body in a state of equilibrium‚ with three forces acting in a singular plane. The following conditions must be met: * Moment of all three forces must pass through the same point. * Magnitudes of the forces can be represented by the sides of a triangle‚ each as a vector

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    Force and Kg

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    the forces exerted by each ladder on the board. FR = 593N‚ FL = 299N 5. The diagram shows a horizontal beam of negligible mass. The wall exerts a 42.0 N horizontal force on the lever. Find the weight of the load. 16.1 N 6. A uniform 3.0 kg shelf of width 0.50 m is supported by a bracket‚ as shown in the diagram below. What force does the bracket exert on the shelf? 48 N 7. The diagram shows the forces acting

    Free Force Mass Friction

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    Force Of 870n

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    with friction force of 870 N and a coefficient of friction 0.23. What is the trailer’s normal force. 870N=.023(FN) divide by .023 FN=870N/.023 FN=37826.7N 9. mass 13.0 kg dropped from a cliff. Find its weight Fw=13.0kg * 9.8m/s^2 Fw=127.4kg*m/s^2 Fw=127.4N 13. A force of 175N needed to keep a 640N engine from sliding. What is the coefficient of static friction? Ff=175N FN=640N divide by 640N µ=175N/640N µ=.273 15. find acceleration of a forklift mass 1400kg pushed by force 2100N opposed by

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    basketball has some type of force working upon it. For example‚ without friction a basketball player would be unable to stop because inertia states that objects in motion tend to stay in motion. Without friction acting upon the player‚ there is no force to stop him‚ until he hits a wall that is. With this information you can come to the conclusion that without forces‚ there would be no game of basketball. However‚ what exactly is a force? Webster’s dictionary defines force as a push or pull that can

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    Resolving Forces In Truss

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    EXERIMENT.NO. 4 Resolving Forces in Truss STRUCTURAL MECHANICS 1 (CIVIL0006) Submitted by: Fahad Ali AL-Amri 11f8247 Session B Submitted to: Dr. Ram Kishore Manchiryal Fall2014 1. Experiment Name: Resolving Forces in Truss 2. Aim: The force in the member of truss is to be compared with the forces measured in the members with the values found by resolution at the joints. 3. Scope of the experiment: The experiment is to know the nature of force in each member of the

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    work on the principles of gravity and air resistance and in effect‚ terminal velocity. Air resistance (air friction) Air resistance is an upward force exerted on a body while it is in the air and is the result of air molecules that come in contact with the surface of the falling object. This force attempts to counteract gravity and other downwards forces influencing a body. The amount of air resistance encountered by an object is dependent on two factors: speed of the object and surface area. Air

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    Studying Force of Friction

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    A1 Studying force of friction Objective To investigate the effect on friction of the following factors: 1. normal force that presses the two surfaces together 2. materials that the two surfaces are made of 3. area in contact of the two surfaces Apparatus Rectangular wooden block Wooden plank Glass plate Plastic plate String Scissors Jack Spring balance Electronic balance Half-meter rule Retort stand and clamp G-clamp Trolley[pic]2 Standard weights (100g)[pic]5 Theory

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    Five forces model

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    The Five Competitive Forces Model In this section‚ the structure of our company will be explained using the five competitive forces model developed by Harvard professor Michael Porter. These forces include: rivalry among existing firms‚ threat of new entrants‚ bargaining power of buyers‚ threat of substitutes and bargaining power of suppliers. Each of these forces will have their own distinctive effect on determining industry profitability. Intensity of rivalry among competitors: Recently there

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    Equilibrium: Force and Mg

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    systems all forces and torques sum to zero. In problems where the first and second conditions of equilibrium are satisfied‚ the best strategy is to create FBD’s for both the first and second conditions‚ derive equations based on these FBD’s and then see what useful information may be gleaned from these equations. When applying the second condition we are free to choose any axis about which to compute torques. It is best to choose an axis that eliminates one or more forces that have lines of force that pass

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