In this investigation I will be burning alcohol ’s to heat up a can of water. I will be burning four alcohol ’s‚ methanol‚ ethanol‚ propanol and butanol. The aim is to find out how much energy is produced when burning these alcohols. Alcohol ’s react with oxygen in the air to form water and carbon dioxide. The reaction that is involved in burning alcohols is exothermic because heat is given out. From this reason the reactant energy is higher than that of the product. The energy is given out when
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Na₂Cr₂O₇ and H₂CrO₄ can be used. The reaction between alcohols and carboxylic acids will produce esters. Apparatus: Stopper‚ dropper‚ test tube‚ stopwatch‚ water bath‚ measuring cylinder (10ml) Chemical Reagents: Ethanol‚ n-Butanol‚ 2-Butanol‚ Alcohol X‚ Lucas reagent‚ 2-methyl-2-propanol‚ Concentrated H₂SO₄‚ 0.04 M Na₂Cr₂O₇‚ Glacial acetic acid Procedure (a) Lucas
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aim of this experiment is to investigate the combustion of various alcohols. The alcohols will be burnt to heat up a test tube of water‚ I aim is to find out how much energy is produced when burning the following alcohols: Methanol‚ Ethanol‚ Propanol‚ Butanol‚ and Pentanol. Any form of burning is an exothermic reaction (heat is given out)‚ this means that the reactants energy is higher than that of the product. Alcohols react with oxygen in the air to form water and carbon dioxide.
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In this experiment you will determine the molar heat of combustion of methanol‚ ethanol‚ 1propanol‚ 1butanol; and 1pentanol. Experimental Procedure Equipment * Electronic Balance ±0.01g * Measuring Cylinders ±1 mL * Aluminium Can * Cotton Wool * Theromometer ±0.5C * Retort Stand and Clamp * Spirit Burner containing alcohol sample * Alcohols (methanol‚ ethanol‚ 1-propanol‚ 1-butanol‚ 1-pentanol) Safety The alcohols are highly flammable. Always place the alcohol
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http://www.erowid.org/archive/rhodium/pdf/solvent.miscibility.pdf Webmaster Webmaster. (2013). Ethanol. Retrieved from: http://www.stenutz.eu/chem/solv6.php?name=ethanol Webmaster Webmaster. (2013). Methylene Chloride. Retrieved from: http://www.stenutz.eu/chem/solv6.php?name=methylene+chloride Webmaster Webmaster. (2013). 1 - Propanol. Retrieved from: http://www.stenutz.eu/chem/solv6.php?name=1-propanol Webmaster Webmaster. (2013). Ethyl Acetate. Retrieved from: http://www.stenutz.eu/chem/solv6.php
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liquids Ethanol‚ Propanol‚ Water‚ Pentane and Acetone evaporate at different rates. Methanol and Butanol were not liquids investigated by our group‚ but collectively as a class we were able to record averages of rates of evaporation. Solvent Molecular Formula Boiling Point (C°) Polar or Nonpolar Intermolecular Force(s) Lewis Dot Structure Methanol CH4O 64.7 Polar Hydrogen Bonding Dipole-Dipole London Dispersion Ethanol C2H6O 78.37 Polar Hydrogen Bonding Dipole-Dipole London Dispersion Propanol C3H8O
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Comparing the enthalpy changes of combustion of different alcohols Aim In this experiment I will investigate the enthalpy changes of combustion. In particular I will be investigating the enthalpy change of combustion for different alcohols. I hope to investigate some of the homologous series alcohols‚ as well as a few structural isomers of these alcohols. Background & theory Enthalpy cannot be measured. What we can actually measure is the enthalpy change from the reactants to the products.
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MOLECULES INVOLVED METHANOL ETHANOL PROPANOL BUTANOL PENTANOL HEXANOL HEPTANOL OCTANOL CARBON DIOXIDE WATER BALANCED EQUATIONS If we work in the bond energies into these balanced equations‚ and we subtract the energy taken in by the breaking of the bonds from the energy given out by the formation of new bonds we will get the total energy released. METHANOL 2CH3OH + 3O2(r) 2C02 + 4H20 ETHANOL 2C2H5OH + 6O2(r) 4C02 + 6H20 PROPANOL 2C3H5OH + 9O2(r) 6C02 + 8H20 BUTANOL 2C4H7OH + 12O2(r) 8C02
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INVOLVED METHANOL ETHANOL PROPANOL BUTANOL PENTANOL HEXANOL HEPTANOL OCTANOL CARBON DIOXIDE WATER BALANCED EQUATIONS If we work in the bond energies into these balanced equations‚ and we subtract the energy taken in by the breaking of the bonds from the energy given out by the formation of new bonds we will get the total energy released. METHANOL 2CH3OH + 3O2(r) 2C02 + 4H20 ETHANOL 2C2H5OH + 6O2(r) 4C02 + 6H20 PROPANOL 2C3H5OH + 9O2(r) 6C02 + 8H20 BUTANOL 2C4H7OH + 12O2(r)
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lot of energy than the rest. Also because it is a polymer it has more chains than we can count so it should have lost of energy. However the butanol could be the fuel to produce the most energy because although the paraffin is a polymer since it is harder to burn it will also take longer to burn and it might not burn within the time limit. So since butanol is the fuel with the second highest carbon atoms and the second longest carbon chains it will burn within this time and may produce the most energy
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