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    1.67 0.27 4 RM106_e 3 4.08 0.29 4 2.91 0.41 7 Column Total 14 - 3.49 10 - 4.88 24 Chi-square‚ X2 total 8.37 H0: The phenotype of awn/awnless is not associated with RM106 Ha: The phenotype of awn/awnless is associate with RM106 Df = 4 X0.052 = 9.49 Since X2 < X0.052‚ the Ho is not rejected. RM106 was not associated with awn phenotype. Table 1.1: Chi-square calculation of phenotype I (awn-awnless) and genotype (RM345) correlation. Genotype Phenotype

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    What proportion of a normal distribution is located in the tail beyond z = +2.00? 0.0228 What proportion of a normal distribution is located between the mean and z = 1.40? 0.4192 The Z-score corresponding to the 52nd percentile is .05 A normally distributed variable has a mean of 10 and a standard deviation of 2. The probability that a value between 7 and 9 is obtained is .2417 An accelerated life test on a large number of type-D alkaline batteries revealed that the mean life for a particular use

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    Computer Exercises C1.2 Use the data in BWGHT.RAW to answer this question. . summ Variable | Obs Mean Std. Dev. Min Max -------------+-------------------------------------------------------------------------------- faminc | 1388 29.02666 18.73928 .5 65 cigtax | 1388 19.55295 7.795598 2 38 cigprice | 1388 130.559 10.24448 103.8 152.5 bwght

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    gfhfhgfdg

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    | | | | | ANOVA table | | | | | | | Source | SS | df | MS | F | p-value | | Regression | 569.73600489 | 1 | 569.73600489 | 4.94 | .0299 | | Residual | 6‚913.25576931 | 60 | 115.22092949 | | | | Total | 7‚482.99177419 | 61 |   |   |   | | | | | | | | | | | | | | | | Regression output | | | | confidence interval | variables | coefficients | std. error | t (df=60) | p-value | 95% lower | 95% upper | Intercept | 93.4294 |

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    Exercise 29

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    8: If researchers conducted 9 t-tests on their study data. What alpha level should be used to determine significant differences between the two groups in the study? Provide your calculations. Q 9: The authors reported multiple df values in Table VI. Why were different df values reported for this study? Q 10: What does the t value for the Physical Component Score tell you about men and women post MI? If this result was consistent with previous research‚ how might you use this knowledge in your

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    Chris McCandless

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    He was experienced and had traveled to many different parts of the world. It was always his dream to go to that national park. advg;lsrgjsljvsd lskvhwsldjv;sod df sdfb sfwr bf bbh ty mktj te bgs rhedtj dfts gvdf rnd t gd sf hjjt g dfs fghj gf d

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    Khokhar\Desktop\Statistics\autos.dta"‚ clear (1978 Automobile Data) 6 . corr mpg weight (obs=74) mpg weight mpg weight 1.0000 -0.8072 1.0000 1 Friday January 9 11:48:08 2015 Page 2 7 . di -0.8072^2 -.65157184 8 . reg mpg weight foreign Source SS df MS Model Residual 1619.2877 824.171761 2 71 809.643849 11.608053 Total 2443.45946 73 33.4720474 mpg Coef. weight foreign _cons -.0065879 -1.650029 41.6797 Std. Err. .0006371 1.075994 2.165547 Number of obs F( 2‚ 71) Prob > F R-squared

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    FOOD CONSUMPTION BEHAVIOR‚ NUTRITION AND HEALTH KNOWLEDGE AND DIETARY CHANGES AMONG MALAYSIAN STUDENTS AT OKLAHOMA STATE UNIVERSITY By SffiW-ING HIT Bachelor of Science Oklahoma State Universiil:y Stillwater‚ Oklahoma 1994 Submitted to the Faculty of the Graduate College of the Oklahoma State University in partial fulfillment of the requirement for the Degree of Master of Science July‚ 1997 FOOD CONSUMPTION BEHAVIOR‚ NUTRITION AND HEALTH KNOWLEDGE AND DIETARY CHANGES AMONG MALAYSIAN STUDENTS

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    Week 6 Statistics Qnt 561

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    Chapt 10 # 42 H0: game length is >= 3.5 hours Ha: game length is < 3.5 hours mean = 2.9553 stdev = 0.5596 Get the t test statistic: t = (x-mu)/(stdev/sqrt(N)) t = (2.9553-3.5)/(0.5596/sqrt(17)) t = -4.0133 Get the critical value for df = N-1 = 16‚ one tail‚ alpha is 0.05: -1.7459 Since our test statistic is much lower than the critical value‚ we reject the null hypothesis. There is enough evidence to conclude that games are shorter than 3.50 hours. Chapt 11 # 58 The amount

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