banks of international repute. After the successful launch of retail financing scheme for vehicles, SBI is now focusing on Wholesale financing of vehicles in... the form of Dealer Financing through its newly launched Electronic Dealer Financing Scheme (e-DFS), which runs on a fully web based portal and ensures automated payments and settlements.Maruti Suzuki ties up with IDBI Bank for car loan financingIDBI Banl Ltd (IDBI) and Maruti Suzuki India Limited (MSIL) today entered into a Memorandum of Understanding...
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Case Study – Direct Food Supply (DFS) Company background DFS is a rapidly growing food distribution and wholesaling company... located in the North East of England. It was founded by Mr Abbas, who started the business from a small storage room with only 3 employees back in 1985. From the mid 80s to the late 90s, DFS experienced tremendous growth in business volume (sales). In order to meet the increasing demand for its services, Mr Abbas began an ambitious expansion plan in 1999. In order to...
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Your Name : Siyao Zhong Role Play Name : 67 Fishpond Lane Your Role : Seller of the House with Marlee. Person... Playing Other Role : Steven and Valerie V, playing the buying $Results : 380,000$ for house + 20,000$ for birds This case presented me a huge impression since it was the first time we did case in groups, where as all the cases we did previously, including the sophisticated Riverside...
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fg fgfgfg f gfg fg fg fg fg gf gf g dg ertf r t rt r tr tr gr g r gr g rfg dfr gf g fg f gf g frg fg f gf bg fg f g fg fg f gf g f g fg f gf g fg f g f g f... g fg fg f gfg dfg fg fg fd g dfg df g fdg dfg df g dfg df g fdg fd gfd g f gdfgd g df g dfg fd g fd g fd g f dg df g fd gf dg fdg f g fd gdf g fd gf g df g fdg fd g fd gfd g fdgdf Dear Sir/Madam I am writing to express my interest in the role of Sales Assistant. As you can see from my CV (attached), I am a proven Sales Assistant with a...
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6/4/2013 Introduction & Problem Statement Since Diamond Foods (DF) became public in 2005, they have experienced positive growth... in both stock price and sales. The management is extremely focused on expansion by capturing market share and increasing product offerings. Their concerted effort to grow is ensuring Diamond and its brands are in the forefront of consumer’s minds and their snacking habits. DF has recently acquired Harmony and Pop Secret, and is considering future growth...
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------------------------------------------------- 4.decrease σ One sample t CI x±t*s√n One sample t-test T=x-µ0s√n... ------------------------------------------------- Df=n-1 ------------------------------------------------- P is 2 closest Two pop means (before and after) xD±t*sD√nD xD=x1-x2 sD=x2-(x)2nn-1 Hypothesis test H0:µa=µb H1: µa≠µb T=xd-D0Sd√n ------------------------------------------------- Df=n-1 ------------------------------------------------- P is 2 closest Two pop means (2 samples one condition) σ known CI: ...
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(iii) mt/tl (iv) tr/tv (e) The amount that withdrawals rise when national income rises from Od to Of (i) tn (ii) nm (iii) tm (iv) ln... (v) lm (f) mpw (i) tn/df (ii) nm/df (iii) df/tn (iv) df/nm (g) The multiplier (i) tn/df (ii) nm/df (iii) df/tn (iv) df/nm ----------------------- ECONOMICS Short-run Macro Equilibrium Short-run Macro Equilibrium Answers to Workshop 12 John Sloman Answers to Workshop 12 Short-run Macroeconomic...
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particular color of magic marker ink. You can also calculate a ratio Rf, which compares how far each compound traveled to how far each solvent (substance... that dissolves another substance) traveled during the experiment. Rf = Ds/Df Ds = Distance traveled by the compound Df = Distance traveled by the solvent Materials: coffee filter, tape, rubbing alcohol, water, 3 different color magic markers (not permanent); 3 identical tall, narrow drinking glasses; metric ruler, 3 pencils Pre-lab Questions: ...
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managing director from research company Fusion FSM. Diane Lane spoke to him about market trends, nurturing young talent, and breakfast beverages Caterer So... David, you're a food service veteran -- what is it about this sector that so appeals to you? DF Across which other industry would you find such commitment, diversity and passion? It's an industry where I feel a real difference can be made. That difference might be in partnering our clients and other suppliers to find the right solutions to develop...
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Step 5 Find the degrees of freedom. a. Between groups: df = k – l; df = 3 – 1 = 2 b. Within groups: df = Nt – k;... df = 18 – 3 = 15 Step 6 Find Mean Squares (MS) a. MSb = SSb = 2052 = 1026 dfb 2 b. MSW = SSW = 2296 = 153.07 dfW 15 Step 7 Find the F-ratio F = MSb = 1026 MSW 153.07 Step 8 Determine the significance of F. Refer to the Table of F-ratio. The critical value of F for df = 2/15 at the .05 level is 3.68 and at a level .01 level...
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Descriptive Statistics | | Mean | Std. Deviation | N | fear of stats time1 | 40.17 | 5.160 | 30 | fear of stats time2 | 37.50 | 5.151 | 30 | fear of... stats time3 | 35.23 | 6.015 | 30 | Multivariate Testsb | Effect | Value | F | Hypothesis df | Error df | Sig. | Partial Eta Squared | Time | Pillai's Trace | .635 | 24.356a | 2.000 | 28.000 | .000 | .635 | | Wilks' Lambda | .365 | 24.356a | 2.000 | 28.000 | .000 | .635 | | Hotelling's Trace | 1.740 | 24.356a | 2.000 | 28.000 | .000 | .635...
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How many standard deviations is my hypothesis (sample mean) is away from the actual (null hypothesis population mean) T – statistic Rejecting the null... may be a mistake = p –value ONE SAMPLE 3 formulas T.Dist.rt (t, sample size - 1 “df”) -> alternative that mu is bigger than a 1 – T.Dist.rt (t, sample size – 1) -> mu is less than a T.Dist.2t(t,samplesize - 1) -> not equal to p < significant level reject the null NEVER accept null TWO SAMPLE directly get the p-value ...
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regress share01 msz01 mkts01 dists01 imps01 exp01 costef01 Source Model Residual Total share01 msz01 mkts01 dists01 imps01 exp01 costef01 _cons SS .009219454... .009618643 .018838097 Coef. .0039095 .0116468 -.0483168 .0079969 .0032243 .0036286 -.0098497 df 6 169 175 MS .001536576 .000056915 .000107646 t 10.95 1.40 -1.46 0.73 1.19 1.98 -4.41 P>|t| 0.000 0.162 0.147 0.464 0.234 0.049 0.000 Number of obs F( 6, 169) Prob > F R-squared Adj R-squared Root MSE = = = = = = 176 27.00 0.0000 0.4894 0.4713 .00754 ...
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Intelligence Homework 2 search strategies Q1. A. Show that DFS generates about O(bm) nodes in the search tree. m: The maximum length of... any path in the state space b: The branching factor: maximum number of successors of any node. At the worst case, DFS generates about O(bm) nodes in the search tree. As follows : At m (max depth )tries : 1 +b + b2 + b3 +….+ bm =O(bm) , the graph below illustrates this. B. Explain why DFS requires less memory than BFS. In BFS you keep all nodes in memory...
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Reject the null hypothesis if F-calculated is greater than 2.85 (F-critical) Step # 5 – Calculate the test statistic, arrive at a decision, and state a... conclusion: Degrees of freedom in the numerator: df= c-1= 4-1= 3 Degrees of freedom in the denominator: df = n-c = 43-4 = 39 Decision is to retain the null hypothesis. Conclusion is that a difference cannot be proven between wages of workers with a 12th grade education based upon age. p-value = 0.086 ...
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no diff in the price quoted for car insurance between A & B H1 = There is a diff in the price quoted for car insurance between A & B With 14° of... freedom, .10 sig level, critical values = -1.761 & 1.761 .90 of CI= (-495, 2) T-Test=0 DF=14 T-value=-1.74 P-value=.103 Accept the hypothesis because there is no sig differences in the quotes of the two insurance providers. Chapter 12: 23) H0 = There is no variation in the selling prices for oceanfront homes. H1 = There is more variation...
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specific models and won’t work or no need to work on all models. Do the unlocking process at your own risk. I am not responsible for any damage cause to the... device or loss. For unlocking Huawei EC150 you’ll need the following Tools & Softwares: 1. DFS 3.3.0.7 - CDMA Reprogram, flashing software.(www.cdmatool.com) 2. IDM UltraEdit v.17.0.XXX (www.ultraedit.com) 3. EC150Update_11.104.04.00.114.B416.exe – Firmware Update (Incase you need to update the firmware, Not necessary if you don’t want...
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~/literature/classics b= rmdir /home/max/literature/classics, rmdir ~max/literature/classics, rmdir ~/literature/classics, rm -r... /home/max/literature/classics 4) The df utility displays all mounted filesystems along with information about each. Use the df utility with the –h (human-readable) option to answer the following questions. $ df -h Filesystem Size Used Avail Use% Mounted on /dev/hda1 1.4G 242M 1.1G 18% / /dev/hda3 23M 11M 10M 51% /boot /dev/hda4 1.5G 1.2G 222M 85% /home /dev/hda7 564M...
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009533 | | | | | | | 5.4 | 5.4 | Standard Error | 0.396714 | | Intrinsic is higher | | | | 6.2 | 6.2 | Observations | 30 | | | | | | |... 6.2 | 5.2 | | | | | | | | | 2.3 | 5.3 | ANOVA | | | | | | | | 4.5 | 4.7 | | df | SS | MS | F | Significance F | | | 5.4 | 5.4 | Regression | 1 | 0.20131 | 0.20131 | 1.279119 | 0.267657 | | | 6.2 | 6.2 | Residual | 28 | 4.40669 | 0.157382 | | | | | 6.2 | 5.2 | Total | 29 | 4.608 | | | | | | 5.4 | 5.5 | ...
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Calculated 99 percent confidence intervals for the selling price of the home. | |Test Value = 0 | | |... | | | | | |t |df |Sig. (2-tailed) |Mean Difference |99% Confidence | | | | | | | |Interval of the | | | | ...
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0.627 n 96 R 0.797 k 2 Std. Error 14.421 Dep. Var. DAYS ANOVA table Source SS df MS F p-value... Regression 33,654.6771 2 16,827.3385 80.91 4.41E-21 Residual 19,341.7292 93 207.9756 Total 52,996.4063 95 Regression output confidence interval variables coefficients std. error t (df=93) p-value 95% lower 95% upper Intercept 70.6818 3.9129 18.064 3.60E-32 62.9116 78.4520 BILL -0.0126 0.0190 -0...
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Outside Sales Professionals | 5. ANOVA | | | | | | | Source of Variation | SS | df | MS | F | P-value | F crit | Between Groups... | 9515793950 | 1 | 9515793950 | 251.5404 | 4.96486E-31 | 3.921478 | Within Groups | 4463949042 | 118 | 37830076.62 | | | | | | | | | | | Total | 13979742992 | 119 | | | | | 6. ANOVA | | | | | | | Source of Variation | SS | df | MS | F | P-value | F crit | Between Groups | 1668100099 | 2 | 834050049.7 | 7.926144 | 0.000591268...
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of freedom (df) are the number of scores in a sample that reflect the variability in the population; used when estimating the population... variability” (Heiman, 2012, p.110). df = N-1, N being the number of scores in the sample. In Martha’s case it would be 9. Consider that a = .05. Then use Appendix B, Table 2 to determine the critical value, state the value, and how you found it. The critical value is 1.833. Using the Table for a one-tailed test, I found 9 in the column for df, then found...
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differences between several means at one time. Formula: Step 1: Computation of the various sums of squares (SS): 1.1. 1.2. 1.3. Step 2:... Computation of the degrees of freedom (df) for the various sums of squares: 2.1. df for “total” = N - 1 2.2. df for “between” = k - 1 2.3. df for “within” = df for “total” – df for “between” Step 3: Computation for the various mean of squares (MS) 3.1. MSB = SSB / dfB 3.2. MSW = SSW / dfw Step 4: Computation for the F-ratio. Fc = MSB / MSW ...
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10 A t-test can be conducted to assess the statistical significance of the difference between the sample means. The null hypothesis is that the... population means are equal (H0: (1 = (2). [pic] df = (n1 + n2 - 2) = (6 + 6 - 2) = 10. For a two-tailed t-test with alpha set at .01 and df=10, the tabled critical value is 3.169. Because the absolute value of the observed t just exceeds the critical value we can reject the null hypothesis (Ho: (1 = (2) at the .01 level of significance. The...
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differences between the two groups in the study. 9. The authors reported multiple df values in Table VI. Why were different df... values reported for this study? The author used multiple df values in table VI because according to the data above, significance of a t ratio can be determined by comparison with the critical values in a statistical table for the t distribution using the degrees of freedom for the study. DF is a mathematical equation that describes the freedom of a particular scores’ value...
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then translate into the mass specific metabolic rate (MSMR). With the comparison between mice in room and cold temperatures, mice held in cold temperatures... had a higher MSMR (t= 3.23, df= 16, p= 0.005). The MSMR of cockroaches held in cold temperatures resulted higher than cockroaches at room temperature (t= 1.87, df= 15, p= 0.081). Also, the mice held at both temperatures had a higher MSMR than the cockroaches at both temperatures. Since mice are endotherms, they would have a higher metabolic rate...
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(correlation coefficient) = 0.79980157 R-sq = 0.63968255 Estimate of error standard deviation: 7.5614248 Parameter estimates: Parameter Estimate Std. Err.... Alternative DF T-Stat P-value Intercept 10.091611 5.7500723 ≠ 0 22 1.7550408 0.0932 Slope 0.87086093 0.13934708 ≠ 0 22 6.2495816 <0.0001 Analysis of variance table for regression model: Source DF SS MS F-stat P-value Model 1 2233.1051 2233.1051 39.057271 <0.0001 Error 22 1257.8532 57.175145 Total 23 3490.9583 Discussion: I used the histogram; I...
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10 27.46 4.44 1.4 Murrells Inlet 12 25.69 2.68 0.77 Difference = mu (small river) - mu (Murrells Inlet) Estimate for difference: 1.77 95% CI for... difference: (-1.67, 5.21) T-Test of difference = 0 (vs not =): T-Value = 1.10 P-Value = 0.288 DF = 14 As p-value> 0.05 and T is the value in the critical values, the null hypothesis is accepted. No difference in the average waiting time vs. Little River Murrells Inlet location. Chapter 11 Exercise 52 Answer H0 = There is no difference...
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Variance Source DF Seq SS Adj SS Adj MS F P Regression 3 34255444 34255444 11418481 63.3013... 0.000000 Income ($1000) 1 16703393 9936482 9936482 55.0855 0.000000 Size 1 17478430 16716632 16716632 92.6730 0.000000 Years 1 73620 73620 73620 0.4081 0.526087 Error 46 8297619 8297619 180383 Total 49 42553062 N = 50 DF = 47 α = 0.05 ...
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positive association between the size of the home and the selling price? Use the .05 significance level. Step 1: Step 2: The alternative... hypothesis is which indicates a one tail test. The degrees of freedom (df) = n-2=12-2=10. The t value at the significance level of .05 and df of 8 and from appendix F is 1.812. The decision rule is to reject the null hypothesis because the test statistic is greater then 1.812. Step 3: According to Appendix F, we can assume that P 1.744), there is...
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To: Kirk Callow, Steelworks Inc. After a careful analysis of the Durabend (DB) and Duraflex (DF) lines it has become evident that there is... volatile demand for specialty products, given that both DB and DF have high coefficients of variation of 1.08, 1.18 respectively (Exhibit 1). In the case of DB, the volatility can be attributed to the lack of high-volume customers (194/195), and the abundance of low-volume purchasers (Exhibit 2). To solve this problem it will be necessary for Steelworks to...
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for the study will be that the runners pulse will be the same as the other althete, and the Ha for the study is that runners pilse is slower than other... athletes. d. Find tcv from appendix A in Jackson’s text. Df = -1 Df 10 -1 = Df = 9 Using alpha 0.05 Tcv = 1.833 e. Compute t obt Tobt = -4.4799 http://in-silico.net/tools/statistics/ttest f. Should H0 be rejected? What should the researcher...
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Column Totals | 707 | 675 | 493 | 109 | 1984 | a) Test of homogeneity H0: No real overall disagreement between the two polls HA: H0 is not true.... There is a real overall disagreement between two polls α = 0.05 df = (r-1)*(c-1) = (2-1)(4-1) = 1*3 = 3 For df = 3; chi-square, based on 0.05 level = 7.8417 Expected observation = Row Total*Column Total/Grand Total Eij | Liberal | PC | NDP | Green | Row Totals | Angus Reid | 356.3508 | 340.2218 | 248.4879 | 54.93952 | 1000 | ...
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| | |Describe and sketch the colors |Distance the solvent |Distance the colors |Ds/Df... | | | |traveled from the pencil |traveled from the pencil |(decimal) | | | |line (cm) Df |line (cm) Ds | | |1.BLACK | | ...
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7}. (12 Marks) 4. a) Briefly explain Strassen’s matrix multiplication. Obtain its (12 Marks) complexity. Apply the algorithm to multiply the given... 2 matrices. 1 2 5 6 3 4 X 7 8 b) Differentiate between DFS and BFS tree traversals. Explain how DFS algorithm can be used to obtain the topological sorting with an example. (08 Marks) PART -B 5. a) Write and explain the Heap sort algorithm using top-down approach. Sort the elements {M,O,R,N,I,N,G} in alphabetical...
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E=er(k) , the error change dE= der(k)and the control input change df. 2. If the minimum and maximum ranges of step one are different then... quantize then into a common universe of discourse using scaling factors such that the maximum and minimum of the quantized error signal E, the quantized error change dE, and the quantized control input changed f are all the same. 3. Define the symmetrical linguistic fuzzy subsets of E, dE, and df. 4. Calculate the error er and the error change der for the...
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expected frequencies, test statistic, and the P-value associated with the test statistic. The approach described in this section is illustrated in the sample... problem at the end of this lesson. * Degrees of freedom. The degrees of freedom (DF) is equal to: DF = (r - 1) * (c - 1) where r is the number of levels for one catagorical variable, and c is the number of levels for the other categorical variable. * Expected frequencies. The expected frequency counts are computed separately for each...
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1923 + 83 - 15233 + 3 - 2 13 + 13 =129-3613+83-22534 23 =129-120.30+83-75 4 23 =8.7+8423 =16.7423=16.76=2.7830 =1.668... Compute t. t t=0.779 6. Find the critical or tabular of t. df (Degrees of freedom) = 4 a = 0.025 ttab = 2.776 Since the tcalc is less than ttabular , accept the null hypothesis. There is no significant difference between the mean numbers of bacterial colonies...
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current and new golf balls is: H0: µ1 - µ2 ≥ 0 (mean distance of new greater than or equal to the old) Ha: µ1 -µ2 < 0 (mean distance of new less than... old) 3. Statistical basis n1 = 40 n2 = 40 x1 = 270.28 x2 = 267.5 s1 = 8.75 s2 = 9.90 α = .05 df = 78 t = (270.28 – 267.5) – 0 = 1.33 P-value = .10 P-value > .05 (or α); do not reject H0 4. The 95% confidence interval for the sample mean driving distance for current golf balls is 267.66 to 272.90. The 95% confidence interval for the sample mean...
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Chapt 10 # 42 H0: game length is >= 3.5 hours Ha: game length is < 3.5 hours mean = 2.9553 stdev = 0.5596 Get the t test statistic: t =... (x-mu)/(stdev/sqrt(N)) t = (2.9553-3.5)/(0.5596/sqrt(17)) t = -4.0133 Get the critical value for df = N-1 = 16, one tail, alpha is 0.05: -1.7459 Since our test statistic is much lower than the critical value, we reject the null hypothesis. There is enough evidence to conclude that games are shorter than 3.50 hours. Chapt 11 # 58 The amount...
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the sample is smaller than 30, a t distribution should be used. We need to assume that the sample is from a normal population (pp. 291-293). c. For a 90... percent confidence interval, what is the value of t? For a 90 percent confidence interval, and df = 15, t= 1.753 d. Develop the 90 percent confidence interval for the population mean. Xbar = 60; s = 20; n = 16 Xbar ±t(s/√n) = 60 ± 1.753 (20/√16) = 60± 1.753 (5) = 60± 8.765 = [51.24, 68.77] e. Would it be reasonable to conclude that the population...
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well with χ2(df = 734; N = 158) = 884.12, p < .01, RMSEA = .036, SRMR = .061 and χ2/df < 2. - χ2 difference test showed Thought... and Memory were separate factors but they were correlated. (r = .76) - Survey 1 analysis finished with 6 factors: Insight, Control, Thought, Realism, Memory and Dissociation. CFA of Survey 2 data - Emotion split into positive and negative as parameter estimation of the model caused a negative error variance before. The model fitted the data quite well with χ2(df = 324; N =...
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| | | 25 | 0 | 0 | 27 | 2 | 4 | 25 | 0 | 0 | 23 | -2 | 4 | 24 | -1 | 1 | 25 | 0 | 0 | 26 | 1 | 1 | 25 | 0 | 0 | x= 200 S2=10/7=... 1.42857 S2M=S2/N=10÷7/8=0.17857 SM=Sm2= 0.422577 Step 3. (=.025, DF=7) =2.365 =.05 /2= .025 (two tailed test) So if the sample > 1.895 We reject H0 Step 4. Sample = 2.366 Step 5. Since 2.66>2.365 we will reject the null hypothesis/HO Part B. . The results show that the average...
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| | Population standard deviation unknown, we need to use t test. Using data analysis, we can easily get the sample mean 217.222 and sample standard... deviation 1.202. Ho: u 216 Reject Ho if t > 2.306 (one-tailed test with a = 0.025 and df = 8) t = (217.222 – 216) / (1.202/sqrt(9)) = 3.05 Reject Ho. The shelf life of the cake mix has increased. Correct Marks for this submission: 2/2. Question 2 Marks: 1 If α = 0.05 for a two-tailed test, how large is the acceptance area? Choose...
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is the heat rate. It is one sample t- test. One-Sample Statistics | | N | Mean | Std. Deviation | Std. Error Mean | HEATRATE | 67 | 11066.43 |... 1594.960 | 194.855 | One-Sample Test | | Test Value = 10000 | | t | df | Sig. (2-tailed) | Mean Difference | 95% Confidence Interval of the Difference | | | | | | Lower | Upper | HEATRATE | 5.473 | 66 | .000 | 1066.433 | 677.39 | 1455.47 | Since SPSS reports the P-value on the basis of a two-tailed...
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captured the fancy of economists and set the stage for the further development of DFA within the competitive industrial context. • Forces that push toward... change are called driving forces. Forces that resist change are called restraining forces. • DFs are those significant, underlying ‘currents’ that define and drive events and trends in certain directions. • These forces are typically broad in scope, long term in nature and associated with uncertainty. FT Press 2007. All Rights Reserved. ...
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Number of Observations Used 100 Analysis of Variance... Sum of Mean Source DF Squares Square F Value Pr > F Model 2 4643274 2321637 19.09 |t| Intercept Intercept 1 303.25287 212.86755 1.42 0.1575 ...
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of a hundred you would find a statistically significant difference between the means even if there was none (i.e., by "chance"). You also need to determine... the degrees of freedom (df) for the test. In the t-test, the degrees of freedom is the sum of the persons in both groups minus 2. Given the alpha level, the df, and the t-value, you can look the t-value up in a standard table of significance (available as an appendix in the back of most statistics texts) to determine whether the t-value is ...
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ocfoundation.org/uploadedFiles/Hoarding%20Fact%20Sheet.pdf?n=3557. Accessed March 14, 2011. 2. Sansone RA, et al. Hoarding: Obsessive symptom or... syndrome? Psychiatry. 2010;7:24. 3. Tolin DF. Challenges and advances in treating hoarding. Journal of Clinical Psychology. 2011. In press. 4. Tolin DF. Understanding and treating hoarding: A biopsychosocial perspective. Journal of Clinical Psychology. 2011. In press. 5. Saxena S. Recent advances in compulsive hoarding. Current Psychiatry Reports...
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the physical property measured was the tension modulus of elasticity in the direction perpendicular to the alignment of the ﬂakes, in pounds per square inch... (psi). For these data, a two-way ANOVA was run and the partial ANOVA table is given below: df SS MSS F p value Source Size 157.44 .613 7256 Species Size∗ Species 41707 Error 12262 Total 17 206664 a. Fill in the blanks b. In the ANOVA table, the test for the main eﬀect of size has a P-value of 0.613. What does this indicate? i. The eﬀect of particle...
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Z 480 Z 600 Z 610 ; PROC ANOVA DATA=READING; TITLE 'ANALYSIS OF READING DATA'; CLASS GROUP; MODEL WORDS=GROUP; MEANS GROUP;... RUN; The ANOVA Procedure Dependent Variable: words Sum of Source DF Squares Mean Square F Value Pr > F Model 2 215613.3333 107806.6667 16.78 0.0003 Error 12 77080.0000 6423.3333 Corrected Total 14 292693.3333 ...
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estimated by the method of least squares. bi measure the impact of unit change in the ith independent variable on crime. The estimated values of regression... coefficients are given below |Variables |coefficients |std. error |t (df=41) |p-value | |Intercept |-642.5030 |1024.03 |-0.627 |.5339 | |PINCOME |-0.0183 |0.0773 |-0.237 |.8136 | |DROPOUT...
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Transmit Unit) One machine will send the biggest packet it can with the DF (Don't Fragment) bit set. With the DF bit set, this... packet will not be broken up into smaller packets. It has to be transmitted at its current size or not at all. If any system along the path has a smaller MTU, it will drop the packet with the DF bit set, and send an ICMP error message back to the origin system saying that it couldn't send packets that big, but DF was set so it couldn't fragment it. Path MTU discovery depends on...
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Draw freehand sketches of the following. (1) Acme thread (2) Dome nut (3) Woodruf key List various methods of reproductions of drawing. 5|-! VFSlT v!... DF\ V[S 5NFY^ GM lR+FtDS N[BFJ VF5[, K[P 5|YD 5|1F[56 5wWlTDF\ 5}ZF DF5DF\ GLR[GF\ s!f ;FD[GM N[BFJ v TLZ ‘x’ GL lNXFDFP\ sZf p5ZGM N[BFJP s#f AFH]GM N[BFJP s!$f 5|-Z sVf VFSVlT vZ DF\ V[S 5NFY^ GF\ A[ N[BFJM NX^FJ[, K[P T[GF\ 5ZYL ;DlDTLI N[BFJ NMZMP sAf VFSVlT v# DF8[ GLR[GF N[BFJM NMZMP s!f 5FK/GM N[BFJP sZf GLR[GM N[BFJP VYJF sAf OST...
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Hypothesis H0: oil is equal to zero 0 (oil is not a significant) Ha: Oil is not equal to 0 (oil variable is significant) - two tail... test 2. tstat = -0.008-0/.00026= -3.07 3. tcritical ( alpha=0.05, df= 50-3) = 2.021 read the two tail 4. Decision if | tstat | > tcritical reject the Null Hypothesis |3.07 | > 2 true 5. Conclusion Oil is a significant variable at...
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R | R Square | Adjusted R Square | Std. Error of the Estimate | 1 | .772a | .597 | .570 | 266752.420 | a. Predictors: (Constant), SIXERS, AGE_1,... ODI_WICKET, BASE_PRICE, COUNTRY, T_RUNS, RUNS_S, ODI_RUNS | ANOVAb | Model | Sum of Squares | df | Mean Square | F | Sig. | 1 | Regression | 1.274E13 | 8 | 1.592E12 | 22.378 | .000a | | Residual | 8.610E12 | 121 | 7.116E10 | | | | Total | 2.135E13 | 129 | | | | a. Predictors: (Constant), SIXERS, AGE_1, ODI_WICKET, BASE_PRICE, COUNTRY...
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