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    that the diluted solution is 0.046 M KOH‚ but has forgotten to record the volume of the original stock solution sample. The concentration of the stock solution is 2.09 M. What was the volume of the original sample of stock solution? 3. A chemist wants to prepare a stock solution of H2SO4 (sulfuric acid)‚ so that a sample of 20.00 mL will produce a solution with a concentration of 0.50 M when added to 100.0 mL of water. A) What should the molarity of the stock solution be? B) If the chemist wants to

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    AP Biology August 23‚ 2012 Egg Osmosis Lab Definition of osmosis: The diffusion of water across a selectively permeable membrane from high to low concentrations Hypothesis: If I place an egg in vinegar‚ then the outer layer of the egg is going to become slimy and look like rubber. It will also become larger and bubbles will form on and around the egg. Hypothesis: If I place an egg in corn syrup‚ then the egg will become small and the outer layer will not look like rubber any longer. Day one:

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    4 M Egg Osmosis

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    occurred because of the levels of concentration of solute in the different solutions. Since the 4 M solution had the highest concentration of solute‚ compared to the other three solutions tested‚ and a higher concentration of solute than that of the solution inside the egg‚ it was a hypertonic solution.

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    From the results obtained and the bar graph plotted‚ it could be seen that when there was a high concentration of sugar the mass of beetroot decreased. This happened because water moved from the inside of the beetroot‚ where there was a high water potential into the sugar solution‚ which had a lower water potential. In the other four beakers where the concentration of sugar solution was less‚ the mass of the beetroot increased. This happened because water moved from the dilute sugar solution where

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    Biology Essay

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    Diffusion of Cell Size 2012 Kayla Szabo Loxton High School 2/20/2012 Rate of Diffusion Practical report Introduction: Diffusion is the movement of a substance from an area of high concentration to an area of low concentration. Cells need to utilise diffusion to exchange materials from outside of the cell to the inside of the cell for them to survive. Diffusion is a passive process‚ which means it doesn’t involve the need of energy. For a cell to survive it relies greatly on its size

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    Rate Of Osmosis

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    Rate of Osmosis vs Solute Concentration Introduction: In nature‚ the quest to reach equilibrium‚ or the state of rest or balance due to the equal action of opposing forces (http://www.dictionary.com). Osmosis and diffusion are two ways that cells reach this equilibrium‚ without exerting energy. Due to the unique nature of the phospholipid bilayer‚ small molecules can pass through the semipermeable membrane easily‚ through diffusion (https://www.biologycorner.com). Water‚ however‚ has a slightly more

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    area of least concentrated‚ which is equal to moving down a concentration gradient. When the molecules have reached equal concentrations in both locations‚ diffusion ends and it has reached equilibrium. Molecules continue to move‚ but move in both directions equally; there is no net change! Osmosis is the movement of water. It moves water molecules across a cell membrane either in or out of the cell and still moves down the concentration gradient. The object is still to reach equilibrium. Osmotic

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    Diffusion Egg Lab

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    LabMr.P/Pd. 63/17/14 Osmosis and Diffusion Lab    Osmosis is a process where molecules pass through a semi permeable membrane from a less concentrated solution into a more concentrated one‚ equalizing the concentrations on each side of the membrane. Diffusion is the spreading of something more widely.During the osmosis and diffusion lab I tested what happens to a fresh egg when osmosis and diffusion across membranes. The eggs were placed in vinegar‚ distilled water‚ and then lastly syrup. The

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    prelab 8

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    and zinc using titration and precipitation. Procedure: 1) First dissolve the zinc core of a penny and leave copper covering intact by applying four notches in the coin using a triangular file. 2) Place the penny in a 50 mL of a pre-determined concentration of HCl solution overnight. 3) Then determine the percent copper from the mass of copper. 4) Find the percent of zinc by precipitation and titration 5) If there is a known amount of HCl added to the beaker that penny is placed in‚ then determine

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    Osmosis Lab

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    for a period of time in solutions of different water concentrations. Hypothesis: If the potato is immersed into the distilled water‚ then it will be the heaviest out of the three. This is because water is at the lower is moving toward the area of higher concentration‚ which in this case is the potato. This solution is a hypotonic solution which is exactly opposite as a hypertonic because the outside of the cell has a higher concentration of water than the inside‚ and so the water on the outside

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