"Bromination of alkenes" Essays and Research Papers

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    hmmm

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    atoms and label each chiral carbon as (R) or (S). 7. Give the stereochemical relationships (same compound‚ structural isomers‚ distereomers‚ or enantiomers) between each pair of isomers. 8. Consider the following free radical bromination of an enantiomerically pure alkane. Is the product formed as a single enantiomer or a racemic mixture? Is the product optically active or optically inactive? Explain your answers. Substitution and elimination reactions (Chpt 11): 9.

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    g/mol bp 60 °C mp 133-134 °C mp 93-95 °C mp 202-204 °C When an electrophile‚ such as bromine‚ adds to an alkene‚ the addition can be done in a syn fashion‚ in which the two groups add to the same side of the molecule‚ or in an anti fashion‚ in which the groups add to opposite sides of the molecule. Depending on the mode of addition‚ syn or anti‚ and the stereochemistry of the starting alkene‚ various stereoisomers will result. In some cases‚ a racemic mixture of products is formed‚ other times

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    S-20 Week 1 Alkenes: Isomers and Nomenclature 1. There are 6 unique alkene isomers of the hydrocarbon C5H10. Draw each of these isomers‚ and provide a systematic name for each. 1-pentene (E)-2-pentene (Z)-2-pentene 2-methyl-1-butene 2-methyl-2-butene 3-methyl-1-butene 2. For the three alkenes above which are various isomers of pentene‚ rank them in order of stability. Explain your ranking. most stable (more subst. double bond) less stable (cis alkene is slightly less

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    ALKYNES

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    1‚6-Heptadiyne  Common names: prefix the substituents on the triple bond to the name “acetylene” IUPAC name: Common name: 2-Butyne D imethylacetylene 1-Buten-3-yne Vinylacetylene  Physical Properties Similar to alkanes and alkenes of comparable molecular weight and carbon skeleton 2-Butyne 1-Pentyne Melting Point Formula (°C) -81 HC CH CH3 C CH -102 CH 3 CH2 C CH -126 -32 CH3 C CCH3 CH 3 ( CH2 ) 2 C CH -90 1-Hexyne CH 3 ( CH2 ) 3 C CH 1-Octyne

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    I. Abstract The experiment: Classification tests on Organic Compounds‚ allows the students to be familiarized with different classification tests used for identifying the different classes of organic compounds; examine unknown compounds using appropriate tests; and identify functional group of an organic compound based on the tests performed. Several organic compounds with different functional groups were tested to identify the functional groups present in the compound. n-heptane‚ pentene

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    Formal Report

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    Alkyl Halides Alkyl halides are a class of compounds where a halogen atom or atoms are bound to an sp3 orbital of an alkyl group. CHCl3 (Chloroform: organic solvent) CF2Cl2 (Freon-12: refrigerant CFC) CF3CHClBr (Halothane: anesthetic) Halogen atoms are more electronegative than carbon atoms‚ and so the C-Hal bond is polarized. H H μ C + C-l δ δ H The C-X bond is polarized in such a way that there is partial positive charge on the carbon and partial negative charge on the halogen. Dipole moment

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    Chm 1321 Final

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    B) is a deactivator and an o‚p-director. C) is an activator and a m-director. D) is an activator and an o‚p-director. E) none of the above Answer: B 32) Which of the following is an intermediate in the bromination of toluene? A) 13 B) C) D) Answer: B 33) Provide the major organic product of the following reaction. Answer: 14 34) Provide the major organic product which results when PhCHOHCH3 is treated with a chromate (PCC- strong oxidant). Answer:

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    CHEMISTRY

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    Keghan Chapter 8 MULTIPLE CHOICE QUESTIONS Topic: Structure Elucidation 1. An alkene adds hydrogen in the presence of a catalyst to give 3‚4-dimethylhexane. Ozonolysis of the alkene followed by treatment with zinc and acetic acid gives a single organic product. The structure of the alkene is: CH3 A) CH3CH=C-CHCH2CH3 (cis or trans) CH3 CH3 B) CH3CH2C=CCH3 (cis or trans) CH2CH3 C) CH3 CH2=CCH2CHCH2CH3 CH3 CH2 D) CH3CH2CCHCH2CH3 CH3 CH3 E) CH3CH2CHCHCH=CH2

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    Chlorine and Mark

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    (CH3)2CHO- (d) (CH3)3CO- (Q.11) The correct order of decreasing dipole moment is: ( 1 mark ) (a) CH3Cl‚ CH3Br‚ CH3F (b) CH3Cl‚ CH3F‚ CH3Br (c) CH3Br‚ CH3Cl‚ CH3F (d) CH3Br‚ CH3F‚ CH3Cl (Q.12) HCl and HI do not give anti- markovnikov’s addition to alkenes in the presence of peroxides because: ( 1 mark ) (a) Both are highly ionic (b) One is oxidizing and other is reducing (c) One of the step is endothermic in both the cases (d) All the steps are exothermic in both the reactions.

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    Preparation of 4-bromoaniline Introduction Aromatic compounds tend to undergo electrophilic aromatic substitutions rather than addition reactions. Substitution of a new group for a hydrogen atom takes place via a resonance-stabilized carbocation. As the benzene ring is quite electron-rich‚ it almost always behaves as a nucleophile in a reaction which means the substitution on benzene occurs by the addition of an electrophile. Substituted benzenes tend to react at predictable positions. Alkyl groups

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