# Math 133 Unit 2 Ip

Topics: Y-intercept, Maxima and minima Pages: 3 (312 words) Published: February 2, 2013

1.
a. x-4x=-6

A) 1
B) -10
C) -6
X^2-10x-24=0
(X-4) (x+6)
X-4=0 x=4
X+6=0 x+-6

b. x=7+4=5.5 x=7-4=1.5

x=-b±b2-4ac2a
x= (-7) ± (-7)2-4(3) (20)2a
x=7±64-802a
x=7±-16
x=7+4/2=5.5
x=7-4/2=1.5

c. 10x^2+x-3=0

x=-b±b2-4ac2a
x=-1± (1)2-4(10) (-3)2(10)
x=1±1-12020
x=1±10
x=1+320 = 5
x=1-320= 10

2.
a. (-2.3, 0), (0, 6.3)

b. This is a maximum function.

This is a maximum function because it is at the peak of the parabola.

c. (2, 9)

d. x=2

3.
a. s= -16t^2+64t+25

b. 73 Feet

S= -16◦(1)^2+64◦(1)+25
S= -16+64+25
S=73 feet

c. 2 seconds

-b2a= -642(-16)= -64/-32=2 seconds

d. 89 feet

S= -16*(2)^2+64*(2)+25
S= 64+128+25= 89 feet

4.
a. x | y |
-2 | 4 |
-1 | 0 |
0 | -2 |
1 | -2 |
2 | 0 |
3 | 4 |

Y=x^2-x-2
X=-2 x= -1 x=0 x=1 Y=-2^2-(-2)-2 y= -1^2-(-1)-2 y= 0^2-0-2 y=1^2-1-2 Y=4+2-2 y= 1+1 -2 y= -2 y= 1-1-2 Y=6-2 y= 2-2 y= 0-2 Y=4 y=0 y= -2

X=2 x=3
Y=2^2-2-2 y=3^2-3-2
Y=4-2-2 y=9-3-2
Y=2-2

b. [pic]

c. x intercept is (2,0)
y intercept is (0,-2)