Answers To Wile E. Coyote Group Project Solution
Wile E. Coyote Group Project Solution
Dear Wile E. Coyote:
We have worked to create graphs of the plan without and with the catapult. The 300 comes from the initial height measured in feet and the -16 comes from (1/2) the acceleration of gravity in feet per second^2. The 20 with the catapult comes from the initial velocity of 20 feet per second.
As you can see based on this graph the time the rock will hit the ground is roughly in 4.3 seconds. We can find the exact value by plugging in 0 for H (height), 0 = -16t^2 + 300. We then subtract 300 from both sides and get -300 = -16t^2. We then divide by -16 on both sides and get 18.75 = t^2. Finally we take the square root on both sides or ^ (1/2) and find the time to be 4.330127 seconds.
In this function it appears to hit the ground in 5 seconds. To see if this is true, we just plugged in 5 for t. H = -16(5) ^2 + 20 (5) + 300. H = -400 + 100 + 300. H = -300 + 300 = 0. It seems to be true that the rock will hit the ground in 5 seconds. …show more content…
Weight is not a factor in the speed, but it can be a factor in how much it damages the bird since both of these graphs are based on gravity which is where the -16t^2 comes from. Since the acceleration is double that being -32 feet per second (being the acceleration of gravity). Basically this means that in one second, any object's downward velocity will increase by 32 ft. /s because of gravity. This is just the way gravity works - it accelerates everything at exactly the same rate since it is a constant after all. With no air resistance a feather and a rock would fall at the same rate. We would just recommend a size which doesn’t damage the bird too
Dear Wile E. Coyote:
We have worked to create graphs of the plan without and with the catapult. The 300 comes from the initial height measured in feet and the -16 comes from (1/2) the acceleration of gravity in feet per second^2. The 20 with the catapult comes from the initial velocity of 20 feet per second.
As you can see based on this graph the time the rock will hit the ground is roughly in 4.3 seconds. We can find the exact value by plugging in 0 for H (height), 0 = -16t^2 + 300. We then subtract 300 from both sides and get -300 = -16t^2. We then divide by -16 on both sides and get 18.75 = t^2. Finally we take the square root on both sides or ^ (1/2) and find the time to be 4.330127 seconds.
In this function it appears to hit the ground in 5 seconds. To see if this is true, we just plugged in 5 for t. H = -16(5) ^2 + 20 (5) + 300. H = -400 + 100 + 300. H = -300 + 300 = 0. It seems to be true that the rock will hit the ground in 5 seconds. …show more content…
Weight is not a factor in the speed, but it can be a factor in how much it damages the bird since both of these graphs are based on gravity which is where the -16t^2 comes from. Since the acceleration is double that being -32 feet per second (being the acceleration of gravity). Basically this means that in one second, any object's downward velocity will increase by 32 ft. /s because of gravity. This is just the way gravity works - it accelerates everything at exactly the same rate since it is a constant after all. With no air resistance a feather and a rock would fall at the same rate. We would just recommend a size which doesn’t damage the bird too