Prefixes and Equations 1mL = -1x10 3 L = 0.001L 1 kilometers (1km) = 1000m (1x103 m) 1 kilometer (1KL) = 1000L (1x10 3 L) Prefixes Symbol Numerical Value Scientific Notation Equality Kilo | K | 1000 | 103 | 1km = 1x103m 1m = 1x10-3Km | Mega | M | 1 000 000 | 106 | 1Mg = 1x106g1g = 1x10-6Mg | Giga | G | 1 000 000 000 | 109 | 1Gm = 1x109m1m = 1x10-9Gm | Tera | T | 1 000 000 000 000 | 1012 | 1Ts = 1x1012s1s = 1x10-12Ts | Deci | d | 0.1 | 10-1 | 1dL = 1x10-1L1L = 1x101dL (10dL) | *These
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CHEM 104: General Chemistry II Spring 2014 Exam 1 Version A Instructions: 1. Do NOT open this exam until you are told to do so. Opening the exam before the start of the exam is considered an act of Academic Dishonesty. 2. All answers must be bubbled into the scantron answer sheet. 3. No credit will be given for answers written on this exam. 4. You must use a #2 pencil to bubble in the answers on your scantron. 5. This is a multiple choice exam consisting of 30 questions (7 pages). Each question
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To investigate how does the concentration of Hydrochloric acid affect the rate of reaction? Outline I aim to discover how different concentrations of Hydrochloric acid influence the rates of reaction. In order to carry out this investigation I have decided to use marble chips‚ which I will vary the sizes as powder‚ small chips and large chips. I will also be changing the concentration‚ the different concentrations are as follows 0.2m‚ 0.5m‚ 1m‚ 1.5‚ 2m. I have chosen these concentrations as they
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An investigation in to the rate of reaction Plan: I am going to investigate the rate of reaction. The reaction I will be using is: Calcium Carbonate + Hydrochloric acid ---- Calcium Chloride + water + carbon dioxide. CaCO3 + 2HCl ---- CaCl +H2O + CO2 Measurements and Variables: The variables I have chosen to change is strength of the hydrochloric acid which will be 1 mole‚ 0.7 mole‚ 0.5 mole‚ 0.3 mole and 0.1 mole some variable I will not be using are temperature‚ mass‚ density. The measurements
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[KI] (M) | Initial rate (sec -1) | 1 | .01 | .01 | .002246 | 2 | .01 | .005 | .001348 | 3 | .005 | .01 | .001627 | 4 | .0075 | .005 | .001126 | 5 | .005 | .0075 | .001267 | Order of Reaction: n=1;m=1 R1/R2=.002246/.001348=k[.01][.01]/k[.01][.005] 1.666172=2n n=1 Rate law Expression: Rate=k[FeCl3][KI] Rate Law constant: Trial 1: .002246=k[.01][.01] k=22.46 Trial 2: k=26.96 Trial 3: k=32.54 Trial 4: k=30.027 Trail 5: k=33.787 Average Rate Constant: Trial1+2+3+4+5=145
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Determining the Effect of Arousal on the Heart Rate and Blood Pressure of Adolescent Males Wyatt Griffith and Michaela Rodriguez Wood River High School Hailey‚ ID 83333 ABSTRACT When male adolescents were unknowingly placed in an isolated environment with an attractive woman‚ there wasn’t enough viable data to determine whether or not their blood pressure increased. Based on our limited and unreliable data there is no significant increase in the heart rate or blood pressure of male adolescents when
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apart. Many enduring substances such as rock and water are highly stable. One molecule of methane and two molecules of oxygen yield one molecule of carbon dioxide. Chemists summarize chemical reactions using formulas called chemical equations. Chemical equations generally show the product formed when the
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PLANNING HORIZON a 1. The long-range time period‚ usually the next two to five years‚ over which the financial planning process focuses is known as the: a. planning horizon. b. planning strategy. c. planning agenda. d. short-run. e. current financing period. AGGREGATION b 2. The process by which smaller investment proposals of each of a firm’s operational units are added up and treated as one big project is known as: a. separation. b. aggregation. c. conglomeration. d. appropriation
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Theory There are numerous equations involved in this experiment all of which are important in different ways and are listed below: Equation 1 The first equation of motion for the carriage is: mx.. + cx. + kx = m0eω2sinωt Where: m – Mass of carriage c – Damping coefficient k – Spring stiffness ω – Frequency of input vibrations (Rads/s) m0 – Mass of the out-of-balance rotating masses e – Eccentricity of these masses This is the standard equation of motion for single degree
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Chemistry Practice Test: Ch. 12‚ Kinetics MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) Consider the following reaction: 3A ¬ 2B The average rate of appearance of B is given by D[B]/Dt. Comparing the rate of appearance of B and the rate of disappearance of A‚ we get D[B]/Dt = _____ x (-D[A]/Dt). A) -2/3 B) -3/2 C) +2/3 D) +3/2 E) +1 2) A burning splint will burn more vigorously in pure oxygen than in air because A) nitrogen is a reactant
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