# "Lab Paq Stoichiometry Of A Precipitation Reaction" Essays and Research Papers

1 - 10 of 500 ### Lab Paq Stoichiometry Of A Precipitation Reaction

Ocean County College Department of Chemistry Stoichiometry of a Precipitation Reaction Submitted by Hendy Zelishovsky                                                                                                                                                                               Date Submitted:   4/26/2012 Date Performed:  4/25/2012 Lab Section: Chem-180-DL1         Course Instructor: Dr. Cynthia Spencer                                                             Purpose ...

Premium Calcium, Calcium chloride, Filter paper 553  Words | 3  Pages ### Stoichiometry of a Precipitation Reaction|

.6Name: Danielle Hall|Date: 10.15.2012| Exp 9: Stoichiometry of a Precipitation Reaction|Lab Section: | Data Tables: Step 3: Show the calculation of the needed amount of Na2CO3 CaCl2.H2O(aq)= m/M =1/147 =0.0068 mol CaCO3(s)=0.0068*1/1 =0.0068 mol CaCO3(s)= CaCO3 (s)= CaCO3 mol *CaCO3 g =0.0068 mol*100.01 g =.68 g Step 4: Mass of weighing dish _0.6___g Mass of weighing dish and Na2CO3 __0.72__g Net mass of the Na2CO3 ___0.12_g Step 6: Mass of filter paper...

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Experiment 3: Stoichiometry of a Precipitation Reaction Abstract: In this experiment, the objective is to use Stoichiometry to predict the amount of product produced in a precipitation reaction. We received working knowledge of how to accurately measure reactants and products of the reaction. We then are able to use the data that we recorded to make assessments of the actual yield opposed to the theoretical yield. When we calculated the percent yield we are able...

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Stoichiometry of a Precipitation Reaction March 20,2013 Amber McCollum Introduction Stoichiometry is a branch of chemistry that deals with the quantitative relationships that exist among the reactants and products in chemical reactions To predict the amount of product produced in a precipitation reaction using stoichiometry, accurately measure the reactants and products of the reaction, determine the actual yield vs. the theoretical yield and to calculate the percent yield. The equation...

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﻿Experiment 3: Stoichiometry of a Precipitation Reaction Abstract: In this experiment the objectives were to try and predict the amount of product that was produced in the precipitation reaction of calcium carbonate by using stoichiometry. Then learn how to figure out the actual yield, theoretical yield and percent yield of the experiment. Experiment and Observation: The first step in the experiment was to weigh 1g of CaCl2 +2 H2O, then pour it into the 100mL...

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﻿ Purpose: In this experiment I will predict the amount of product produced in a precipitation reaction using stoichiometry by accurately measuring the reactants and products of the reaction. I will also determine the actual yield vs. the theoretical yield by calculating the percent yield. Materials: 1 Distilled water 1 Paper towels 1 Small paper cup 1 Coffee cup or mug 1 Beaker, 100 mL, glass 1 Funnel 1 Cylinder, 25 mL 1 Goggles-Safety 1 Scale-Digital-500g 1 Weighing boat, Plastic 1 CaCl2·2...

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percent yield. = Actual yield/Theoretical yield x 100 = 0.5/0.68 x 100 = 73.5% Conclusion: The objective of the experiment is to predict the amount of product produced in a precipitation reaction using stoichiometry. Secondly, the experiment accurately measures the reactants and products of a reaction. Also, the experiment is to determine actual yield vs. theoretical yield and to calculate the percent yield. For example in this experiment, we were able to predict that we need 0.72g of...

Premium Calcium, Calcium carbonate, Precipitation 567  Words | 3  Pages ### Lab 3 Stoichiometry Precipitation

The calculations completed for this experiment include determining the amount of Na2CO3 needed to do a full reaction. This was calculated through stoichiometry calculations: Molar mass was first calculated for CaCl2*2H2O Ca = 40.078g Cl2 = 35.453g*2 = 70.906g 2H2 = 1.00794g*4 = 4.03176g 2O = 15.9994g*2 = 31.9988g 40.078g + 70.906g + 4.03176g + 31.9988g = 147.01456g or 147.0 g CaCl2 1g CaCl2 * 2H2O x (1 mol CaCl2 *2H2O/147g CaCl2 *2H2O) = 0.0068 mol of CaCl2*2H2O Molar mass was...

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﻿Stoichiometry lab By: James Stewart Purpose: To calculate mole ratios Introduction: There are two types of chemical analysis; qualitative analysis which is the identification of a substance present in a material, and qualitative analysis which measures the amount of the substance. In this lab, you will perform a quantitative analysis of a two-step reaction. Copper(II) oxide will be synthesized from a known mass of copper(II) sulfate pentahydrate. Using the relationship of the balanced equation...

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Name: Brian James|Date:3/10/13| Exp 9: Stoichiometry of a Precipitation Reaction|Lab Section: 73426| Data Tables: Step 3: Show the calculation of the needed amount of Na2CO3 CaCl2.H2O(aq)= m/M =1/147 =0.0068 mol CaCO3(s)=0.0068*1/1 =0.0068 mol CaCO3(s)= CaCO3 (s)= CaCO3 mol *CaCO3 g =0.0068 mol*100.01 g =.68 g Step 4: Mass of weighing dish _0.6_g Mass of weighing dish and Na2CO3 .72_g Net mass of the Na2CO3 .12_g Step 6: Mass of filter paper...

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