Stoichiometry of a Precipitation Reaction
Experiment 3: Stoichiometry of a Precipitation Reaction
Abstract: In this experiment, the objective is to use Stoichiometry to predict the amount of product produced in a precipitation reaction. We received working knowledge of how to accurately measure reactants and products of the reaction. We then are able to use the data that we recorded to make assessments of the actual yield opposed to the theoretical yield. When we calculated the percent yield we are able to see how accurate the data we recorded is.
Experiment and Observation: The first thing we needed to do for this experiment was to weigh 1.0 g of CaClᴤ ˣ 2HᴤO and placed it into a 100 mL beaker. Next we measured 25 mL of water and added it to the beaker with the calcium chloride dihydrate and stirred until the granules were dissolved and mixed with the water. The water became slightly cloudy. Next we had to figure out how much NaᴤCoᴣ we needed for this experiment. I know that for this we need mass/molar mass and that equals 1.0/147.015=.006802 mol. Next we use the mol which is .006802 and multiply by the molar mass which equals: .006802 ͯ 105.99= .72 g of CaClᴤ * 2HᴤO. We could then pour this into the beaker with the calcium chloride dihydrate solution. Instantly, the solution turned milky white. I then folded my filter and placed the filter into the funnel and poured the milky solution into the filter lined funnel. The liquid poured through into the paper cup inside the coffee mug. It filtered slowly and I had to continually stop to allow the liquid to drain once all the milky solution went into the liner I waited until no more water was dripping from the funnel. Finally, I was able to remove the filter and placed it on a folded paper towel until dried completely. While I was waiting for the filter to completely dry I calculated the theoretical yield. To do this we use: 1g CaClᴤ*2HᴤO * (1 mol CaClᴤ*2HᴤO/147.015 g CaClᴤ*2HᴤO) * (1 mol CaCOᴣ/1 mol CaClᴤ*2HᴤO) *
Abstract: In this experiment, the objective is to use Stoichiometry to predict the amount of product produced in a precipitation reaction. We received working knowledge of how to accurately measure reactants and products of the reaction. We then are able to use the data that we recorded to make assessments of the actual yield opposed to the theoretical yield. When we calculated the percent yield we are able to see how accurate the data we recorded is.
Experiment and Observation: The first thing we needed to do for this experiment was to weigh 1.0 g of CaClᴤ ˣ 2HᴤO and placed it into a 100 mL beaker. Next we measured 25 mL of water and added it to the beaker with the calcium chloride dihydrate and stirred until the granules were dissolved and mixed with the water. The water became slightly cloudy. Next we had to figure out how much NaᴤCoᴣ we needed for this experiment. I know that for this we need mass/molar mass and that equals 1.0/147.015=.006802 mol. Next we use the mol which is .006802 and multiply by the molar mass which equals: .006802 ͯ 105.99= .72 g of CaClᴤ * 2HᴤO. We could then pour this into the beaker with the calcium chloride dihydrate solution. Instantly, the solution turned milky white. I then folded my filter and placed the filter into the funnel and poured the milky solution into the filter lined funnel. The liquid poured through into the paper cup inside the coffee mug. It filtered slowly and I had to continually stop to allow the liquid to drain once all the milky solution went into the liner I waited until no more water was dripping from the funnel. Finally, I was able to remove the filter and placed it on a folded paper towel until dried completely. While I was waiting for the filter to completely dry I calculated the theoretical yield. To do this we use: 1g CaClᴤ*2HᴤO * (1 mol CaClᴤ*2HᴤO/147.015 g CaClᴤ*2HᴤO) * (1 mol CaCOᴣ/1 mol CaClᴤ*2HᴤO) *