Preview

Operational Efficiency and Operational Optimization Questions and Answers

Better Essays
Open Document
Open Document
1389 Words
Grammar
Grammar
Plagiarism
Plagiarism
Writing
Writing
Score
Score
Operational Efficiency and Operational Optimization Questions and Answers
Operational Efficiency & Operational Optimization

Sa – Situation Anlysis

Pa – Problem Analysis

Da – Decission Analysis

Pa – Probabilty Analysis

1) Suppose that a peak harvest-season day involves 18,000 barrels of berries, 70% of them wet harvested, arriving uniformly over a twelve-hour period from 7 a.m. to 7 p.m., and process initiates as soon as the first truck arrives.

a) At what time during the day, would the trucks start queuing up to upload?

Answer: - Trucks carrying wet berries will have to wait to unload during the day because the incoming arrival rate is 1050 is greater than processing rate 600. The Trucks arriving with dry berries will not have to wait as processing is greater than arrival. Also, if Maximum storage capacity is been used for storing wet berries then total available will be 3200 bbls. Assuming all storage was empty @ 7:00 A.M , trucks delivering wet berries would have to start waiting after 10:00 A.M as the bins would be full (3200/1050 – 3.04 hours) Also, the Processing will be completed at 4:00 A.M on Peak Harvest Day assuming that work will start at 7:00 A.M

This has been assumed with following Logic – Considering that each truck carried the same number of Barrels; 1500 barrels (18,000/12) are delivered every hour over a period of 12 hours. Each truck will contain 1050 barrels (70%) of wet berries and 450(30%) barrels of dry berries. Thus, the total input for the day will be 12,600(70% of 18000) of wet berries and 5400(30% of 18000) of dry berries.

Since the process capacity is of bottleneck, the capacity of the cranberry process is 600 bbls/hour. Also, we have to take note that only wet berries go through the drying process and thus the processing of the dry berries are not affected by this. The process capacity of processing dry berries alone would be 1200 bbls per hour (Bottleneck = Quality Grading). However, even with the capacity of 1200 bbls per hour, all dry berries received

You May Also Find These Documents Helpful

  • Powerful Essays

    On an average busy day, 18,000 bbl arrive over the 12-hr period. Thus, we can say that 1,500 bbl arrive every hour. Since 75% of the berries are wet berries, 1,125 bbl of wet berries and 375 bbl of dry berries arrive every hour. These berries are dumped into 5 Kiwanee Dumpers that take 600 bbls per hour each.…

    • 1348 Words
    • 5 Pages
    Powerful Essays
  • Good Essays

    Spmproject File

    • 667 Words
    • 3 Pages

    The maximum long-term achievable throughput rate is determined by the resource with the least capacity. As different process routes are followed by dry and wet berries, there will be distinct and separate maximum achievable throughput rates for these two products. The capacity of the dryers is the bottleneck for the wet berries. Therefore, the maximum throughput for wet berries is 600 bbls/hr. As for dry berries, the separation process is the bottleneck. The maximum throughput for dry berries will therefore be 1200 bbls/hr.…

    • 667 Words
    • 3 Pages
    Good Essays
  • Satisfactory Essays

    Hog Problem

    • 370 Words
    • 2 Pages

    The next recommended step is to turn this data into a specific number of loads, and then assign the loads to trucks, and see how many we would need to complete that particular days required shipping (see appendix- TABLE D).…

    • 370 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    ECO 550 FINAL EXAM

    • 1177 Words
    • 4 Pages

    4. The production manager for Beer etc. produces 2 kinds of beer: light (L) and dark (D). Two resources used to produce beer are malt and wheat. He can obtain at most 4800 oz of malt per week and at most 3200 oz of wheat per week respectively. Each bottle of light beer requires 12 oz of malt and 4 oz of wheat, while a bottle of dark beer uses 8 oz of malt and 8 oz of wheat. Profits for light beer are $2 per bottle, and profits for dark beer are $1 per bottle. If the production manager decides to produce of 0 bottles of light beer and 400 bottles of dark beer, it will result in slack of…

    • 1177 Words
    • 4 Pages
    Good Essays
  • Satisfactory Essays

    3. Suppose that a peak harvest-season day involves 18,000 barrels of berries, 70% of them wet harvested, arriving uniformly over a…

    • 1037 Words
    • 5 Pages
    Satisfactory Essays
  • Powerful Essays

    Dermaplus Analysis

    • 1521 Words
    • 7 Pages

    Information in terms of the recommended average daily production capacity in units for the next 12 months will be provided in order to set the size of the plant’s unionized workforce. The assumption is the quantity of units identified used to set the size of the workforce will maximize daily profit.…

    • 1521 Words
    • 7 Pages
    Powerful Essays
  • Good Essays

    On average, 18000 barrels arrive over the 12hr span that the business is open. This means approximately 1500 barrels of berries are input into the process per hour (18000barrels/12hrs). The capacity of the Kiwanee dumpers was given as 3000 b/hr., and I was able to calculate the implied utilization by dividing the berry input rate by the capacity(1500bbl/hr divided by 3000bbl/hr). To calculate the actual utilization of the dumpers, you must first determine the flow rate of the system. Only 25% of the berries are dry and 75% are wet. This sums to 375 dry berries per hour (1500 input/hr x.25) and 1125 wet berries per hour (1500 input x .75). The dry berries have 16 bins that hold 250 barrels a piece, adding up to a total of 4000 berries that can be stored. The wet berries have 8 bins that hold 250 barrels and 3 bins that hold 400 barrels, adding up to 3200 barrels total for storage. The capacity of the DeStoners was given as 1500bbl/hr. The implied utilization would be the input rate (1500bbl/hr) divided by the capacity (1500 bbl/hr). Since the bottleneck does…

    • 1003 Words
    • 5 Pages
    Good Essays
  • Satisfactory Essays

    Bob goes to school

    • 273 Words
    • 2 Pages

    capacity and utilization of each of the operations. Show the flows of wet and dry berries…

    • 273 Words
    • 2 Pages
    Satisfactory Essays
  • Good Essays

    The resource with least capacity determines the maximum long-term achievable throughput rate. Because wet and dry berries follow different routes at RP#1 there will be a maximum achievable throughput for each. The capacity of the dryers is the bottleneck for the wet berries. The maximum throughput for wet berries is 600 bbls/hr. For dry berries the separation process is the bottleneck. The maximum throughput for dry berries is 1200 bbls/hr.…

    • 1103 Words
    • 5 Pages
    Good Essays
  • Good Essays

    Exam 2 Operations Management

    • 2658 Words
    • 11 Pages

    Best operating level is the volume of output at which average unit cost is minimized.…

    • 2658 Words
    • 11 Pages
    Good Essays
  • Satisfactory Essays

    A bakery buys sugar in 15-pound bags. The bakery uses 5000 bags of sugar each year. Carrying costs are $20 per bag per year. Ordering costs are estimated at $5 per order. Assume that the bakery is open 250 days a year and its daily demand is estimated at 20 bags. It takes 5 days for each order of sugar to be filled.…

    • 1687 Words
    • 12 Pages
    Satisfactory Essays
  • Good Essays

    Ncc Case

    • 1281 Words
    • 6 Pages

    As the Drying station is the bottleneck, it would be enough to consider only the wet berries processing capacities into consideration to estimate the…

    • 1281 Words
    • 6 Pages
    Good Essays
  • Satisfactory Essays

    Cranberry Case

    • 730 Words
    • 3 Pages

    (1)However, it assumes exactly 70 percent of all berries will be wet on each peak day. This effect is very important. Because most of the highest volumes ovvur early in the peak season, recognizing this effect in the analysis may reduce the need for new dryer cpacity.…

    • 730 Words
    • 3 Pages
    Satisfactory Essays
  • Good Essays

    2. We assume we are open 4 hours each night. Using Question 1, we know we need 16 + 10xN minutes to fill a N dozens rush order. We want to maximize N knowing we have to have 16 + 10xN < 240. We easily find N = 22. We can fill 22 orders in a night.…

    • 1260 Words
    • 6 Pages
    Good Essays
  • Good Essays

    Mushroom Spawn Production

    • 1652 Words
    • 7 Pages

    (1) To produce 200 spawn bottles of two shift i.e. 5,000 bottles of spawn assuming 25 working days per month.…

    • 1652 Words
    • 7 Pages
    Good Essays