Chromatography of Dyes

Topics: Dye, Food coloring, Analytical chemistry Pages: 2 (492 words) Published: April 26, 2005
Separation and identification of components of a mixture was determined by using Chromatography. The components of a mixture have different affinities for a stationary phase as well as different affinities for a mobile phase.

An extremely common technique by using two chemicals and filter paper can give you sufficient information. A well-done Chromatography of dyes will provide you with enough data to determine if a liquid mixture is heterogeneous or homogenous . In a learning activity you can separate and possibly identify food dyes in some drinks mixes and food colors. The effect of solvent polarity or the ability to separate and elute compounds will also be demonstrated. In this experiment you will need to use the equation Xcm/Acm=RF value. The length of A, is the length of the longest line of the food dye or food coloring. The Length of X is the length of all the other variables. In the experiment the lengths will be measured in Centimeters.

Experimental Procedure
You will need to obtain a piece of standard filter paper approximately 10*15 cm. Use a pencil to draw a line parallel to one of the longer edges, about 1 cm from the edge. Make 10 dashes on the pencil line, be sure to have them evenly distributed. At this point you will spot each of the 5 standards on separate dashes. Be sure to write down which liquid is at which dash. Then choose two food colors and two drink mixes, and spot them on the remaining four dashes. Curl the filter paper into a cylinder, make sure colors out, and staple the edges together. Do not allow the edges of the filter paper to overlap. Add approximately 10 ml of a 7:3 isopropanol:water mixture to your 600 mL beaker, then carefully place the chromatogram into the beaker the colored spots must be higher than the solvent. Be sure to cover the beaker, remove, lay out to dry then measure when the solvent is 1 to 2 cm from the top. Repeat all the above steps but use 0.1% NaCl in the place of the 7:3...
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