14) SA= Pi•r (r+l) *where Pi is multiplied to radius and multiplied to the sum of the measurements of the radius and slant height ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ For Sphere SA=4•Pi•r^2 *where the SA is 4 times the product of Pi and the square of the radius of sphere
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ancient times. Some of them went as far back as Babylon. In his theory’s and writings her explains how to come up with the area and or volumes of different plane and solid figures. In book one their is also an iterative method to approximating the square root of a dumber to arbitrary accuracy. It is an interesting fact that computers today use a very similar method. Heron’s formula of a the area of a triange was different then other formulas because it used “half of the base times the height or half
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My Ideal Room My ideal room is in a gigantic mansion located in a beautiful island down the coast of South America‚ which is a tropical‚ warm and extremely relaxing and calming environment. My room is large and spacious about 100 meters square in area and 10 meters high. Its a rectangle shape. Its located on the second floor of the mason. Oxygenated from the three sides‚ it has a total of 8 large windows allowing cool breeze and sunlight to flow in. All windows have two pink wooden shutters
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area‚ I will begin reviewing the concept of finding the area of a two-dimensional object such as a square or rectangle‚ and remind them of the formula for area is length times width (LxW). Next‚ I will begin to link this review with the new concepts. For instance‚ if the length of each side of the square which forms one of the cubes faces is three inches‚ then the area of one of the faces or squares is 3x3 equaling 9. I will then explain to students that to figure the surface area they will need to
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Title of Project An investigation into a quadratic expression used to represent a parabolic edge in designing a flower garden utilizing calculus to determine the maximum area of the lawn Purpose of the Project Mr. Jack is an avid gardener and he is considering a new design for his garden. He has a rectangular lawn measuring 5 metres by 3 metres and wants to dig up part of it to include a flower bed. He desires to have a parabolic edge for the flower bed as shown below in Figure 1.
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QUADRATIC FUNCTIONS (WORD PROBLEMS) 1. The area of a rectangle is 560 square inches. The length is 3 more than twice the width. Find the length and the width. Representation: Let L be the length and let W be the width. The length is 3 more than twice the width‚ so The area is 560‚ so Equation: Plug in and solve for W: Solution: Use the Quadratic Formula: Since the width can’t be negative‚ I get . The length is 2. The hypotenuse of a right triangle is 4 times the smallest side. The third
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Chapter Test Area Results of the quiz. 1. Find the area of ΔABC. The figure is not drawn to scale. * CORRECT: 23.14 cm2 2. Find the area of a parallelogram with vertices at P(–8‚ –3)‚ Q (–7‚ 3)‚ R(–9‚ 3)‚ and S(–10‚ –3). * CORRECT: 12 square units 3. A slide that is inches by inches is projected onto a screen that is 3 feet by 7 feet‚ filling the screen. What will be the ratio of the area of the slide to its image on the screen? * CORRECT: 1 : 12‚544 4. Find the area of the triangle
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Laws of Exponents Here are the Laws (explanations follow): Law | Example | x1 = x | 61 = 6 | x0 = 1 | 70 = 1 | x-1 = 1/x | 4-1 = 1/4 | | | xmxn = xm+n | x2x3 = x2+3 = x5 | xm/xn = xm-n | x6/x2 = x6-2 = x4 | (xm)n = xmn | (x2)3 = x2×3 = x6 | (xy)n = xnyn | (xy)3 = x3y3 | (x/y)n = xn/yn | (x/y)2 = x2 / y2 | x-n = 1/xn | x-3 = 1/x3 | And the law about Fractional Exponents: | | | Laws Explained The first three laws above (x1 = x‚ x0 = 1 and x-1 = 1/x) are just part of
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rectangle are parallel and equal in length‚ All angles are equal to 90°. c) Square Opposite sides of a square are parallel and all sides are equal in length‚ All angles are equal to 90°. d) Rhombus All sides of a rhombus are equal in length‚ Opposite sides are parallel‚ Opposite angles of a rhombus are equal‚ The diagonals of a rhombus bisect each other at right angles. Rectangles‚ squares and rhombuses are parallelograms. 2.Other Quadrilaterals Other quadrilaterals
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recognizes what a cube looks like‚ able to identify the length of one side‚ know that a cube has six equal sides‚ and the students will needs to be able to calculate the area of a square in order to calculate the surface area of a cube. Students will also need to recall that 3-dimensional objects are measured out in “square units.” Forming the Cube First students will learn that 2-dimensional objects are flat and only deal with length and width; whereas 3-dimensional deal with length‚ width
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