KINETIC ENERGY Objects have energy because of their motion; this energy is called kinetic energy. Kinetic energy of the objects having mass m and velocity v can be calculated with the formula given below; K=1/2mv² Kinetic energy is a scalar quantity; it does not have a direction. Unlike velocity‚ acceleration‚ force‚ and momentum‚ the kinetic energy of an object is completely described by magnitude alone. Like work and potential energy‚ the standard metric unit of measurement for kinetic energy
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UIC PHYSICS 105 Spring 2013 Practice Exam 1 UIC Physics 105 Midterm Practice Exam 1 Spring 2013 Best if used by February 17 PROBLEM Multiple Choice Short Problem 1 Short Problem 2 Short Problem 3 Short Problem 4 Short Problem 5 Short Problem 6 Total POINTS 40 10 10 10 10 10 10 100 SCORE Page 1 of 11 UIC PHYSICS 105 Spring 2013 Practice Exam 1 MULTIPLE CHOICE QUESTIONS (2 points each) Clearly circle the letter of the best answer MCQ 1: The figure to the right represents
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Research for Kinetics Coursework http://www.google.co.uk/#sclient=psy-ab&hl=en&rlz=1R2ADRA_enGB386&source=hp&q=An+investigation+into+the+kinetics+of+the+reaction+between+potassium+peroxodisulphate+and+potassium+Iodide&pbx=1&oq=An+investigation+into+the+kinetics+of+the+reaction+between+potassium+peroxodisulphate+and+potassium+Iodide&aq=f&aqi=&aql=1&gs_sm=e&gs_upl=4649l5023l3l5663l2l0l0l0l0l0l0l0ll0l0&rlz=1R2ADRA_enGB386&bav=on.2‚or.r_gc.r_pw.&fp=4cbda8eccdfde5e1&biw=1280&bih=600 http://www.chemistry-react
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Part One: The friction model is the idea that there are various sources that work together to keep policies in place so that the status quo prevails for extended periods of time. There are many different players within the friction model that try to help protect the status quo‚ but other ideas that try to go against the model and change it. The friction model has a head start as it is much easier to protect the status quo than to change it. A major problem policy changer’s face is lack of attention
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Tro’s Chemistry Chapter 13 – Chemical Kinetics Page 1 of 13 Acknowledgements: Many of the images are adopted from Tro’s textbook‚ the only purpose of which is to enhance student learning. Key terms‚ concepts‚ skills: Refer to pp 599 – 601. Review questions: 3 – 24. Suggested problems: 25‚ 27‚ 33‚ 39‚ 43‚ 53‚ 57‚ 59‚ 69‚ 73‚ 75‚ 81‚ 93‚ 103. 13.1 & 2 Introduction to the Rate of a Chemical Reaction • kinetics is the study of the factors that affect the speed of a reaction and the mechanism by
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ME313L Fluid Mechanic Lab Manual (DRAFT) Pipe Friction Experiment Object: The friction loss in a small-bore horizontal pipe is to be determined over a wide range of Reynolds number. Both laminar and turbulent flow regimes are to be studied. Equipment: Air valve Water manometer Mercury U-tube Isolating tap meter From water supply Needle valve Test tube Figure 1 Pipe friction apparatus A. Laminar Flow The laminar pipe friction apparatus is shown above. It consists of a water loop. The
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Physics Review Notes 2007–2008 Tom Strong Science Department Mt Lebanon High School strong@dementia.org June‚ 2008 The most recent version of this can be found at http://www.tomstrong.org/physics/ Chapter 1 — About Science . . . . . . . . . . . . . . . . . . . . . . . . . . Chapter 2 — Linear Motion . . . . . . . . . . . . . . . . . . . . . . . . . . Chapter 3 — Projectile Motion . . . . . . . . . . . . . . . . . . . . . . . . Chapter 4 — Newton’s First Law of Motion - Inertia . . . . .
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Life Without Friction By: Anthony Cacciato Life without friction would be dangerous. There would be things flying all around and no one would be safe from an airborne bicycle. You would not even be able to stand on your feet. You would not be able to eat or drink. Life with no friction would be deadly. Nothing would be able to sustain life without friction. We would all die if out of the blue friction went away. There are four kinds of friction and they all help us go throughout our daily lives;
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ENGR 210 - Statics Tutorial 1 Your Name: Partner’s Names: Section:_____________ _______________________ _________________ _________________ _________________ _________________ _________________ _________________ VECTORS This assignment will introduce the use of the Cartesian Coordinate System‚ vector notation‚ and properties of vectors to find corresponding unit vectors and resultant forces. The dot product will also be introduced. Each group will choose the origin of a coordinate system in
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Engineering Mechanics - Statics Chapter 1 Problem 1-1 Represent each of the following combinations of units in the correct SI form using an appropriate prefix: (a) m/ms (b) μkm (c) ks/mg (d) km⋅ μN Units Used: μN = 10 −6 N km μkm = 10 9 −6 Gs = 10 s ks = 10 s mN = 10 ms = 10 Solution: ( a) m 3m = 1 × 10 ms s m km =1 ms s ( b) μkm = 1 × 10 μkm = 1 mm ( c) ks 9 s = 1 × 10 mg kg ks Gs =1 mg kg ( d) km⋅ μN = 1 × 10 −3 −3 −3 3 N s −3 m mN km⋅ μN = 1 mm⋅ N 1 ©
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