QUADRATIC EQUATIONS Quadratic equations Any equation of the form ax2 + bx + c=0‚ where a‚b‚c are real numbers‚ a 0 is a quadratic equation. For example‚ 2x2 -3x+1=0 is quadratic equation in variable x. SOLVING A QUADRATIC EQUATION 1.Factorisation A real number a is said to be a root of the quadratic equation ax2 + bx + c=0‚ if aa2+ba+c=0. If we can factorise ax2 + bx + c=0‚ a 0‚ into a product of linear factors‚ then the roots of the quadratic equation ax2 + bx + c=0 can be found
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6 Systems Represented by Differential and Difference Equations Recommended Problems P6.1 Suppose that y 1(t) and y 2(t) both satisfy the homogeneous linear constant-coeffi cient differential equation (LCCDE) dy(t) + ay(t) = 0 dt Show that y 3 (t) = ayi(t) + 3y2 (t)‚ where a and # are any two constants‚ is also a solution to the homogeneous LCCDE. P6.2 In this problem‚ we consider the homogeneous LCCDE d 2yt + 3 dy(t) + 2y(t) = 0 dt 2 dt (P6.2-1) (a) Assume that a solution to
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Maxwell’s EquationsMaxwell’s equations represent one of the most elegant and concise ways to state the fundamentals of electricity and magnetism. From them one can develop most of the working relationships in the field. Because of their concise statement‚ they embody a high level of mathematical sophistication and are therefore not generally introduced in an introductory treatment of the subject‚ except perhaps as summary relationships. These basic equations of electricity and magnetism can be used
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THE MOLE CONCEPT References : Mohammed and Lambert ( Old Edition) Chapter 11 pg. 107 Mohammed and Lambert ( New edition) Chapter 8 pg 123 Anne Tindale Chapter 10 pg 46 The following topics will be covered : 1. Definition of Relative Atomic and Relative Molecular Masses. 2. Calculation of Relative Molecular Masses 3. Converting Moles to Grams / Grams to Moles 4. Calculation from equations Masses of substances /Volumes of gases / Concentration
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Cause and Effect on The Cold Equation In the story "the Cold Equation" by Tom Godwin‚ the author created a cause and effect relationship by having Marilyn decide to stowaway on the emergency dispatch ship that only has enough fuel for one person. Because Marilyn decided to stowaway she ended her own life‚ forced Barton to deal with having to kill a woman‚ negatively affects the results of the mission to Woden‚ and for her parents and brother to deal with her death. Marilyn’s last moments of her life
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of each element in BaCo3‚ assume we have 1 mole of BaCo3‚ we have M(Baco3)g=137.3+12.0+3x16.0=197.3g/mol so we have 197.3g Baco3 so 1mol of Ba=…… 8. %element=m(element)/m(compound)x100% 9. Empirical formula-----simplest whole number ratio Metallic elements and ionic substances--- EF=formula Covalent substances---EF may be the same or simple whole number ratio of the empirical formula. 10. mass(g) m/M moles(mol) divide by smallest simplest mole ratio-----EF 11. If it doesn’t give the exact
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Accounting is founded on the basic equation that states a company’s Assets equal their total Liabilities plus their total Owner’s Equity . This equation is summarized as ALOE . This isthe basis of the Balance Sheet.Assets are the company’s furniture‚ fixtures and equipment‚ physical property‚ intellectual property and other resources. These properties include the physical land as well as the equipmentand building improvements on the property.A company’s liabilities
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This article is about quadratic equations and solutions. For more general information about quadratic functions‚ see Quadratic function. For more information about quadratic polynomials‚ see Quadratic polynomial. A quartic equation is a fourth-order polynomial equation of the form. A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and (the first power of) a single variable. Monomial – is a polynomial with only one term. Binomial
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ME 381 Mechanical and Aerospace Control Systems Dr. Robert G. Landers State Equation Solution State Equation Solution Dr. Robert G. Landers Unforced Response 2 The state equation for an unforced dynamic system is Assume the solution is x ( t ) = e At x ( 0 ) The derivative of eAt with respect to time is d ( e At ) dt Checking the solution x ( t ) = Ax ( t ) = Ae At x ( t ) = Ax ( t ) ⇒ Ae At x ( 0 ) = Ae At x ( 0 ) Letting Φ(t) = eAt‚ the solution
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| | |Assignment title | | | | |Simultaneous Equation | | |Programme (e.g.: APDMS) |HND CSD | | |Unit
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