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    answers on a separate sheet of paper‚ not squished in the spaces on these pages. When relevant‚ data collected should be presented in a table. Objective: To explore the acceleration and force of an object that travels a circular path at constant speed. Motion of this kind is called uniform circular motion. Part 1: Centripetal Acceleration 1. The Gizmotm shows both a top view and a side view of a puck constrained by a string‚ traveling a circular path on an air table. Be sure the Gizmo has these settings:

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    Stupid Ticker Tape 2

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    a = = (Acceleration) b. a = Δv = vf – vi = – = Δt = tf – ti = 0.525s – 0.4s = 0.125s a = = (Deceleration) c. a = Δv = vf – vi = – = Δt = tf – ti = 1.1s – 0.55s = 0.55s a = = (No acceleration) b) Questions a => g a. Our line of best fit (in each section‚ in this case section a) is a straight line. This indicates that there was constant positive acceleration b. a = Δv = vf – vi = – 0 = Δt = tf –

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    E102

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    motion are time‚ position‚ displacement‚ velocity and acceleration. Newton has described objects in motion in balanced and unbalanced state. There is equilibrium to the object with balanced forces that are acting on it. He said that the object will never accelerate if there will be no net force acting on it. Thus‚ the velocity is constant and its acceleration is always zero. In the Second Law of Motion‚ he showed that an object will have acceleration due to unbalanced forces acting on it. There are two

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    Tasneen Ahsan Date: 19th November‚ 2012 Purpose To show how the acceleration of an object changes when‚ the mass changes and the net force is kept constant and when the mass is the same.. Hypothesis I predict that by changing the mass of the object will result in a change in the acceleration as Newton`s second law states that the magnitude of the acceleration of any object is directly proportional to the magnitude of the net force‚ and inversely proportional

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    Force and Acceleration

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    force and motion I problem 1 The figure below is an overhead view of a 12 kg tire that is to be pulled by three ropes. One force (Fl‚ with magnitude 50 N) is indicated. Orient the other two forces F2 and F3 so that the magnitude of the resulting acceleration of the tire is least‚ and find that magnitude if (a) F2 = 30N‚ F3= 20 N; (b) F2= 30 N‚ F3 = 10 N; and (c) F2 = F3 = 30 N. problem 2 A weight-conscious penguin with a mass of 15.0 kg rests on a bathroom scale (see figure below). What are (a)

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    Physics Lab Report

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    first experiment‚ one dimensional motion of a small cart on an air track is measured in a one photogate system. The acceleration was calculated by the infrared light emitting electrode of the photogate sensing the slacks on the picket fence. The calculation for gravity yielded 9.63 m/s^2‚ which is consistent with the accepted value of 9.8m/s^2. In the second experiment‚ acceleration of a cart traveling down a slight incline was measured with a two photogate method. Gravity was calculated and yielded

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    units of measurement

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    differ only in the scale of two out of the three base units (centimeter versus meter and gram versus kilogram‚ respectively)‚ while the third unit (second as the unit of time) is the same in both systems. Sub-outcome 3: Derive units of speed‚ acceleration‚ force‚ density‚ area‚ volume from basic units. The Derived Units: From the base SI units‚ many units for other physical quantities were derived. A derived unit is a unit that is defined by a simple combination of one or more of base units

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    MP trial assignment

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    equilibrium before the next heartbeat.) A graph of acceleration of the table versus time‚ termed a ballistocardiogram‚ is generated. Based on these measurements‚ the acceleration of the blood ejected by the heart can be determined. Patients with low blood accelerations generally have weakened heart muscles. A sketch of a single cycle of a ballistocardiogram is given in the figure. . The units of the graph are arbitrary and linear for both time‚ ‚ and acceleration‚ . Part A At what time (in the arbitrary

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    Physics Lab

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    hit the ground exactly. 3. When counting the dots we could have missed counted the dots because they were small and faint. Conclusion: The acceleration of the 50 g rate weight was .10 greater than the weight of the 100 g weight; however‚ this is attributed to our sources of error. Therefore‚ we concluded that mass does not affect the acceleration due to

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    physic

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    LAB WRITE-UP NAME: Gabriel-Ohanu Emmanuel PARTNER: Baptiste Gilman TITLE: Graph Matching PURPOSE: The purpose of the experiment was to analyze the motion of a student walking along a straight line in front of the motion detector moving back and forward with different speed trying to match the graph provided. To also understand and interpret graphs of distance vs time and velocity vs time. To also know what the slopes of the each graph represent which tells how far the student travelled

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