error or by a specific request from a user program that an OS service be performed .Dual-mode Operation allows OS to protect itself and other system components whereas Multimode Operation increasingly CPUs support multi-mode operations. System call provides the means for a user program to ask OS to perform OS tasks on the user program’s behalf. When a system callis executed‚ it is treated by H/W as a S/W interrupt. Timer protects CPU resource from getting stuck by a user program. To ensure OS maintains
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Chapter no | Topic | 1 | Introduction‚ Types ‚ Computer System Overview | 2 | Operating System Structure‚ Components and Functions‚ Virtual Machine | 3 | Process Concept‚ Operation‚ Process scheduling‚ symmetric multi -processing‚ Cooperating Processes | 4 | Thread Concept‚ Thread Vs Process‚ IPC ‚kernel ‚microkernel | 5 | Scheduling‚ Types‚ Scheduling in batch‚ interactive and real-time systems (SJN‚ SJF‚ FIFO‚ LJN‚ round-robin‚ priority scheduling‚ and hybrid schemes). | 6 | Deadlock:
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Operating Systems Assignment 1 Session: Summer 2013 Faculty of Information Technology UCP Lahore Pakistan Operating Systems Assignment: Introduction and Overview of Operating Systems 150 MARKS Write in your own words to answer the following‚ if you use material from any book website apart from your recommended book please provide so. All work will be assumed yours otherwise. Justify your answers where needed. Explain briefly and concisely 1. You are to procure Linux
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1. Computer System Components (i) Hardware Provides basic computing resources (CPU‚ memory‚ Input/output (I/O) devices). (ii) Operating System (OS) Controls and coordinates the use of the hardware among the various application programs for the various users. (iii) Applications Programs /Application Software Define the ways in which the system resources are used to solve the computing problems of the users (compilers‚ database systems‚ video games‚ business programs). (iv) Users
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Operating Systems Assignment #5 Of Chapter 4 Eighth Edition of Operating System Concepts by Avi Silberschatz Peter Baer Galvin & Greg Gagne 2009 4.1 Provide two programming examples in which multithreading does not provide better performance than a single-threaded solution Answer: (1) Any kind of sequential program is not a good candidate to be threaded. An example of this is a program that calculates an individual tax return. (2) Another example is a "shell" program such as
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CS 3530 Operating Systems L02 OS Intro Part 1 Dr. Ken Hoganson Chapter 1 Basic Concepts of Operating Systems Computer Systems A computer system consists of two basic types of components: • Hardware components‚ which are the electronic devices and electromechanical devices‚ such as the processors‚ memory modules‚ disk units‚ keyboard‚ screen‚ and other devices. • Software components‚ such as the application programs‚ operating system‚ utilities‚ and other programs. 3 Computer Architecture
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CS 2203: Operating Systems Centre for Advance Studies in Engineering (CASE) Hand-out 8: Lab 08 Instructions March 2014 Computer Science Department Instructor: Shehreyar Rashid Lab 8: Introduction to Java and Sockets Objectives Write‚ compile‚ and execute Java programs in Linux using command line. Use an IDE to write‚ compile‚ and execute Java programs in Linux. Learn to write client-server application using Sockets. Credits: This lab uses material from Silberschatz‚ Galvin
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What are the two differences between user-level and kernel-level threads? Under what circumstances is one type is better than other? Answer: 1- User-level threads are unknown by the kernel‚ whereas the kernel is aware of kernel threads. 2- On systems using either M: 1 or M: N mapping‚ user threads are scheduled by the thread library and the kernel schedules kernel threads. 3- Kernel threads need not be associated with a process whereas every user thread belongs to a process. Kernel threads are
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Chapter 7 Exercise #3 – Given a disk pack with 10 platters yielding 18 recordable surfaces… A = Rotational speed = 10ms B = Transfer rate = 0.1ms/track C = Density per track = 19‚000 bytes D = Number of records to be store = 200‚000 records E = Size of each record = 160 bytes F = Block size = 10 logical records G = Number of tracks per surface = 500 a) Number of blocks per track: (C) / (E*F) 19‚000 / (160*10) 19‚000 / 1600 11.875 11 BLOCKS b) Waste per track: C – (E*F*11)
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Definition of Operating System: An Operating system is a program that controls the execution of application programs and acts as an interface between the user of a computer and the computer hardware. Need of an operating system: When a program written in a high level language is executed by a computer‚ the following steps are followed… The compiler to translate the program is loaded in the memory. The source program is read and loaded in the memory. The source program is compiled into object program
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