HYDROSTATIC FORCE (EXPERIMENT 1) INTRODUCTION The determination of force which are exerted by liquid which are at rest on surface immersed in liquids. From the study by hydrostatic‚ the following principles have been established : a) There are no shear stress present when the fluid is not in motion. b) The pressure exerted by a fluid under hydrostatic conditions. This pressure acts perpendicular to an immersed surface. c) Hydrostatic pressure various linearly‚ increasing with an
Premium Force Fluid mechanics Fluid
September 26‚ 2003 CVEN-3313 Theoretical Fluid Mechanics Module#1: 1 1. OBJECTIVE The purpose of this module is to investigate hydrostatic forces on a plane surface under partial and full submersion. 2 2. DESCRIPTION The apparatus shown in Figure 1 will be used. It consists of a quarter circle block attached to a cantilevered arm with a rectangular surface on the other end. The pivot point on the arm corresponds to the center of radius of the block. With no water
Premium Mass Fluid mechanics Force
have done an experiment on hydrostatics‚ or is also known as fluid statics (fluid at rest) within the fluid mechanics field of study. This condition explains that in a stable condition‚ the fluid is at rest. The use of fluid in doing work is known as hydraulics‚ and the science of fluid in motion is known as fluid dynamics. INTRODUCTION The natural nature of fluids are they cannot remain stationary under the application of shear stress. However‚ fluid can apply force normal to any surface contacting
Premium Fluid mechanics Force Fluid dynamics
Mechanical Engineering: Hydrostatic Force Introduction Hydrostatics is a fundamental aspect of mechanics which consists of the analysis of fluid bodies which are either completely at rest or slow enough for any motion to be neglected during calculations. The concept of hydrostatics has many applications in industry‚ some notable ones being: Manmade dams and water features preventing the passage of water. In this particular example‚ large volumes of water is held back‚ which is eventually released
Premium Mass Hot air balloon Force
Abstract: The previous lab explored the effect of gravity on free fall. It was determined that acceleration is always constant under free fall. However‚ in this lab‚ acceleration was observed under different forces‚ other than just gravity. Therefore‚ depending on how strong the forces being exerted were‚ acceleration differed. It wasn’t constant anymore. Using a glider on a air track and a pulley‚ different masses were attached at the end of the string and the glider was allowed to move on the
Premium Newton's laws of motion Mass Classical mechanics
about the LCF produced by weight additions‚ removals‚ or shifts (wd)‚ where w is the amount of weight added‚ removed‚ or shifted. Moment to Trim One cm (MT1cm): The moment necessary to produce a change in trim (CT) of one cm. Found using the hydrostatic curves. Tons Per cm
Premium Ship Conscription in the United States
Buoyant Forces The purpose of this lab is to calculate buoyant forces of objects submerged in water. The first step in the lab was to measure the mass of a metal cylinder‚ which was found to be 100g‚ and then to calculated it’s weight‚ which was .98 newtons. Then next step was to measure the apparent weight of the cylinder when it is completely submerged in a bath of water using the formula Wa=ma*g ‚ this was found to be 88.5grams. Knowing these two numbers‚ the buoyant force that the water
Premium Force Density Fundamental physics concepts
yields two integrations: x = x0+v0t+1/2at2 v = v9+at These two expressions show the relationship between position‚ velocity‚ and acceleration at a given time. Newton’s 2nd law states that the acceleration of an object depends on the net force acting upon the object and the mass of the object. If there were no friction in this experiment‚ then the acceleration of the glider would be equal to acceleration of gravity multiplied by the angle between the air track and the horizontal table (g
Premium Velocity Derivative Force
Centripetal Force Lab Activity Analysis: 1. A) Average Percent Difference: 50g: (values expressed in newtons) Step 1: Calculate the average value of the two variables Average Value= Value 1+ Value 2 /2 = 0.49+ 0.61/2 = 1.1/2 = 0.55 Step 2: Calculate the difference between the two variables Difference= Value 2- Value 1 = Fc- Fg = 0.61- 0.49 = 0.12 Step 3: Calculate % difference % difference= difference
Free Energy Potential energy Kinetic energy
Purpose To be able to understand and verify the relationship centripetal force‚ mass‚ velocity‚ and the radius of orbit for a body that is undergoing centripetal acceleration. Background Information An object moving in the same direction is not necessarily undergoing acceleration. If the object changes speed while moving in the same direction there is acceleration (or deceleration). On the other hand‚ if the object moves at a constant speed in the same direction‚ there is no acceleration
Premium Kinematics Force Newton's laws of motion