Decomposition of Hydrogen Peroxide by Potassium Iodide Brief Description: Two solutions are mixed resulting in an eruption of foam resembling a huge stream of toothpaste. This is the classic “Elephant Toothpaste” reaction. Purpose/Goal: Procedure presents an example of a catalyzed reaction. Explanation of Experiment: The rapid evolution of oxygen gas is produced by the following reaction: 2 H2O2 (aq) = 2 H2O (l) + O2 (g) + heat The decomposition of hydrogen peroxide in the presence
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Introduction: This experiment will investigate the factors that affect the rate of reaction of the enzyme catalyse‚ an enzyme found in food such as potato and liver. Catalyse is used to remove hydrogen peroxide from cells. The enzyme speeds up the rate of decomposition of hydrogen peroxide into water and oxygen. The reaction is: Catalyse is able to speed up the process because the enzyme lowers the activation energy of the reaction. This means that the free energy required for the reaction
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Chemical Kinetics of Hydrogen Peroxide Decomposition Purpose The purpose of this experiment was to determine the rate equation for the catalyzed decomposition of hydrogen peroxide H2O2. Procedure The procedure for this lab can be found on pages 36 - 40 in “General Chemistry CHE111L Laboratory Manual Spring 2014.” Data Tables Carbon copies of data tables and the graph have been attached to the back of this lab report. Calculations 30 mL of
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kind of role does hydrogen peroxide and a liver have in their chemical reaction? In the experiment‚ we saw they had a reaction‚ but completed further tests to determine whether they changed after the reaction. Hydrogen peroxide is chemically changed into water and the liver is broken down in the reaction. In the experiment‚ a fresh piece of chicken liver was put into a test tube filled with 3% hydrogen peroxide. We knew a reaction was taking place because the hydrogen peroxide started to foam and
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In my coursework I will investigate about enzymes in potatoes reacting with Hydrogen Peroxide. In particular I will investigate the effects of changing the surface area of a potato when added to Hydrogen Peroxide. This is because‚ when increasing the surface area of the potatoes it will increase the rate of reaction because there will be more surface area on which particles from the potato and the Hydrogen Peroxide will collide on‚ and with more surface area there would be more particles carrying
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molecules be exposed to hydrogen peroxide. This will result in the rate of reaction increasing because it increases the chance of more successful collisions between the enzyme and the substrate. Catalase is an enzyme found in food such as‚ potato. It is used to break down a poisonous by-product of metabolism called hydrogen peroxide. Hydrogen peroxide is a compound that can kill cells therefore; it is essential that our body can break it up. Catalase breaks down hydrogen peroxide into oxygen and water
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Effects of Different Concentration of Catalyse on Hydrogen Peroxide Aim: In this investigation I will try to find how long it takes for the filter paper disc to rise up whilst varying the amounts of concentration of catalyse. Prediction: I predict that the lower the concentration of catalyse the longer it will take for the filter paper disc to rise to the surface of the tube. Equipment: 1. Hydrogen peroxide in a container 2. Flat bottom tube 3. Tweezers 4. Filter paper
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Study of the first element – Hydrogen. Answer the following questions:- 1. Give a reason why hydrogen can be placed in group 1[IA] and group 17[vIIA] of the periodic table. 2. What similarities does it show with group 1[IA] and group 17[VIIA]. With special reference to valency electrons and ion formaton and examples. 3. How does hydrogen occur in the free and combined state? 4. Which metals react with cold‚steam and boiling water to form their respected oxides and hydroxides ? Give examples and
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Kinetics of Hydrogen Peroxide February 22‚ 2007 Chem. 1130 TA: Ms. Babcock Room 1830 Chemistry Annex PURPOSE OF THE EXPERIMENT Kinetics of Hydrogen Peroxide The major purpose of this experiment is to determine the rate law constant for the reaction of hydrogen peroxide and potassium iodide. In this experiment‚ the goal will be to try to measure the rate law constant at low acidity‚ since at low acidity‚ anything less than 1.0 x 10-3M‚ the effect of the hydrogen ion is negligible. To calculate
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Abstract The decomposition of hydrogen peroxide (H2O2) in a whole and diced wedges by with The enzyme catalase was observed. The catalase was able to break down the hydrogen peroxide In the diced banana wedge better than the whole banana because after the banana was diced that Increases the surface area allowing the breakdown to flow. The effects of temperature on enzyme In a liver sample were observed under iced‚ boiling‚ 37 degrees‚ and room temperature Conditions. The enzymes became completely
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