Ch. 3, p. 95 Exercise 88
88. Refer to the Baseball 2005 data, which reports information on the 30 major league teams for the 2005 baseball season.
A. Select the variable team salary and find the mean, median, and the standarddeviation.
B. Select the variable that refers to the age the...
normal distribution. Since the standarddeviation is so high (and going even one standarddeviation below average takes you outside of the range of the data: 5 hours below the mean of 4 hours equals –1 hours and is obviously outside the range of the data), it is pretty clear that the histogram for the...
Weight Reducers is less than 10 pounds.
Exercise Question 32: Dole Pineapple, Inc. is concerned that the 16-ounce can of sliced pineapple is being overfilled. Assume the standarddeviation of the process is .03 ounces. The quality control department took a random sample of 50 cans and found...
0
1
Standard Normal Q
(b)
2
−3
−2
−1
0
1
Standard Normal Q
2
(c)
7. The length of human pregnancies from conception to birth varies according to
a distribution that is approximately Normal with mean 266 days and standarddeviation16 days. Let X be the variable...
to his school?
59
Student
John Ali
GPA
2.85 77
School Mean GPA
3.0 80
School StandardDeviation
0.7 10
(Solution to Exercise 2.6 on p. 72.)
Your concentration should be on what the standarddeviation does, not on the arithmetic. The standarddeviation is a number which...
minimum specification are (50,000) × (0.159) = 7950. This exercise may also be solved using Excel or MINITAB: (1) Excel Function NORMDIST(X, µ, σ, TRUE) (2) MTB > Calc > Probability Distributions > Normal
Cumulative Distribution Function
Normal with mean = 40 and standarddeviation = 5 x P( X 48...
up to 140 12
140 up to 160 16
160 up to 180 7
180 up to 200 4
Total 50
a. Estimate the mean cost. The estimated mean cost would be $141.2
b. Estimate the standarddeviation. The standarddeviation is 26.23
c. Use the Empirical Rule to estimate the proportion of costs within two...
a standarddeviation of 13 pounds. A random sample of 40 firefighters taken six months after the program was implemented revealed that the mean of the sample was 192 pounds. Construct a 96% confidence interval for the mean weight of all firefighters six months after the exercise rooms were...
for the weights (kg) of a random sample of 30 first year
university female students. Find the standarddeviation, the variance and the mean.
Graduate’s weight
(kg)
Frequency
Cumulative
frequency
60
2
2
61
14
16
62
8
24
63
1
25
64
5
30
The...
Pineapple, Inc., is concerned that the 16-ounce can of sliced pineapple is being overfilled. Assume the standarddeviation of the process is .03 ounces. The quality control department took a random sample of 50 cans and found that the arithmetic mean weight was 16.05 ounces. At the 5 percent level of...
are 3 and 8.
2) You have been asked to give a student two different tests; an intelligence test and a creativity test. The student scored 123 on the intelligence test and 123 on the creativity test. The mean for the intelligence test is 100, and the standarddeviation is 16...
intervals are called grouped data; whereas ungrouped data are data that are distributed randomly without class intervals.
In statistics, mean, mode, median, range, interquartile range, variance and standarddeviation are used to represent the data collected. The mean of ungrouped data is the...
observations will be below 16 and 25% will be higher than 16.
*
* 4.47 interquartile range
* 2, 5, 6, 8, 9, 10, 11, 14, 18, 21
*
* Coefficient of variation – is the standarddeviation of a set of observations divided by their mean
Measure of Linear Relationship
Two...
GRADE 9/9
Lind Chapter 9; Exercise 12
The American Sugar Producers Association wants to estimate the mean yearly sugar consumption.
A sample of 16 people reveals the mean yearly consumption to be 60 pounds with a standarddeviation of 20 pounds.
a. What is the value of the population mean? What...
above and below the mean? 2 standarddeviations?
3 standarddeviations?
For Exercises 6 through 25, ﬁnd the area under the
standard normal distribution curve.
6. Between z ϭ 0 and z ϭ 1.89
7. Between z ϭ 0 and z ϭ 0.75
8. Between z ϭ 0 and z ϭ Ϫ0.46
9. Between z ϭ 0 and z ϭ Ϫ2.07
10. To the...
-60000)/2000 = 5
* It is unlikely that one truck was above 5 stdevs above the mean. The prob is almost 0.
*
* Exercise 38 (Ch. 8)
38. The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50 with a standarddeviation of $5.00. Assume the distribution of amounts...