"Effect of surface area to volume ration on diffusion time in agar cubes" Essays and Research Papers

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    RELATIONSHIP BETWEEN SURFACE AREA AND THE VOLUME OF A CELL‚ HOW IT AFFECTS THE RATE OF DIFFUSION Nazirul Ibrahim 04.10.2011 DATA COLLECTION AND PROCESSING We have determined the following variables: * dV- the time for the color indicator phenolphthalein to reach the center of the cube (diffusion) * iV- the size of the cube * cV- the amount of Sodium Hydroxide the perfect dimensions of the cube‚ how the cube is fully submerged in the solution‚ the temperature of the cube and the constant

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    Diffusion In Agar Cubes

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    _____Block:______ Diffusion In Agar Cubes Is Bigger Better? OR Is Smaller Smarter? Adapted from Flinn Scientific Publication No. 10110 Introduction: Diffusion is one of the very important processes by which substances such as nutrients‚ water‚ oxygen‚ and cellular wasted are transported between living cells and their environment. This activity will help you explore the relationship between diffusion and cell size by experimenting with model “cells.” In this experiment‚ you will use agar cubes

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    Title: The Effects of Surface Area to Volume ratio in Agar Introduction: What is an efficient way to maximize mass but minimize diffusion time in cell? Answer: An efficient way to maximize mass but minimize diffusion time in a cell is to increase its surface area. If you increase the surface area of a cell relatively to its volume‚ then the diffusion time will decrease. Materials: Agar cubes‚ bromothymol blue- pH indicator‚ vinegar‚ ruler‚ spatula‚ beaker. Methods: I used agar cubes as cell models

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    Affect Diffusion Biology The aim of this investigation is to prove the effect of increasing size on the efficiency of diffusion. Diffusion is the process that cells use to obtain oxygen‚ water and food. Also‚ how they lose waste substances‚ for example‚ urea and carbon dioxide. Basically‚ Diffusion is when particles move from an area of high concentration to an area of low concentration. The surface area to volume ratio of the cell is an important factor in diffusion. It is the effect of this

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    Surface Area of a Cube

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    Task 5: Surface Area of Cubes Introducing Surface Area For a fifth or sixth grade class to understand the concept surface area in relation to a cube they need to understand what a cube is first. They will learn that a cube is a special type of rectangular solid. The length‚ width‚ and height of a cube are exactly the same. After explaining what a cube is they will need to understand what it means to find the surface area. The surface area is not the same as finding the volume of a cube. The surface

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    Surface Area to Volume Ratio and the Relation to the Rate of Diffusion Aim and Background This is an experiment to examine how the Surface Area / Volume Ratio affects the rate of diffusion and how this relates to the size and shape of living organisms. The surface area to volume ratio in living organisms is very important. Nutrients and oxygen need to diffuse through the cell membrane and into the cells. Most cells are no longer than 1mm in diameter because small cells enable nutrients and oxygen

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    Surface area to volume ratio

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    The Effects of the Ratio of Surface Area to Volume on Transformation Efficiency in Escherichia coli K-12 Eliana Pouchard‚ Steve Teng‚ and Cameron Wong Department of Microbiology & Immunology‚ UBC In the process of transformation‚ bact eria take up DNA fr om the environment through their cell wall. To induce competence in the cells‚ the DNA for uptake must first attach to the cell surface prio r to passing throug h the membrane. Previous studies on the effect of surface area

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    Mathematics Volume of Solids Formulae for Volume of Solids Cube | Cuboid | Triangular Prism | Cylinder | Cone | Pyramid | Sphere | AnyPrism | s3 | lwh | ½bhl | Πr2h | 1/3πr2h | 1/3Ah | 4/3πr3 | Ah | A = area of the base of the figure s = length of a side of the figure l = length of the figure w = width of the figure h = height of the figure π = 22/7 or 3.14 1. Compute the volume of a cube with side 7cm. Volume of cube: s3 s = 7cm s3 = (7cm x 7cm x 7cm) = 343cm3 2. Compute

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    Cell Biology- Osmosis‚ Cell Size and Diffusion and Enzymes 1.0 INTRODUCTION Cells are the basic building blocks of all living things. They provide structure for the body‚ take in nutrients from the food‚ convert those nutrients into energy‚ and carry out specialized functions. Cells also contain the body’s genetic material and can make copies of themselves. A cell is also a metabolic compartment where many different chemical reaction occur. There are two types of cells‚ eukaryotic and prokaryotic

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    a statement as to which potato cubes will diffuse the closer to the center of a cell (small‚ medium‚ large. __________________________________________________________________________________________________________________________________________________________________________ Dimensions For Experiment 3 Cubes with sizes A) 0.5 cm B) 1.0 cm C) 2.0 cm Experimental Evidence: 1. Using a razor blade and paper towels‚ carefully cut 3 potato cubes using the dimensions from above

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