N09/4/PHYSI/SPM/ENG/TZ0/XX+ 88096504 Physics standard level PaPer 1 Monday 16 November 2009 (afternoon) 45 minutes INSTRUCTIONS TO CANDIDATES • Do not open this examination paper until instructed to do so. • Answer all the questions. • For each question‚ choose the answer you consider to be the best and indicate your choice on the answer sheet provided. 8809-6504 16 pages © International Baccalaureate Organization 2009 – 2 – 1. N09/4/PHYSI/SPM/ENG/TZ0/XX+ The
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Determining the activation energy in the reaction between crystal violet and sodium hydroxide. I. DESIGN ASPECT 1: definition of the problem‚ hypothesis and selection of variables Problem: How the Arrhenius equation can be used to determine the activation energy in the reaction between crystal violet and sodium hydroxide. Objective: The objective of the experiment is to determine the activation energy. Knowing the rate constant k of reactions between crystal violet and sodium hydroxide at
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Investigating the Water Potential of a Potato. I have been asked to investigate the water potential of a potato. During my investigation I will not actually be able to measure a value for‚ as it is a pressure value (kPa). Osmosis is a special form of diffusion involving only water molecules. It is defined as "The passage of water from a region of high water potential to a region of low water potential through a partially permeable membrane" Definition of Water Potential. The potential for water to move
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Experiment 24 - A Rate Law and Activation Energy Observe • To conduct an experiment in order to discover and calculate the expression known as the rate law for a particular reaction. • To conduct an experiment in order to determine the role each reactant plays within the reaction and the overall activation energy that is needed for a chemical reaction to occur all while utilizing an analytical tool. Procedure 1. Determination of Reaction Rates • Obtain boiled‚ deionized water‚ pipets or burets
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........................................... v Executive Summary........................................................................................ vi Potential Market Segmentation of a Brand New Product Product Potrayal................................................................................. vii Potential Market Segmentation..................................................................... viii Segmentation Profile...........................................
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Introduction Molecules are constantly in motion due to thermal energy. Therefore‚ the molecules will move around and bump into each other. Because of this‚ molecules tend to spread out evenly into available space in a process called diffusion. Diffusion is the random process of molecules moving from areas of high concentration to low concentration‚ thus requiring no energy. Many of the substances that enter or leave the cell do so through diffusion. Osmosis‚ a type of diffusion‚ is the movement
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Osmosis and Water Potential Year 11 Emary Venter INTRODUCTION: The cell is the basic unit of living things‚ and is made up of multiple organelles. Organelles are membrane bound subdivisions‚ each specialised for a specific function. This experiment looks at the Plasma Membrane‚ which is a semipermeable layer surrounding the cell. It’s primary job is to control what goes in and out of the cell. Molecules can move across this membrane in either an active movement or a passive movement
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Danielle Ashworth Mr. Fletcher English 12 AP 18 February 2014 The Potential Destructiveness of Repetition Life is made up of routines and patterns. Every human being has their own unique system of how they carry themselves through the day. These systems are how we survive‚ and they tend to become part of our subconscious. But there are those who get so caught up in their own conformity that daily life becomes much more demanding than it should be. The results of this perpetual routine can
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AN INTRODUCTION. Advertising is a favorable representation of product to make consumer‚ customers and general public aware of product. It let the potential buyers‚ general public and end users to be aware and familiar with the brands and their goods and services. Before going on the importance of advertising‚ we would have an introduction to advertising first. Advertising can be define as a paid
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685N and your belongings have a weight of 915N. How much work does the elevator do in lifting you and your belongings 5 stories (15.2m)? Solution: W= (685N+915N) (15.2m) W= (1600N) (15.2m) W= 24‚320Nm or J Section 2 Gravitational Potential Energy: 6. A 0.15kg ball is thrown 9.0m straight up. What is the work done by the gravitational force? And what is the change in PE? (Notice anything?) Solution: PE= m*a*h PE= (0.15kg) (9.8 m/s^2) (9.0) PE= 13.23 kg m^2/s^2 or J - The
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