Cultural Anthropology Case Study: Cahokia Mounds In southern Illinois in Collinsville‚ the largest prehistoric settlement north of Mexico can be found. This is the Cahokia Mounds State Historic Site which is 4‚000 acres. How Cahokia began and ended to this day is still considered a mystery. The people of Cahokia built more thank 120 earth mounds as landmarks‚ tombs‚ and ceremonial platforms. The largest of these mounds is Monks Mound. It covers more than 14 acres‚ and it once supported a 5‚000-square-foot
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starting puberty; one breast grows larger than the other. In her conversation with herself she knows her innocence has vanished‚ and a development is changing her life once again; the baby growing within her. The circles remind me of life. There is a beginning and an ending. The circles in this painting are in locations of the body that develop at a much faster pace than the
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are going in a circle. The second principal I think of is proximity as the circles are near to each other. The third principal I see is continuity .The rows of circles seem endless. 7. This image represents similarity which is one of Gestalt’s principals. The shadows create almost identical shapes on the wall. 8. This photograph represents more than one of Gestalt’s principles. The whole object can be described as figure and ground as it is obvious that the metal circle is the object
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probability of not guessing the correct answer to the same question is ¾ then the value of P is a) 4 b)2 c) 3 d) 1 4. If p( -1‚1) is the midpoint of the line segment joining A (-3 ‚ 6) and B (1‚ b+4) ‚ then b is a) 1 b) -1 c) 2 d) 0 5. The area of two circle are in the ratio 4 : 9 ‚ the ratio of their circumference is a) 2 :3 b) 3 :2 c) 4 :9 d) 9:4 6. The no. of two digits that are divisible by 6 is a) 12 b) 16 c) 15 d) 18 7. The angle of depression of an object from a 60m high tower is 30O. The distance
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emphasis on trigonometric identities‚ a solution was found. The conclusion reached is‚ “if we are given the coordinate plane positions of billiard ball A with coordinates (xA‚ yA) and billiard ball B with coordinates (xB‚ yB)‚ and also the radius of the circle‚ the solution points are at any of the points of intersection of the circular table with the hyperbola‚ x 2 @ y 2 P + r 2 ` yp @ xm a + xy2M ”‚ where P b c b c b c = y A A xB + yB A x A ‚ M = y A A yB @ x A A xB ‚ p = x A + xB ‚ m = b c `
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objects/actions that would obviously not be used in this scenario. The first few lyrics is "Circles‚ we goin’ in circles" now‚ obviously they’re not walking in actual circles‚ they keep repeating the same problems over and over again‚ They try to fix there problems‚ but whenever they do they end up at the very begging again. This keeps happening‚ the problems‚ them trying to fix it‚ fighting etc. And like a circle it never ends. "Wake up‚ we both need to wake up" once again‚ they’re obviously not actually
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Katie Donald Professor John Weatherford English 1102 9 September 2013 To Mourn or Not To Mourn John Donne’s poem “A Valediction Forbidding Mourning” is a man’s farewell before he departs on a long distance journey. The speaker’s wife is the audience in this dramatic monologue. The speaker metaphorically describes his departure to help him and his lover avoid “mourning‚” as summarized in the title. He assures his lover that he will always love her‚ no matter what physical space separates them
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Circular Motion Uniform circular motion is the movement of an object or particle trajectory at a constant speed around a circle with a fixed radius. The fixed radius‚ r‚ is the position of an object in uniform or circular motion relative to to the center of the circle. The length of the position vector of the circle does not change but its direction does as the object follows its circular path. In order to find the object’s velocity‚ one needs to find its displacement vector over the specific
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Cad Rep Parametrisation Some of the important parameters that I created and then used in my design table and also in the calculations below are as follows: Shaft Radius= Shaft Diameter/2 Gear Circumference= No. of teeth x 10mm Flange Diameter= (2 x Gear Radius) + 10 Hub Diameter= Shaft Diameter x 2 ‘Cut for Shaft’ diameter= Shaft Diameter Hole Diameter= Shaft Diameter Calculations The first calculation was to calculate the Gear Radius (r) using the information provided: The appropriate
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octagon with perimeter 48 cm. * CORRECT: 173.8 cm2 8. Find the area of the circle. Use π = 3.14. * CORRECT: 7.07 m2 9. Find the area of a regular hexagon with an apothem 17.3 miles long and a side 20 miles long. * CORRECT: 1038 mi2 10. A circle with a diameter of 2 inches and a square with 2-inch sides have the same center. Find the area of the region that is inside the square and outside the circle. Use 3.14 for π. * CORRECT: 0.9 in.2 11. Find the area of the rhombus.
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