equation. [3 marks] d) The quality assurance manager of the production plant found out that the method in (c) is not very efficient and has decided to look for an alternative pathway to produce nhexane. He suggested on forming an intermediate step of alkene‚ which later undergoes reduction reaction to form n-butane. Propose two reaction pathways to produce n-butane‚ writing the complete chemical reaction equations. [10 marks] e) n-hexane is a type of alkane. List three physical properties of alkane.
Premium Oxygen Chemistry Atom
The Stereochemistry of Bromine Addition: Bromination of trans-Cinnamic Acid Pitak Chuawong Objectives 1. To perform bromination of trans-‐cinnamic acid 2. To investigate stereochemistry of bromination reaction Introduction Alkenes undergo electrophilic addition to give alkyl halides. When bromine is used as a
Premium Bromine Acid Sodium
The percent yield of meso-1‚2-dibromo-1‚2-diphenylethane was calculated to be 66.36% and with a melting point of 235.1°C. Therefore‚ it can be concluded that this experiment was successfully conducted as the percent yield obtained is only 33.64% off from the equilibrium point‚ and because the melting point met the literature value. The percent yield for the product was less than 100%‚ indicating that were experimental errors‚ such as an undesirable side reaction‚ or more likely‚ an incomplete reaction
Premium Chemical reaction Chemistry Melting point
phenol soln in test tube + 1 drop FeCl3 soln Aliphatic and Aromatic Hydrocarbons/ Alkenes Bromination in Light (Free Radical Bromination) (Reacts with alkanes) Reagent: Br2 in H2O Observation: decolorization‚ brown ( colorless Procedure: 2 drops of test compound in test tube+ 1 drop 0.05 M Br2 in H2O‚ shake well‚ record observations Bromination in Dark (Electrophilic Addition Halogenation) (Reacts with alkenes) Reagent: Br2 in H2O Observation: decolorization‚ brown ( colorless Procedure:
Premium Carboxylic acid Alcohol Amine
form‚ write the structure of any meso compounds below. If none would form‚ write the word “NONE” below. [pic] 3. (25 points) The following reaction produces a major alkene product. First‚ on the Newman template provided draw the conformation from which the raction will occur. Then‚ on the product alkene template provided‚ draw the product that will form from this reaction. Finally‚ indicate the stereochemical designation of the major product.
Premium
chemistry experiment involved carrying out the first three parts of the Cyclohexanol Cycle. The cyclohexanol was first converted to cyclohexene and water by simple distillation (product: 6.5395g‚ 79.75% recovery). The cyclohexene then underwent a bromination reaction by addition of concentrated HBr and a 30% H2O2 solution‚ followed by an extraction of the aqueous phase. This produced trans-1‚2-dibromocyclohexane (product: 12.8886g‚ 67.34% recovery). The trans-1‚2-dibromocyclohexane was reduced by zinc
Premium Chemistry
atoms and label each chiral carbon as (R) or (S). 7. Give the stereochemical relationships (same compound‚ structural isomers‚ distereomers‚ or enantiomers) between each pair of isomers. 8. Consider the following free radical bromination of an enantiomerically pure alkane. Is the product formed as a single enantiomer or a racemic mixture? Is the product optically active or optically inactive? Explain your answers. Substitution and elimination reactions (Chpt 11): 9.
Premium
g/mol bp 60 °C mp 133-134 °C mp 93-95 °C mp 202-204 °C When an electrophile‚ such as bromine‚ adds to an alkene‚ the addition can be done in a syn fashion‚ in which the two groups add to the same side of the molecule‚ or in an anti fashion‚ in which the groups add to opposite sides of the molecule. Depending on the mode of addition‚ syn or anti‚ and the stereochemistry of the starting alkene‚ various stereoisomers will result. In some cases‚ a racemic mixture of products is formed‚ other times
Premium Chemistry Chemical reaction
S-20 Week 1 Alkenes: Isomers and Nomenclature 1. There are 6 unique alkene isomers of the hydrocarbon C5H10. Draw each of these isomers‚ and provide a systematic name for each. 1-pentene (E)-2-pentene (Z)-2-pentene 2-methyl-1-butene 2-methyl-2-butene 3-methyl-1-butene 2. For the three alkenes above which are various isomers of pentene‚ rank them in order of stability. Explain your ranking. most stable (more subst. double bond) less stable (cis alkene is slightly less
Premium Electron Aromaticity Electron configuration
1‚6-Heptadiyne Common names: prefix the substituents on the triple bond to the name “acetylene” IUPAC name: Common name: 2-Butyne D imethylacetylene 1-Buten-3-yne Vinylacetylene Physical Properties Similar to alkanes and alkenes of comparable molecular weight and carbon skeleton 2-Butyne 1-Pentyne Melting Point Formula (°C) -81 HC CH CH3 C CH -102 CH 3 CH2 C CH -126 -32 CH3 C CCH3 CH 3 ( CH2 ) 2 C CH -90 1-Hexyne CH 3 ( CH2 ) 3 C CH 1-Octyne
Premium Alkene Functional groups