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    chem answers

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    b 19.8 − 3.9 100 = 80% × 19.8 1 7.4 − 1.9 100 K9 Budget % water = = 74% × 7.4 1 15.0 − 3.8 100 Fresh meat – buffalo mince % water = = 75% × 15.0 1 Water would not be a good guide to the nutritional value of the dog food. The amount of protein‚ carbohydrates‚ fats‚ vitamins and minerals need to be

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    i dont know

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    denotes a specific amount 2. Avogadro created this unit 3. He used 12 grams of carbon to figure out his unit‚ weighed out 12 grams and did multiple test calculations 4. Abbreviation for the mole is mol 5. Avogadro’s number is 6.022 x 10^23 6. 1 mole= 6.022 x 10^23 7. Avogadro used the number to create molar mass 8. Molar mass is the weight of an atom in 1 mol‚ g/mol is the unit 9. MM is the abbreviation for molar mass 10. A mole is defined as the quantity of a substance that has the same

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    Problem How can the understanding of colligative properties be applied to making ice cream? Hypothesis Adding salt to the water lowers its freezing point (freezing point depression‚ which is a colligative property). The water will now stay liquid at lower temperatures‚ which is required to make ice cream. Procedures 1. Get all the materials : - 1/2 cup milk - 1-quart plastic bag - 1/2 cup heavy cream - 1-gallon plastic bag -

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    numericals on mole concept

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    1 mole of any substance can be defined as: Amount of a substance that contains as many particles (atoms‚ molecules or ions) as there are atoms in 12 g of the 12C isotope Avogadro number or Avogadro constant (NA); equal to 6.022 × 1023 particles Example − 1 mole of oxygen atoms = 6.022 × 1023 atoms 1 mole of carbon dioxide molecules = 6.022 × 1023 molecules 1 mole of sodium chloride = 6.022 × 1023 formula units of sodium chloride Molar mass of a substance can be defined as: Mass of one mole

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    2/11/2009 Purpose The purpose of this experiment is to determine the Molar Mass of an unknown substance using its freezing point depression. Introduction There are two types of mixtures; homogenous and heterogeneous. Homogenous mixtures have components that are uniformly mixed‚ while heterogeneous mixtures do not. A solution is a homogenous mixture that has two or more substances. A solution is mainly made of a solvent‚ while the solute is the smaller part of the solution. A solution’s

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    Stoichiometry-problems

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    solve some stoichiometric problems in chemistry. Almost all stoichiometric problems can be solved in just four simple steps: 1.Balance the equation. 2.Convert units of a given substance to moles. 3.Using the mole ratio‚ calculate the moles of substance yielded by the reaction. 4.Convert moles of wanted substance to desired units. These "simple" steps probably look complicated at first glance‚ but relax‚ they will all become clear. Let’s begin our tour of stoichiometry by

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    Arra

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    1856) was an Italian scientist. He is most noted for his contributions to molecular theory‚ including what is known as Avogadro’s law. In tribute to him‚ the number of elementary entities (atoms‚ molecules‚ ions or other particles) in 1 mole of a substance‚ 6.02214179(30)×1023‚ is known as the Avogadro constant. Avogadro’s Law Avogadro’s law states that equal volumes of gases‚ at the same temperature and pressure‚ contain the same number of molecules. Avogadro’s hypothesis wasn’t generally accepted

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    Experiment 3: Cryoscopic Determination of Molecular Weight Aim: The primary objective of the experiment is to calculate the total molecular mass of the compound benzoic acid in a predetermined amount of cyclohexane. Introduction: One of the key concepts in this experiment is the term freezing point depression. The definition of this phrase is that when a solute is dissolved into a solvent‚ their collective boiling point will be less than that of the original boiling point of the solvent. This incidentally

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    9702 S06 Qp 2

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    w w Name ap eP m e tr .X Candidate Number w Centre Number om .c s er UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Advanced Subsidiary Level and Advanced Level 9702/02 PHYSICS Paper 2 May/June 2006 1 hour Candidates answer on the Question Paper. No Additional Materials are required. READ THESE INSTRUCTIONS FIRST Write your Centre number‚ candidate number and name on all the work you hand in. Write in dark blue or black pen in the spaces provided

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    CHEM 1411 – General Chemistry I Practice Problems‚ Chapters 1–3 Chapter 1 – Chemistry: The Study of Change 1. Element‚ compound‚ homogeneous mixture (solution)‚ or heterogeneous mixture: a) orange juice b) brass c) 0.9% saline (NaCl) solution d) garden soil e) room air f) methane gas g) sodium metal h) N2 gas i) Cu(NO3)2 crystals (freshly-squeezed) 2. Define (some of these terms are found in Chapters 2 and 3): a) c) e) g) i) k) m) o) 3. b) d) f) h) j) l) n) compound physical change

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